asp.net后台拼接，前端解析不了json的问题

[小孩快跑]

后台代码：rjson.AppendFormat("{{\"Pid\":\"{0}\",",Pid);
rjson.AppendFormat("\"TagName\":[{0}],\"IsSMSValid\":\"{1}\",\"Count\":\"{2}\",\"IsEmailValid\":\"{3}\",\"IsIDNumber\":\"{4}\",",TagName, IsSMSValid, Count, IsEmailValid, IsIDNumber);
rjson.AppendFormat("\"SubmitBeginDate\":\"{0}\",",SubmitBeginDate);
rjson.AppendFormat("\"RemainTime\":\"{0}\",\"RewardMoney\":\"{1}\",\"UpperMoney\":\"{2}\",\"LowerMoney\":\"{3}\",\"SubmitNum\":\"{4}\",\"PName\":\"{5}\"}},", RemainTime, RewardMoney, UpperMoney, LowerMoney, SubmitNum, PName);


前台代码是：
{"success": [{"msg": [{"Pid":"1000","TagName":[{"CTagName":"建筑","TagCount": "1"},{"CTagName":"还不错啊","TagCount"
: "1"},{"CTagName":"Coreldraw","TagCount": "1"}],"IsSMSValid":"1","Count":"3","IsEmailValid":"0","IsIDNumber"
:"0","SubmitBeginDate":"2015-09-02","RemainTime":"已过期","RewardMoney":"0","UpperMoney":"86547.00","LowerMoney"
:"30000.00","SubmitNum":"0","PName":"开发APP项目"},{"Pid":"1011","TagName":[{"CTagName":"Coreldraw","TagCount"
: "1"},{"CTagName":"还不错啊","TagCount": "1"},{"CTagName":"Coreldraw","TagCount": "1"},{"CTagName":"建筑"
,"TagCount": "1"}],"IsSMSValid":"1","Count":"3","IsEmailValid":"0","IsIDNumber":"0","SubmitBeginDate"
:"2015-09-14","RemainTime":"19天23时","RewardMoney":"0","UpperMoney":"40000.00","LowerMoney":"30000.00"
,"SubmitNum":"0","PName":"ss"},{"Pid":"1008","TagName":[{"CTagName":"","TagCount": "0"}],"IsSMSValid"
:"1","Count":"3","IsEmailValid":"0","IsIDNumber":"0","SubmitBeginDate":"2015-09-14","RemainTime":"29
天23时","RewardMoney":"0","UpperMoney":"63113.00","LowerMoney":"35283.00","SubmitNum":"0","PName":"11"
}]}],"error": [{"msg": ""}],"totalpage":"2","totalcount":"3","curPageIndex":"0"}

但是解析不了，前台自动换行了，请问怎么让它不自动换行，怎么才可以解析

[老李家的小二]

能不用拼接的方法吗 另外，在线验证可用通过吗

[老李家的小二]

Newtonsoft用这个试试

[娃都会打酱油了]

你的json不是标准json呗，有控件不用，非要用拼接方式，何苦呢

[不断学习的ITer]

用 jquery parseJson 方法转化下。 或者 var a=eval('('+json+')'); 解析a

[紫魂一号]

格式不对，要加 [ ]

[紫魂一号]

建议你去下一个解析json的工具，看看你写的json是否能解析出来

[cocosip]

Newtonsoft 不是很强大么，还需要你自己去拼接？后台拼成一个dynamic类型，用Newtonsoft直接转成json，都不需要定义新的实体类。

[xboxeer]

后台拼JSON已经是很古老的事情了。。。。

[小鬼当家家]

对于换行的问题，直接将你返回的字符串转义一下就可以了。比如你返回的字符串是returnString.最后转义一下 returnString=returnString.replace("\r\n","\\r\\n").

[桃红沟]

还是别用拼接了，这个容易出错，用Newtonsoft.Json很方便，他的JsonConvert.SerializeObject(obj）方法，直接将obj对象序列化位json字符串，在前天用eval（）方法解析就行 这是我上传的Newtonsoft.Json.dll的地址，http://yunpan.cn/cHVgSVNfp5ep6 （提取码：6a88），你可以试试