请教Shell下的一个函数问题

[Sanm_Lee]

Shell脚本如下：#!/bin/bash
count()
{

if [ $# -ne 3 ]

then

echo "The number of arguments is not 3!"
fi



let "s = 0"

case $2 in

+)

let "s = $1 + $3"

echo "$1 + $3 = $s";;

-)

let "s = $1 - $3"

echo "$1 - $3 = $s";;

\*)

let "s = $1 * $3"

echo "$1 * $3 = $s";;

\/)

let "s = $1 / $3"

echo "$1 / $3 = $s";;

*)

echo "What you input is wrong!";;

esac
}

echo "Please type you word:(e.g. 1 + 1)"
read a b c
count $a $b $c


脚本测试如下：

1.测试加法

[root@localhost 13study]# sh function5.sh

Please type you word:(e.g. 1 + 1)

3 + 3

3 + 3 = 6

2.测试减法

[root@localhost 13study]# sh function5.sh

Please type you word:(e.g. 1 + 1)

3 - 3

3 - 3 = 0

3.测试乘法

[root@localhost 13study]# sh function5.sh

Please type you word:(e.g. 1 + 1)

3 * 3

The number of arguments is not 3!

What you input is wrong!

4.测试除法

[root@localhost 13study]# sh function5.sh

Please type you word:(e.g. 1 + 1)

3 / 3

3 / 3 = 1
为什么乘法测试结果不对，问题出在哪里？是因为“*”星号符么，要如何操作才正确。请高手指点下。谢谢，谢谢

[我用双手-成就你的梦想]

调用count前把 a b c都echo看看

[nswcfd]

a="*" echo $a <----- 显示当前目录的所有文件名 echo "$a" <----- 显示*字符 调用count的时候，三个参数分别用引号括起来。

[qq_29937191]

来看看，学习下