Spring MVC 如何跳转项目以外的地址？

[Summer_東]

@RequestMapping(produces = "select")
private String getPid(ProductCatalogEntity bean, Model model,HttpServletResponse response) {
boolean pid = productCatalogService.getPid(bean, model);
if(pid){
//return "Info.jsp";
// return new ModelAndView("redirect:/http://192.168.1.115:8090/jeeshop/product/10321.html");
return "redirect:/http://192.168.1.115:8090/jeeshop/product/10321.html"; 要跳转的地址

}
return null;
}
试了很多方法都没解决 跳转的总是当前项目下的地址，求大神解决 还需要带参数跳转

[迷林]

如果是在同一工程的项目 就不用那么麻烦，直接返回“10321.html“页面

[gukuitian]

试试 @RequestMapping(produces = "select") private void getPid(ProductCatalogEntity bean, Model model,HttpServletResponse response) { response.sendRedirect(url); }

[Inhibitory]

"redirect:/http://192.168.1.115:8090/jeeshop/product/10321.html" 多了一个 / 应该是： "redirect:http://192.168.1.115:8090/jeeshop/product/10321.html"

[陈舍鱼]

引用 3 楼 Inhibitory 的回复:

"redirect:/http://192.168.1.115:8090/jeeshop/product/10321.html" 多了一个 / 应该是： "redirect:http://192.168.1.115:8090/jeeshop/product/10321.html"

三楼高手