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分享Iterater的remove方法
public class EnumerationTester2 {
public static void main(String[] args) {
String [] num = {"one","two","three","four","five","six","seven","eight","nine","ten"};
Vector <String> aVector = new Vector<String>(java.util.Arrays.asList(num));
System.out.println("before Vector"+aVector);
// Enumeration<String> nums = aVector.elements();
Iterator<String> nums = aVector.iterator();
while(nums.hasNext()){
String aString = nums.next();
System.out.println(aString);
if(aString.length()>4){
nums.remove();
}
}
System.out.println("after Vector"+aVector);
}}
最后程序的运行结果是：
before Vector[one, two, three, four, five, six, seven, eight, nine, ten]
one
two
three
four
five
six
seven
eight
nine
ten
after Vector[one, two, four, five, six, nine, ten]
问题是他究竟是怎样删除的，按我的理解不应该是5...10被删了吗？请大神做详细的解释？？！！
public static void main(String[] args) {
String [] num = {"one","two","three","four","five","six","seven","eight","nine","ten"};
Vector <String> aVector = new Vector<String>(java.util.Arrays.asList(num));
System.out.println("before Vector"+aVector);
// Enumeration<String> nums = aVector.elements();
Iterator<String> nums = aVector.iterator();
while(nums.hasNext()){
String aString = nums.next();
System.out.println(aString);
if(aString.length()>4){
nums.remove();
}
}
System.out.println("after Vector"+aVector);
}}
最后程序的运行结果是：
before Vector[one, two, three, four, five, six, seven, eight, nine, ten]
one
two
three
four
five
six
seven
eight
nine
ten
after Vector[one, two, four, five, six, nine, ten]
问题是他究竟是怎样删除的，按我的理解不应该是5...10被删了吗？请大神做详细的解释？？！！
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sinat_29738921 2015-08-11
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谢谢你了
nicholasbobo 2015-08-11
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是删除元素字符长度大于4的，不是删除元素下标大于4的
