Java开发过程中的解压问题
IT老狼 2015-09-08 06:46:21 import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.nio.charset.Charset;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
import java.util.zip.ZipInputStream;
public class ZipInputStreamTest {
public static void main(String args[]) throws IOException {
File file = new File("E:\\ott\\www.wandoujia.com\\二维码扫描.apk");//压缩文件
// ZipFile zipFile = new ZipFile(file);
ZipFile zipFile = new ZipFile(file, Charset.forName("gbk"));//实例化ZipFile,并指定其编码格式,防止中文乱码和解压错误,每一个zip压缩文件都可以表示为一个ZipFile
//实例化一个Zip压缩文件的ZipInputStream对象,可以利用该类的getNextEntry()方法依次拿到每一个ZipEntry对象
// ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream(file), Charset.forName("GBK"));
ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream(file), Charset.forName("GBK"));
//直接利用ZipFile进行解压
unpack(zipFile);
//利用ZipFile和ZipInputStream进行解压
unpack(zipFile, zipInputStream);
}
/**
* 该方法是通过ZipFile和ZipInputStream共同来解压文件的,通过ZipInputStream可以拿到ZipFile中的每一个
* ZipEntry对象,然后通过ZipFile的getInputStream(ZipEntry zipEntry)方法拿到对应的每一个ZipEntry的
* 输入流,从而实现文件的解压
* @param zipFile
* @param zipInputStream
* @throws IOException
*/
public static void unpack(ZipFile zipFile, ZipInputStream zipInputStream) throws IOException {
ZipEntry zipEntry = null;
while ((zipEntry = zipInputStream.getNextEntry()) != null) {
String fileName = zipEntry.getName();
File temp = new File("E:\\ott\\www.wandoujia.com\\" + fileName);
if (! temp.getParentFile().exists())
temp.getParentFile().mkdirs();
OutputStream os = new FileOutputStream(temp);
//通过ZipFile的getInputStream方法拿到具体的ZipEntry的输入流
InputStream is = zipFile.getInputStream(zipEntry);
int len = 0;
System.out.println(zipEntry.getName());
while ((len = is.read()) != -1)
os.write(len);
os.close();
is.close();
}
zipInputStream.close();
}
/**
* 该方法是直接通过ZipFile的entries()方法拿到包含所有的ZipEntry对象的Enumeration对象,
* 接下来的操作和上面的是一样的
* @param zipFile
* @throws IOException
*/
public static void unpack(ZipFile zipFile) throws IOException {
Enumeration<ZipEntry> entries = (Enumeration<ZipEntry>) zipFile.entries();
while (entries.hasMoreElements()) {
ZipEntry zipEntry = entries.nextElement();
String fileName = zipEntry.getName();
File temp = new File("E:\\ott\\www.wandoujia.com\\" + fileName);
if (! temp.getParentFile().exists())
temp.getParentFile().mkdirs();
OutputStream os = new FileOutputStream(temp);
//通过ZipFile的getInputStream方法拿到具体的ZipEntry的输入流
InputStream is = zipFile.getInputStream(zipEntry);
System.out.println("555555555555555555555");
int len = 0;
while ((len = is.read()) != -1)
os.write(len);
os.close();
is.close();
}
}
}
我按网上的解压完全一样,就是红字哪里会提示构造函数不对