ajax接受json问题

[zhangsheng_1992]

js代码

 $.ajax({
            url:url,
            type: "POST",
            dataType: "json",
            data: {"id": id},
            success: function(jsonObj){
            
        }
        });

返回的json串为

{
    "code": 1,
    "message": {
        "id": 100,
        "health_id": "",
        "name": "轮毂清洗养护",
        "price": "",
        "workhour": "",
        "parent_id": 10,
        "sorts": "1-10-100",
        "factory_id": 0,
        "type": 2,
        "is_del": 0
    }
}

我该如何把里面的code
和message里面的值遍历出来

[slwsss]

alert(jsonObj.code); alert(jsonObj.message.name)

[zhongyuan332]

 $.ajax({
            url:url,
            type: "POST",
            dataType: "json",
            data: {"id": id},
            success: function(jsonObj){
                alert(jsonObj.code);
                alert(jsonObj.message.id);
        }
        });

[zhongyuan332]

你console.log(jsonObj);试一下 要是object对象的话就得用[0]来取

[Lucky丶钉钉]

 BufferedReader br = new BufferedReader(new InputStreamReader(request.getInputStream()));
        String line = null;
        StringBuilder sb = new StringBuilder();
        while ((line = br.readLine()) != null) {
          sb.append(line);
        }
        reqBody = URLDecoder.decode(sb.toString(), "UTF-8");
        String inputDataFormat = getInputDataFormat();
        JSONObject json;
        if (inputDataFormat.equals("json")) {
          new JSONObject(); json = JSONObject.parseObject(reqBody);
          for (String key : map.keySet()) {
            if (StringUtils.isEmpty(json.getString(key))) {
              continue;
            }
            map.put(key, json.getString(key));
          }

你看看这个能不能用，也是接收json格式数据，后台做处理的