分类取各地区销售额占比80%的品种（28法则）

[o_range]

用户要求如题，如果取所有记录里面销售额占比前80%的品种，我网上找到了解决方案，如下：
但是分组取的话就没辙了，求各位大神指点迷津~

	
declare @e_rq varchar(15),@orgid int;
	select @e_rq='2015-07-31',@orgid=308;
	
	select spbh,SUM(hsje) as hsje,ROW_NUMBER() over(order by sum(hsje) desc) as rowid 
	into #tb
	from tb_asyy_zhfx_ygdc 
	where  convert(varchar(7),execdate,120)= convert(varchar(7),@e_rq,120)  and orgid=@orgid
	group by spbh
	-------------------取销售额80%的品种编号-------------------------
	select spbh,hsje		
	into #A_spbh 
	from #tb  a
	where (select SUM(hsje) from #tb where rowid<=a.rowid)/(select SUM(hsje) from tb_asyy_zhfx_ygdc where convert(varchar(7),execdate,120)= convert(varchar(7),@e_rq,120)   and orgid=@orgid)*100<80

tb_asyy_zhfx_ygdc ：spbh 商品编号 hsje 销售额 dqfl 大区分类

[Tiger_Zhao]

declare @e_rq varchar(15),@orgid int;
select @e_rq='2015-07-31',@orgid=308;

-- 求出各组总计
    SELECT dqfl,
           SUM(hsje) as hsje
      into #ta
      from tb_asyy_zhfx_ygdc 
     where convert(varchar(7),execdate,120)= convert(varchar(7),@e_rq,120)
       and orgid=@orgid
  group by dqfl

-- 求各组下面的商品统计
    SELECT dqfl,
           spbh,
           SUM(hsje) as hsje,
           ROW_NUMBER() over(PARTITION BY dqfl order by sum(hsje) desc) as rowid 
      into #tb
      from tb_asyy_zhfx_ygdc 
     where convert(varchar(7),execdate,120)= convert(varchar(7),@e_rq,120)
       and orgid=@orgid
  group by dqfl, spbh

-- 每组的前80%
    select b.dqfl,
           b.spbh,
           b.hsje		
      into #A_spbh 
      from #tb b
      JOIN #ta a
        ON a.dqfl = b.dqfl
     where (select SUM(b1.hsje)
              from #tb b1
             where b1.dqfl = b.dqfl
               AND b1.rowid <= b.rowid
           ) / a.hsje * 100 < 80
  ORDER BY b.dqfl, b.rowid