编一个程序，从三个红球，五个白球，六个黑球中任意取出八个球，且其中必须有白球，输出所有可能的方案

2015-11-19 05:43:40 7.5k 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

2572: 红球还是黑球 python 2572: 红球还是黑球：一个盒子中有n个红球和m个黑球，n+m>=1，现在规定随机拿出两个球（拿出后不放回盒子中），如果是一红一黑，则向盒子中放入一个黑球；其他情况向盒子中放入一个红球。求当盒子中只剩一个球时，是红球的概率。输入：有多组测试数据，每组输入两个数，n,m（0<=n<=100,0<=m<=100,1<=n+m）输出：输出包含一行是红球的概率，保留6位小数。 python代码：提示：在红n黑m的情况下，每次最多有三种情况发生：刚好拿到两个阅读详情

刚接触c# 求教下面问题如何编程
编一个程序，从三个红球，五个白球，六个黑球中任意取出八个球，且其中必须有白球，输出所有可能的方案。

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Benny_ 2015-11-27

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static void Main(string[] args)
        {
            int red = 3;
            int write = 5;
            int black = 6;

            for (int i = 1; i <= write; i++)
            {
                for (int j = 0; j <= red; j++)
                {
                    black = 8 - i - j;
                    if (black != 7)//黑球数只有6个
                    {
                        Console.WriteLine("write:{0}" + " red:{1}" + " black:{2}", i, j, black);
                    }

                }
            }
            Console.ReadKey();

        }

write:1 red:1 black:6
write:1 red:2 black:5
write:1 red:3 black:4
write:2 red:0 black:6
write:2 red:1 black:5
write:2 red:2 black:4
write:2 red:3 black:3
write:3 red:0 black:5
write:3 red:1 black:4
write:3 red:2 black:3
write:3 red:3 black:2
write:4 red:0 black:4
write:4 red:1 black:3
write:4 red:2 black:2
write:4 red:3 black:1
write:5 red:0 black:3
write:5 red:1 black:2
write:5 red:2 black:1
write:5 red:3 black:0

caojinrong 2015-11-22

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不好意思，算法有误，

                if (arry[i - 1] < arry[i])
                {
                    int tmp = arry[i - 1];
                    arry[i - 1] = arry[i];
                    arry[i] = tmp;
                    return true;
                }

此处应该把i后面比第i个元素大的最小值和第i元素互换，然后将i+1之后的元素按小至大排列，要是纠结结果的话可以自选修改。

qq_32529103 2015-11-20

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谢谢各位，已经懂了。

秋的红果实 2015-11-20

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只要各个球没有编号就好，白球一定是{1,2,3,4,5}，剩下考虑红黑的

crystal_lz 2015-11-20

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引用 9 楼 caojinrong 的回复:

19种组合、352种排列

        //编一个程序，从三个红球，五个白球，六个黑球中任意取出八个球，且其中必须有白球，输出所有可能的方案。
        static void Main()
        {
            int gIndex = 0, aIndex = 0;
            ConsoleColor[] colors = new ConsoleColor[] { ConsoleColor.White, ConsoleColor.Red, ConsoleColor.DarkGray };
            for (int white = 1; white <= 5; white++)
            {
                for (int red = 0; red <= 3; red++)
                {
                    int black = 8 - white - red;
                    if (black < 0 || black > 6) continue;    //白+红不足2个，抛弃

                    gIndex++;
                    //分别用0、1、2表示白球、红球、黑球
                    int[] arry = new int[8];
                    for (int i = 0; i < white; i++)
                        arry[i] = 0;
                    for (int i = 0; i < red; i++)
                        arry[i + white] = 1;
                    for (int i = 0; i < black; i++)
                        arry[7 - i] = 2;

                    do
                    {
                        aIndex++;
                        Console.Write("{0:00}:{1:000}:", gIndex, aIndex);
                        for (int i = 0; i < arry.Length; i++)
                        {
                            Console.ForegroundColor = colors[arry[i]];
                            Console.Write("●");
                        }
                        Console.WriteLine();
                        Console.ResetColor();
                    } while (Range(arry));
                }
            }
            Console.ReadKey();
        }

        private static bool Range(int[] arry)
        {
            for (int i = arry.Length - 1; i > 0; i--)
            {
                if (arry[i - 1] < arry[i])
                {
                    int tmp = arry[i - 1];
                    arry[i - 1] = arry[i];
                    arry[i] = tmp;
                    return true;
                }
            }
            return false;
        }

