1.串口无法接收信息
2.如何把接受的信息用波形图即时的表现出来
private void btnSend_Click(object sender, EventArgs e)
{
if (isOpen)//写串口数据
{
try
{
sp.WriteLine(tbxSendData.Text);
}
catch (Exception)
{
MessageBox.Show("发送数据时发生错误！", "错误提示");
return;
}
}
else
{
MessageBox.Show("串口未打开！", "错误提示");
return;
}
if (!CheckSendData())//检测要发送的数据
{
MessageBox.Show("请输入要发送的数据！", "错误提示");
return;
}
lblStatus.Text = "提示！！！！";
}
private void sp_DataReceived(object sender, SerialDataReceivedEventArgs e)
{
System.Threading.Thread.Sleep(100);//延时 100ms 等待接收完数据
//this.Invoke 就是跨线程访问 ui 的方法，也是本文的范例
this.Invoke((EventHandler)(delegate
{
if (isHex == false)
{
tbxRecvData.Text += sp.ReadLine();
}
else
{
Byte[] ReceivedData = new Byte[sp.BytesToRead]; //创建接收字节数组
sp.Read(ReceivedData, 0, ReceivedData.Length); //读取所接收到的数据
String RecvDataText = null;
for (int i = 0; i < ReceivedData.Length - 1; i++)
{
RecvDataText += ("0x" + ReceivedData[i].ToString("X2") + " ");
}
tbxRecvData.Text += RecvDataText;
}
sp.DiscardInBuffer();//丢弃接收缓冲区数据
}));
}
