java 是否支持在 xslt 中使用 EXSLT custom fuction

[keshuichonglx]

在使用java做一个xslt的过程中遇到xsl文件中存在是使用custom fuction的情况，我仍然采用javax.xml.transform.Transformer和javax.xml.transform.TransformerFactory进行处理，但是报出了以下错误：

ERROR: '非 static Java 函数 'listFind' 的第一个参数不是有效的对象引用。'
FATAL ERROR: '无法将数据类型 'void' 转换为 'boolean'。'
:无法将数据类型 'void' 转换为 'boolean'。

望各位大神给予大力技术支持，急，谢谢！

下面是例子的相关数据：

xsl文件代码

<?xml version="1.0" encoding="ISO-8859-1"?>

	<xsl:transform
		version="1.0"
		xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
		xmlns:ben="http://www.bennadel.com/xslt"
		xmlns:func="http://exslt.org/functions"
		xmlns:str="http://exslt.org/strings"
		extension-element-prefixes="func str ben">

		<func:function
			name="ben:list-find"
			ben:return-type="boolean"
			ben:hint="I take a delimited list and a value and return true or false as to whether that value is a list item in the given list.">

			<!-- Define arguments. -->
			<xsl:param
				name="list"
				ben:type="string"
				ben:required="true"
				ben:hint="I am the delimited list of values that is being searched."
				/>

			<xsl:param
				name="value"
				ben:type="string"
				ben:required="true"
				ben:hint="I am the value for which we are searching in the above list."
				/>

			<xsl:param
				name="delimiters"
				select="','"
				ben:type="string"
				ben:required="false"
				ben:hint="I am the collection of delimiters used to deliniate the list values. I can be one or more characters (each character is used as a valid delimiter). I am defaulted to the comma."
				/>

			<xsl:variable
				name="tokens"
				select="str:tokenize( $list, $delimiters )"
				/>


		</func:function>


		<!-- Match the root girls node. -->
		<xsl:template match="/girls">

			<girls>

				<xsl:copy-of
					select="./girl[ ben:list-find( 'athletic,hot', @type ) ]"
					/>

			</girls>

		</xsl:template>

	</xsl:transform>

xml文件代码：

<?xml version="1.0"?>
<girls>
		<girl type="cute">
			<name>Sarah</name>
		</girl>
		<girl type="athletic">
			<name>Tricia</name>
		</girl>
		<girl type="hot">
			<name>Katie</name>
		</girl>
		<girl type="cute">
			<name>Libby</name>
		</girl>
	</girls>

java代码如下（参数xml_text为xml文本数据，参数xsl_stylesheet_path为xsl文件路径）：

static  Transformer m_transformer ;
    static  String      m_strLastXslPath = "" ;
    public static  String xsl_transform_with_stylesheet(String xml_text ,String xsl_stylesheet_path){
        String strRet = null ;
        try {
            //
            TransformerFactory  ddd = TransformerFactory.newInstance() ;
            if ( m_strLastXslPath != xsl_stylesheet_path ){ //xsl
                StreamSource    SourceXsl = new StreamSource(xsl_stylesheet_path) ;
                m_transformer = ddd.newTransformer (SourceXsl);
                
                m_strLastXslPath = xsl_stylesheet_path;
            }
            
            //xml
            ByteArrayInputStream bisXml = new ByteArrayInputStream(xml_text.getBytes());
            StreamSource    SourceXml = new StreamSource(bisXml) ;

            //html ouput
            ByteArrayOutputStream   bosHtml  =  new  ByteArrayOutputStream();
            Result                  ResultHtml = new StreamResult( bosHtml );

            //do it
            m_transformer.transform(SourceXml, ResultHtml);
            strRet = bosHtml.toString();
        }
        catch (TransformerConfigurationException e) {
            e.printStackTrace( );
        }
        catch (Exception e) {
            e.printStackTrace( );
        }
        return strRet ;
    }