关于zeromq的pub-sub模式

[anakjh]

第一次接触0mq,写了一个pub-sub的例子.不知道为何sub端zmq_recv的时收不到消息,一直停在这里..望大神不吝赐教.
代码如下

pub.cpp #include <iostream>
#include "zhelpers.hpp"
#include "timer.h"
using namespace std;

#define within(num) (int) ((float) (num) * random () / (RAND_MAX + 1.0))

int main()
{
    int rst;
    void *context =zmq_init(1);
    void *publisher=zmq_socket(context,ZMQ_PUB);
    assert(publisher);
    zmq_bind(publisher,"tcp://*:5555");
    while(1)
    {
        sleep(5);
        zmq_msg_t msg;
        zmq_msg_init_size (&msg, 6);
        memcpy (zmq_msg_data (&msg), "hello", 6);
        rst=zmq_send (publisher, &msg,6, 0);
       cout<<"result==="<<rst<<endl;
    }
    zmq_close(publisher);
    zmq_term(context);
    return 1;
}

#include <iostream>
#include "zhelpers.hpp"
#include <cstdlib>

using namespace std;

int main()
{
    void *context =zmq_init(1);
    void *subscriber=zmq_socket(context,ZMQ_SUB);
    assert(subscriber);
    int rst = zmq_setsockopt (subscriber, ZMQ_SUBSCRIBE, "MR.X ", 5);
    zmq_setsockopt(subscriber, ZMQ_TCP_ACCEPT_FILTER, NULL, 0);
    rst=zmq_connect(subscriber,"tcp://localhost:5555");    
    while(1)
    {        
        zmq_msg_t msg;
        zmq_msg_init (&msg);
        cout<<"1111"<<endl;
        zmq_recv (subscriber, &msg,256, 0);
        cout<<"2222"<<endl;
        printf ("Received  %s\n", (char *)zmq_msg_data(&msg));
        zmq_msg_close (&msg);  
    }
    
    zmq_close(subscriber);
    zmq_term(context);
    
    return 1;
}

[ztenv]

http://www.baidu.com/s?ie=utf-8&f=8&rsv_bp=1&tn=baidu&wd=zeromq&oq=zeromq官网&rsv_pq=ed0c5de0000091d1&rsv_t=6b0eBtnj9GWX6qz2Un6V1u66KVXsWIWY7hFT3qOBgI3yN%2BL8XLwWnsSHSfU&rsv_enter=0&rsv_sug3=3&rsv_sug1=3&rsv_sug7=100&inputT=707&rsv_sug4=1351 看下这个应该对你有帮助，在会议上和别人讨论过zeromq，但没实际用过

[anakjh]

自己顶一下....

[法号随缘]

SUB端设置了ZMQ_SUBSCRIBE, "MR.X "，PUB端发送的信息必须以这个"MR.X "开头你的SUB端才能收到。PUB/SUB 发布/订阅，发布端可以发布多种类型数据，订阅端订阅什么收什么