求助：error C2679: 二进制“=”: 没有找到接受“int *”类型的右操作数的运算符(或没有可接受的转换)

[囧囧骚年]

int main(int argc,char* argv[])
{
int a[] = { 10, 20, 30, 40, 50 };
vector<int> v1(a, a + 5);
v1[2] = 70;
if (equal(v1.begin(), v1.end(), a))
{
cout << "两个序列内容相等" << endl;
}
else
{
cout << "两个序列内容不相等" << endl;
}

pair<vector<int>::iterator, vector<int>::iterator> pair1;
pair1 = mismatch(v1.begin(), v1.end(), a);
cout << "v1(" << *(pair1.first);
cout << ") and v2(" << *(pair1.second) << ")" << endl;
return 0;



}
出现错误：error C2679: 二进制“=”: 没有找到接受“int *”类型的右操作数的运算符(或没有可接受的转换)




int main(int argc, char* argv[])
{
//int a[] = { 10, 20, 30, 40, 50 };
//vector<int> v1(a, a + 5);
//v1[2] = 70;
vector<int> v;
v.push_back(10);
v.push_back(20);
v.push_back(30);
v.push_back(40);
v.push_back(50);
vector<int> v1;
v1.push_back(10);
v1.push_back(20);
v1.push_back(70);
v1.push_back(40);
v1.push_back(50);

if (equal(v1.begin(), v1.end(), v.begin()))
{
cout << "两个序列内容相等" << endl;
}
else
{
cout << "两个序列内容不相等" << endl;
}

pair<vector<int>::iterator, vector<int>::iterator> pair1;
pair1 = mismatch(v1.begin(), v1.end(), v.begin());
cout << "v1(" << *(pair1.first);
cout << ") and v2(" << *(pair1.second) << ")" << endl;
return 0;



}

运行成功

为什么？

[pcboyxhy]

pair<vector<int>::iterator, int *> pair1;

[囧囧骚年]

引用 1楼pcboyxhy 的回复:

pair<vector<int>::iterator, int *> pair1;

谢谢啦，