一共有20种排列组合有多少种我是不知道不过看你的打印来看下面几个应该就是三个红球的组合排法了可是我随便想了一种组合为什么没有看到？红红白白白白..红????

caojinrong 2015-11-20

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19种组合、352种排列

        //编一个程序，从三个红球，五个白球，六个黑球中任意取出八个球，且其中必须有白球，输出所有可能的方案。

        static void Main()

        {

            int gIndex = 0, aIndex = 0;

            ConsoleColor[] colors = new ConsoleColor[] { ConsoleColor.White, ConsoleColor.Red, ConsoleColor.DarkGray };

            for (int white = 1; white <= 5; white++)

            {

                for (int red = 0; red <= 3; red++)

                {

                    int black = 8 - white - red;

                    if (black < 0 || black > 6) continue;    //白+红不足2个，抛弃



                    gIndex++;

                    //分别用0、1、2表示白球、红球、黑球

                    int[] arry = new int[8];

                    for (int i = 0; i < white; i++)

                        arry[i] = 0;

                    for (int i = 0; i < red; i++)

                        arry[i + white] = 1;

                    for (int i = 0; i < black; i++)

                        arry[7 - i] = 2;



                    do

                    {

                        aIndex++;

                        Console.Write("{0:00}:{1:000}:", gIndex, aIndex);

                        for (int i = 0; i < arry.Length; i++)

                        {

                            Console.ForegroundColor = colors[arry[i]];

                            Console.Write("●");

                        }

                        Console.WriteLine();

                        Console.ResetColor();

                    } while (Range(arry));

                }

            }

            Console.ReadKey();

        }



        private static bool Range(int[] arry)

        {

            for (int i = arry.Length - 1; i > 0; i--)

            {

                if (arry[i - 1] < arry[i])

                {

                    int tmp = arry[i - 1];

                    arry[i - 1] = arry[i];

                    arry[i] = tmp;

                    return true;

                }

            }

            return false;

        }

TimLee✿ 2015-11-19

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引用 5 楼 crystal_lz 的回复:

[quote=引用 3 楼 hjq624779687 的回复:] [quote=引用 2 楼 crystal_lz 的回复:]


//白球可以是 1 - 5 个
for(int write = 1;write <= 5;write++){
    //红球可以是 0 - 3 个
    for(int red = 0;red <= 3;red++){
        //剩下的就是黑球
        Console.WriteLine(
            "write:" + write + 
            " red:" + red + 
            " black:" + (8 - write - red));
    }
}

write:1 red:0 black:7
write:1 red:1 black:6
write:1 red:2 black:5
write:1 red:3 black:4
write:2 red:0 black:6
write:2 red:1 black:5
write:2 red:2 black:4
write:2 red:3 black:3
write:3 red:0 black:5
write:3 red:1 black:4
write:3 red:2 black:3
write:3 red:3 black:2
write:4 red:0 black:4
write:4 red:1 black:3
write:4 red:2 black:2
write:4 red:3 black:1
write:5 red:0 black:3
write:5 red:1 black:2
write:5 red:2 black:1
write:5 red:3 black:0

....write....可能他还要求有排序什么的，想了有点久了。。。。[/quote] 求都是一样还有什么排序？难道还要排列组合不成。。。再拿出来的球上面还有什么排法不成？。。[/quote] 用C#还纠结排序? 数据防到list里面,然后Sort啊....

crystal_lz 2015-11-19

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引用 3 楼 hjq624779687 的回复:

[quote=引用 2 楼 crystal_lz 的回复:]


//白球可以是 1 - 5 个
for(int write = 1;write <= 5;write++){
    //红球可以是 0 - 3 个
    for(int red = 0;red <= 3;red++){
        //剩下的就是黑球
        Console.WriteLine(
            "write:" + write + 
            " red:" + red + 
            " black:" + (8 - write - red));
    }
}

write:1 red:0 black:7
write:1 red:1 black:6
write:1 red:2 black:5
write:1 red:3 black:4
write:2 red:0 black:6
write:2 red:1 black:5
write:2 red:2 black:4
write:2 red:3 black:3
write:3 red:0 black:5
write:3 red:1 black:4
write:3 red:2 black:3
write:3 red:3 black:2
write:4 red:0 black:4
write:4 red:1 black:3
write:4 red:2 black:2
write:4 red:3 black:1
write:5 red:0 black:3
write:5 red:1 black:2
write:5 red:2 black:1
write:5 red:3 black:0

