字符串替换的问题(正则或者有其他更好的解决办法)

[csdnFUCKINGSUCKS]

json字符串如下 是从 mongodb中获取的document

{
  "_id" : ObjectId("55beda39f495cc8c6da3d21c"),
  "dictionary_name" : "(location_dic)",
}

现要实现如下的效果
将ObjectId中的值取出,替换原来完整的ObjectId()这样的格式,因为有括号的关系,所以不能
影响到其他的字段.

{
  "_id" : "55beda39f495cc8c6da3d21c",
  "dictionary_name" : "(location_dic)",
}

数据不止一条.实际格式是这样

{"data":[{"_id" : ObjectId("55beda39f495cc8c6da3d21c"),"dictionary_name" : "(location_dic)",},{"_id" : ObjectId("55beda39f495cc8c6da3d21d"),"dictionary_name" : "(test_dic)",}]}

[娃都会打酱油了]

string json=@"{""data"":[{""_id"" : ObjectId(""55beda39f495cc8c6da3d21c""),""dictionary_name"" : ""(location_dic)"",},{""_id"" : ObjectId(""55beda39f495cc8c6da3d21d""),""dictionary_name"" : ""(test_dic)"",}]}"  ;
string patten=@"\bObjectId\b\(""([^""]*)""\)";
Console.WriteLine(Regex.Replace(json, patten, m =>
{
    return m.Groups[1].Value;
}));

[娃都会打酱油了]

string json=@"{""data"":[{""_id"" : ObjectId(""55beda39f495cc8c6da3d21c""),""dictionary_name"" : ""(location_dic)"",},{""_id"" : ObjectId(""55beda39f495cc8c6da3d21d""),""dictionary_name"" : ""(test_dic)"",}]}"  ;
string patten=@"\bObjectId\b\((""[^""]*"")\)";
Console.WriteLine(Regex.Replace(json, patten, "$1"));

写傻掉了，这个结果是你要的，上面把双引号弄掉了

[csdnFUCKINGSUCKS]

引用 2 楼 starfd 的回复:

string json=@"{""data"":[{""_id"" : ObjectId(""55beda39f495cc8c6da3d21c""),""dictionary_name"" : ""(location_dic)"",},{""_id"" : ObjectId(""55beda39f495cc8c6da3d21d""),""dictionary_name"" : ""(test_dic)"",}]}"  ;
string patten=@"\bObjectId\b\((""[^""]*"")\)";
Console.WriteLine(Regex.Replace(json, patten, "$1"));

写傻掉了，这个结果是你要的，上面把双引号弄掉了

大神厉害 结贴了