VideoCapture sequence为什么读取图像序列失败

[Fred Johnson]

int main(int argc, char** argv)
{
string first_file = "Campus\\trees%04d.bmp";
VideoCapture sequence(first_file);

if (!sequence.isOpened())
{
cerr << "Failed to open the image sequence!\n" << endl;

system("pause");
return 1;
}

Mat image;
namedWindow("Image sequence", 1);

for(;;)
{

sequence >> image;

if(image.empty())
{
cout << "End of Sequence" << endl;
break;
}

imshow("Image sequence", image);
waitKey(0);
}
}
文件夹Campus在当前工程中，文件夹中的文件名为trees1000.bmp，trees1001.bmp，trees1002.bmp。。。序列图像。请问为什么运行后Failed to open the image sequence!

[赵4老师]

int main(int argc, char** argv)
{
        char files[256];
        int i;
        for (i=1000;i<1010;i++) {
            sprintf(files,"Campus\\trees%04d.bmp",i);
            VideoCapture sequence(files);
            if (!sequence.isOpened())
            {
                    cerr << "Failed to open the image sequence" << files << "!\n" << endl;
                    system("pause");
                    return 1;
            }
            Mat image;
            namedWindow("Image sequence", 1);
            sequence >> image;
            if(image.empty())
            {
                    cout << "End of Sequence" << endl;
                    break;
            }
            imshow("Image sequence", image);
            waitKey(0);
        }
}

[赵4老师]

string first_file = "Campus\\trees%04d.bmp"; 改为 string first_file = "Campus\\trees1%03d.bmp";