....write....可能他还要求有排序什么的，想了有点久了。。。。[/quote] 求都是一样还有什么排序？难道还要排列组合不成。。。再拿出来的球上面还有什么排法不成？。。

crystal_lz 2015-11-19

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上面贴的只是数据碰巧不会出现什么特殊情况如果有什么特殊情况的用这个


int nCount = 8;//总共拿出个数
int nRedCount = 100;
int nWriteCount = 100;
int nBlackCount = 1;
for (int write = 1; write <= nWriteCount && write <= nCount; write++) {
    for (int red = 0; red <= nRedCount && (write + red) <= nCount; red++) {
        //黑球不够凑够8个的情况下的情况下
        if (nCount - write - red > nBlackCount) continue;
        Console.WriteLine(
            "write:" + write + 
            " red:" + red + 
            " black:" + (nCount - write - red));
    }
}

write:1 red:6 black:1
write:1 red:7 black:0
write:2 red:5 black:1
write:2 red:6 black:0
write:3 red:4 black:1
write:3 red:5 black:0
write:4 red:3 black:1
write:4 red:4 black:0
write:5 red:2 black:1
write:5 red:3 black:0
write:6 red:1 black:1
write:6 red:2 black:0
write:7 red:0 black:1
write:7 red:1 black:0
write:8 red:0 black:0

夏天的枫 2015-11-19

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引用 2 楼 crystal_lz 的回复:


//白球可以是 1 - 5 个
for(int write = 1;write <= 5;write++){
    //红球可以是 0 - 3 个
    for(int red = 0;red <= 3;red++){
        //剩下的就是黑球
        Console.WriteLine(
            "write:" + write + 
            " red:" + red + 
            " black:" + (8 - write - red));
    }
}

write:1 red:0 black:7
write:1 red:1 black:6
write:1 red:2 black:5
write:1 red:3 black:4
write:2 red:0 black:6
write:2 red:1 black:5
write:2 red:2 black:4
write:2 red:3 black:3
write:3 red:0 black:5
write:3 red:1 black:4
write:3 red:2 black:3
write:3 red:3 black:2
write:4 red:0 black:4
write:4 red:1 black:3
write:4 red:2 black:2
write:4 red:3 black:1
write:5 red:0 black:3
write:5 red:1 black:2
write:5 red:2 black:1
write:5 red:3 black:0

....write....可能他还要求有排序什么的，想了有点久了。。。。

crystal_lz 2015-11-19

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//白球可以是 1 - 5 个
for(int write = 1;write <= 5;write++){
    //红球可以是 0 - 3 个
    for(int red = 0;red <= 3;red++){
        //剩下的就是黑球
        Console.WriteLine(
            "write:" + write + 
            " red:" + red + 
            " black:" + (8 - write - red));
    }
}

write:1 red:0 black:7
write:1 red:1 black:6
write:1 red:2 black:5
write:1 red:3 black:4
write:2 red:0 black:6
write:2 red:1 black:5
write:2 red:2 black:4
write:2 red:3 black:3
write:3 red:0 black:5
write:3 red:1 black:4
write:3 red:2 black:3
write:3 red:3 black:2
write:4 red:0 black:4
write:4 red:1 black:3
write:4 red:2 black:2
write:4 red:3 black:1
write:5 red:0 black:3
write:5 red:1 black:2
write:5 red:2 black:1
write:5 red:3 black:0

为自己喝彩0415 2015-11-19

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两个For循环遍历即可？比如： for (int i = 1; i <= 5; i++) { for (int j = 1; j <= 3; j++) { if (i + j == 8) { Console.Writeline(“白球：i个；红球：j个”); } else { Console.Writeline("白球：i个；红球：j个；黑球：8-i-j个"); } } }

编一个程序，从三个红球，五个白球，六个黑球中任意取出八个球，且其中必须有白球，输出所有可能的方案

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