java 是否支持在 xslt 中使用 EXSLT custom fuction

在使用java做一个xslt的过程中遇到xsl文件中存在是使用custom fuction的情况，我仍然采用javax.xml.transform.Transformer和javax.xml.transform.TransformerFactory进行处理，但是报出了以下错误：

ERROR: '非 static Java 函数 'listFind' 的第一个参数不是有效的对象引用。'
FATAL ERROR: '无法将数据类型 'void' 转换为 'boolean'。'
:无法将数据类型 'void' 转换为 'boolean'。

望各位大神给予大力技术支持，急，谢谢！

下面是例子的相关数据：

xsl文件代码

<?xml version="1.0" encoding="ISO-8859-1"?>



	<xsl:transform

		version="1.0"

		xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

		xmlns:ben="http://www.bennadel.com/xslt"

		xmlns:func="http://exslt.org/functions"

		xmlns:str="http://exslt.org/strings"

		extension-element-prefixes="func str ben">



		<func:function

			name="ben:list-find"

			ben:return-type="boolean"

			ben:hint="I take a delimited list and a value and return true or false as to whether that value is a list item in the given list.">



			<!-- Define arguments. -->

			<xsl:param

				name="list"

				ben:type="string"

				ben:required="true"

				ben:hint="I am the delimited list of values that is being searched."

				/>



			<xsl:param

				name="value"

				ben:type="string"

				ben:required="true"

				ben:hint="I am the value for which we are searching in the above list."

				/>



			<xsl:param

				name="delimiters"

				select="','"

				ben:type="string"

				ben:required="false"

				ben:hint="I am the collection of delimiters used to deliniate the list values. I can be one or more characters (each character is used as a valid delimiter). I am defaulted to the comma."

				/>



			<xsl:variable

				name="tokens"

				select="str:tokenize( $list, $delimiters )"

				/>





		</func:function>





		<!-- Match the root girls node. -->

		<xsl:template match="/girls">



			<girls>



				<xsl:copy-of

					select="./girl[ ben:list-find( 'athletic,hot', @type ) ]"

					/>



			</girls>



		</xsl:template>



	</xsl:transform>

xml文件代码：

<?xml version="1.0"?>

<girls>

		<girl type="cute">

			<name>Sarah</name>

		</girl>

		<girl type="athletic">

			<name>Tricia</name>

		</girl>

		<girl type="hot">

			<name>Katie</name>

		</girl>

		<girl type="cute">

			<name>Libby</name>

		</girl>

	</girls>

java代码如下（参数xml_text为xml文本数据，参数xsl_stylesheet_path为xsl文件路径）：

static  Transformer m_transformer ;

    static  String      m_strLastXslPath = "" ;

    public static  String xsl_transform_with_stylesheet(String xml_text ,String xsl_stylesheet_path){

        String strRet = null ;

        try {

            //

            TransformerFactory  ddd = TransformerFactory.newInstance() ;

            if ( m_strLastXslPath != xsl_stylesheet_path ){ //xsl

                StreamSource    SourceXsl = new StreamSource(xsl_stylesheet_path) ;

                m_transformer = ddd.newTransformer (SourceXsl);

                

                m_strLastXslPath = xsl_stylesheet_path;

            }

            

            //xml

            ByteArrayInputStream bisXml = new ByteArrayInputStream(xml_text.getBytes());

            StreamSource    SourceXml = new StreamSource(bisXml) ;



            //html ouput

            ByteArrayOutputStream   bosHtml  =  new  ByteArrayOutputStream();

            Result                  ResultHtml = new StreamResult( bosHtml );



            //do it

            m_transformer.transform(SourceXml, ResultHtml);

            strRet = bosHtml.toString();

        }

        catch (TransformerConfigurationException e) {

            e.printStackTrace( );

        }

        catch (Exception e) {

            e.printStackTrace( );

        }

        return strRet ;

    }