C#接收串口数据如何用波形图显示出来？

 

  private void btnSend_Click(object sender, EventArgs e)

        {

            if (isOpen)//写串口数据

            {

                try

                {

                   

                    sp.WriteLine(tbxSendData.Text);



                }

                catch (Exception)

                {

                    MessageBox.Show("发送数据时发生错误！", "错误提示");

                    return;

                }

            }

            else

            {

                MessageBox.Show("串口未打开！", "错误提示");

                return;

            }

            if (!CheckSendData())//检测要发送的数据

            {

                MessageBox.Show("请输入要发送的数据！", "错误提示");

                return;

            }

            lblStatus.Text = "提示！！！！";

        }



private void sp_DataReceived(object sender, SerialDataReceivedEventArgs e)

        {

            System.Threading.Thread.Sleep(100);//延时 100ms 等待接收完数据

                                               //this.Invoke 就是跨线程访问 ui 的方法，也是本文的范例

            this.Invoke((EventHandler)(delegate

            {

                if (isHex == false)

                {

                    tbxRecvData.Text += sp.ReadLine();

                }

                else

                {

                    Byte[] ReceivedData = new Byte[sp.BytesToRead]; //创建接收字节数组

                    sp.Read(ReceivedData, 0, ReceivedData.Length); //读取所接收到的数据

                    String RecvDataText = null;

                    for (int i = 0; i < ReceivedData.Length - 1; i++)

                    {

                        RecvDataText += ("0x" + ReceivedData[i].ToString("X2") + " ");

                    }

                    tbxRecvData.Text += RecvDataText;

                }

                sp.DiscardInBuffer();//丢弃接收缓冲区数据

            }));

        }