字符串处理的问题

[xin_xiao]

有类似这样的字段串:

<p><img src="/ueditor/net/upload/image/20151120/6358363963167809393441278.jpg" title="20150909031003_59_MovieDetailSmall.jpg" alt="20150909031003_59_MovieDetailSmall.jpg"/></p>
<p><img src="/ueditor/net/upload/image/20151120/6358363963167809323232323.jpg" title="20150909031003_59_MovieDetailSmall.jpg" alt="20150909031003_59_MovieDetailSmall.jpg"/></p>
<p><img src="/ueditor/net/upload/image/20151120/6358363963167801111111112.jpg" title="20150909031003_59_MovieDetailSmall.jpg" alt="20150909031003_59_MovieDetailSmall.jpg"/></p>

问题:怎样找到所有的img的src属性,然后在src前面加上ip地址.

[BillHu233]

var imglist = document.getelementbytagname("img"); foreach(var img in imglist) { img.src="ip"+img.src; } 如果是jQuery就更简单了 var imglist = $("img"); foreach(var img in imglist) { var src = $(img).attr("src"); $(img).attr("src","ip"+src) }

[江南小鱼]

javascript、jquery都有这种功能，获取标签集合，然后遍历某个属性

[lovebaby]

服务器端实现

@{
            StringBuilder str = new StringBuilder("<p><img src=\"/ueditor/net/upload/image/20151120/6358363963167809393441278.jpg\" title=\"20150909031003_59_MovieDetailSmall.jpg\" alt=\"20150909031003_59_MovieDetailSmall.jpg\"/></p>");
            str.Append("<p><img src=\"/ueditor/net/upload/image/20151120/6358363963167809323232323.jpg\" title=\"20150909031003_59_MovieDetailSmall.jpg\" alt=\"20150909031003_59_MovieDetailSmall.jpg\"/></p>");
            str.Append("<p><img src=\"/ueditor/net/upload/image/20151120/6358363963167801111111112.jpg\" title=\"20150909031003_59_MovieDetailSmall.jpg\" alt=\"20150909031003_59_MovieDetailSmall.jpg\"/></p>");
            Regex re = new Regex(@"src="".+?""",RegexOptions.IgnoreCase);
            MatchCollection mc = re.Matches(str.ToString());
            foreach(var s in mc)
            {
                @:*.*.*.* @s<br />
            }
        }

[风2013]

$("img").each(function(){
   var src = $(this).attr(str);
   $(this).attr(src,ip+src);
})

[shugeer]

引用 5 楼 hanjun0612 的回复:

你给 img增加一个统一class属性。比如叫 class = 'myImg'

<script>
           var ip = "192.168.1.1";
           var q = $('.myImg').each(function () {
               $(this).attr('src', ip + $(this).attr('src'));
               alert($(this).attr('src'));
           });

       </script>

你不是多此一举吗？直接$("img") 多好

[正怒月神]

引用 7 楼 shugeer 的回复:

[quote=引用 5 楼 hanjun0612 的回复:] 你给 img增加一个统一class属性。比如叫 class = 'myImg'

<script>
           var ip = "192.168.1.1";
           var q = $('.myImg').each(function () {
               $(this).attr('src', ip + $(this).attr('src'));
               alert($(this).attr('src'));
           });

       </script>

你不是多此一举吗？直接$("img") 多好[/quote] 这是习惯问题，我不清楚他是否存在其他不需要修改的img标签。

[海棠是否依旧]

引用 6 楼 feng1366259807 的回复:

$("img").each(function(){
   var src = $(this).attr(str);
   $(this).attr(src,ip+src);
})

正解

[myhope88]

jquery遍历就搞定啦

[正怒月神]

你给 img增加一个统一class属性。比如叫 class = 'myImg'

<script>
           var ip = "192.168.1.1";
           var q = $('.myImg').each(function () {
               $(this).attr('src', ip + $(this).attr('src'));
               alert($(this).attr('src'));
           });

       </script>