java中用Callable创建多线程，为什么多个线程没有共享target？

[xuliwenBlogs]

import java.util.Random;
import java.util.concurrent.Callable;
import java.util.concurrent.FutureTask;

public class Test {

	public static void main(String[] args) {
		Thr hh=new Thr();
	    FutureTask<String> a=new FutureTask<String>(hh);
		new Thread(a,"aaa").start();//开启线程aaa
		System.out.println(1);
		new Thread(a,"bbb").start();//开启线程bbb
		System.out.println(2);
		new Thread(a,"ccc").start();//开启线程ccc
		System.out.println(3);

}
}

class Thr implements Callable<String>{
	int i=0;
	@Override
	public String call() throws Exception {
		/*
		 * 如果线程是aaa，则执行以下代码
		 */
	if(Thread.currentThread().getName().equals("aaa")){
		for(;i<20;i++){
			System.out.println("aaa"+i);
			}
		System.out.println("aaa finish");
		return "aaa finish";
	}

	/*
	 * 如果线程是bbb，则执行以下代码
	 */
	else if(Thread.currentThread().getName().equals("bbb")){
		for(;i<40;i++){
			System.out.println("bbb"+i);
		}
		System.out.println("bbb finish");
		return "bbb finish";
	}
	
	/*
	 * 如果线程是ccc，则执行以下代码
	 */
	else if(Thread.currentThread().getName().equals("ccc")){
		for(;i<60;i++){
			System.out.println("ccc"+i);
		}
		System.out.println("ccc finish");
		return "ccc finish";
	}
	return "exe failure";
	
	}
	
}

输出一下结果如下
1
aaa0
aaa1
aaa2
aaa3
2
aaa4
aaa5
aaa6
3
aaa7
aaa8
aaa9
aaa10
aaa11
aaa12
aaa13
aaa14
aaa15
aaa16
aaa17
aaa18
aaa19
aaa finish


请问为什么线程bbb，ccc没有被执行呢

[街头小贩]

AMD x450 双核:out

1
aaa0
aaa1
aaa2
aaa3
aaa4
aaa5
aaa6
aaa7
aaa8
aaa9
aaa10
aaa11
aaa12
aaa13
aaa14
aaa15
aaa16
aaa17
aaa18
aaa19
aaa finish
2
bbb20
bbb21
bbb22
bbb23
bbb24
bbb25
bbb26
bbb27
bbb28
bbb29
bbb30
bbb31
bbb32
bbb33
bbb34
bbb35
bbb36
bbb37
bbb38
bbb39
bbb finish
ccc37
3
ccc41
ccc42
ccc43
ccc44
ccc45
ccc46
ccc47
ccc48
ccc49
ccc50
ccc51
ccc52
ccc53
ccc54
ccc55
ccc56
ccc57
ccc58
ccc59
ccc finish

[街头小贩]

	public static void main(String[] args) {
		// TODO Auto-generated method stub
        Thr hh=new Thr();
        //FutureTask<String> a=new FutureTask<String>(hh);
        Thread t1=new Thread(new FutureTask<String>(hh),"aaa");
        t1.start();//开启线程aaa
        System.out.println(1);
        Thread t2=new Thread(new FutureTask<String>(hh),"bbb");
        t2.start();//开启线程bbb
        System.out.println(2);
        Thread t3=new Thread(new FutureTask<String>(hh),"ccc");
        t3.start();//开启线程ccc
        System.out.println(3);
	}

[qq_35321353]

我也遇到和楼主一样问题，希望大神给解答，楼上的回答，是创建多个target，问题是多个线程可不可以共享同一个target？

[AK47PLUS]

跟源码可已看出，是因为共享一个对象，第一个执行start更改了对象的状态，后面两个执行到run方法时直接返回了！详细看下面这个博客 https://mp.csdn.net/postedit/79672337

[AK47PLUS]

发错链接了，哈哈 https://blog.csdn.net/imxutao/article/details/79672337