请教：Hibernate5.0配置hbm访问Oracle数据库，sequence主键的配置问题

问题：程序运行时，hibernate自动创建的sequence不是在hbm主键配置中的名称，而是“hibernate_sequence”这个名称，怎样配置才能创建指定的sequence？

我的环境：hibernate5.0.6+oracle11g

hibernate.cfg.xml:

<!DOCTYPE hibernate-configuration PUBLIC

	"-//Hibernate/Hibernate Configuration DTD 3.0//EN"

	"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>

	<session-factory>

		<property name="hibernate.connection.driver_class">oracle.jdbc.driver.OracleDriver</property>

		<property name="hibernate.connection.url">jdbc:oracle:thin:@localhost:1521:orcl</property>

		<property name="hibernate.connection.username">ora</property>

		<property name="hibernate.connection.password">ora</property>

		<property name="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</property>

		<property name="hibernate.hbm2ddl.auto">create</property>

		<property name="hibernate.show_sql">true</property>

		<property name="hibernate.format_sql">true</property>

		<mapping resource="lenApp/pojo/sysMng/User.hbm.xml"/>

	</session-factory>

</hibernate-configuration>

User.hbm.xml

<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE hibernate-mapping PUBLIC 

    "-//Hibernate/Hibernate Mapping DTD 3.0//EN"

    "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">

<hibernate-mapping package="lenApp.pojo.sysMng">

	<class  name="User" table="tbuser">

		<id name="id" type="integer">

			<column name="id" not-null="true" sql-type="NUMBER" unique="true"></column>

			<generator class="sequence" >

				<param name="sequence">sq_tbuser_uid</param>   

			</generator>

		</id>

		<property name="lname" column="lname" type="java.lang.String" length="80"></property>

		<property name="pwd" column="pwd" type="string" length="80"></property>	

		<property name="uname">

 			<column name="uname" sql-type="varchar2(80)"></column>	

		</property>

		<property name="isdel" column="isdel" type="int"></property>

		<property name="count"  formula="(select count() from tbuser)"></property>

	</class>

</hibernate-mapping>

User.java

package lenApp.pojo.sysMng;

public class User {

	private Integer id;

	private String lname;

	private String pwd;

	private String uname;

	public int isdel;

	public int count;

	public Integer getId() {

		return id;

	}

	public void setId(Integer id) {

		this.id = id;

	}

	public String getLname() {

		return lname;

	}

	public void setLname(String lname) {

		this.lname = lname;

	}

	public String getPwd() {

		return pwd;

	}

	public void setPwd(String pwd) {

		this.pwd = pwd;

	}

	public String getUname() {

		return uname;

	}

	public void setUname(String uname) {

		this.uname = uname;

	}

	public int getIsdel() {

		return isdel;

	}

	public void setIsdel(int isdel) {

		this.isdel = isdel;

	}

	public int getCount() {

		return count;

	}

	public void setCount(int count) {

		this.count = count;

	}

	@Override

	public String toString() {

		return "User [id=" + id + ", lname=" + lname + ", pwd=" + pwd

				+ ", uname=" + uname + ", isdel=" + isdel + ", count=" + count

				+ "]";

	}



}

JUnitTest.java

@Test

	public void testAdd() {

		User user=new User();

		user.setLname("asdfasdf");

		user.setPwd("fdasfdas");

		tx=sess.beginTransaction();

		sess.persist(user);

		

		tx.commit();

		System.out.println(user.toString());

	}

执行结果：
Hibernate:
create sequence hibernate_sequence start with 1 increment by 1
Hibernate:
create table tbuser (
id NUMBER not null,
lname varchar2(80 char),
pwd varchar2(80 char),
uname varchar2(80),
isdel number(10,0),
primary key (id)
)
Hibernate:
select
hibernate_sequence.nextval
from
dual
Hibernate:
insert
into
tbuser
(lname, pwd, uname, isdel, id)
values
(?, ?, ?, ?, ?)
User [id=1, lname=asdfasdf, pwd=fdasfdas, uname=null, isdel=0, count=0]
创建的sequence不是我指定的sequence名称，求解释和处理方法，谢谢