package com.struts2.action;这只是一个简单的登录的action
import com.opensymphony.xwork2.Action;
public class LoginAction implements Action {
private String username;
private String password;
private String result;
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
@Override
public String execute() throws Exception {
return null;
}
public String login(){
if(username.equals(password)){
return SUCCESS;
}else{
return ERROR;
}
}
public String logout(){
result="重新登录";
return SUCCESS;
}
public String getResult() {
return result;
}
public void setResult(String result) {
this.result = result;
}
}
<struts>这是struts文件
<package name="HelloWorld" extends="struts-default">
<action name="HelloWorld" class="com.struts2.action.HelloWorld">
<result name="success">/HelloWorld.jsp</result>
</action>
<action name="login" class="com.struts2.action.LoginAction" method="login">
<result name="succsess">/Success.jsp</result>
<result name="error">/Error.jsp</result>
</action>
</package>
</struts>
文件结构
登录失败的jsp
与登录成功的jsp
我只想问问，struts.xml配置都类似的，action也是 为什么 不能显示 成功页面呢？
