一个关于switch的小语句问题....

[Me骜]

#include<stdio.h>
#include<ctype.h>
int main()
{
	int time = 0;
	int jotime;

	float money = 0;
	float basic;

	char select;
	for (int i = 0; i < 104; i++)
		printf("*");
	printf("\n");
	printf("Enter the number corresponding to .the desired pay rate or action：\n");
	printf("A) $8.75/hr						B) $9.33/hr\n");
	printf("C) $10.00/hr					D) $11.20/hr\n");
	printf("E) quit\n");
	while (scanf("%c", &select) == 1)
	{
		int cp = 0;
		select = toupper(select);
		switch (select)
		{
		case 'A':
			basic = 8.75;
			break;
		case 'B':
			basic = 9.33;
			break;
		case 'C':
			basic = 10.00;
			break;
		case 'D':
			basic = 11.20;
			break;
		case 'E':
			cp++;
			break;
		default:
			printf("请输入一个选择:\n");
			cp++;
		}
		if (cp = 1)
			continue;
		else
			break;
	}
	printf("您的选择是:%c\n", select);
}

这个代码有什么问题,,,为啥运行的时候无论输入什么都会显示请输入一个选择:

[Me骜]

if (cp = 1)写错了...应该是if (cp == 1),好低级的错误啊...