正则表达式如何匹配问号

[cn00439805]

var url1 = 'http://m.a.com/mulu/a1.png';
var url2 = 'http://m.a.com/mulu/a1.png?r=122134234';
function getName(url){
return url.match(/.*\/(.*)(\??)/)[1];
}
console.log(getName(url1));
console.log(getName(url2));
我想用正则同时处理这两种情况，都得到"a1.png"，请问函数中的正则应该怎么修改

[cn00439805]

不一定是png var url3 = 'http://m.a.com/mulu/xx.jpeg?xx=cc'; var url4 = 'http://m.a.com/mulu/xx.xxxx?aa=bbb';

[文盲老顾]

alert(/^.*?(?=(?:\?|$))/gi.exec(url3));

[天际的海浪]

return url.match(/.*\/([^?]*)/)[1];

[Go 旅城通票]

    var url1 = 'http://m.a.com/mulu/afefa1.png';
    var url2 = 'http://m.a.com/mulu/axxafe1.png?r=122134234';
    function getName(url) {
        return url.match(/(([^\/]+)\.png)/i)[1];
    }
    console.log(getName(url1));
    console.log(getName(url2));

[scscms太阳光]

function getName(url){
    var reg = (url+"").match(/[^/]+$/);
    return reg ? reg[0].split(/[?#]/)[0] : "";
}
console.log(getName(""));
console.log(getName("/sdf/"));
console.log(getName("sdf/a1.png?sd=sd"));
console.log(getName("sdf/a1.php?sd=sd"));
console.log(getName("sdf/a1.aspx#sd"));