求一个将阿拉伯数字转换为美元大写的代码或函数。。。

qq_35012205 2016-05-16 12:22:17

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赵4老师 2016-05-30

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million，billion后面直接出现几十或几也得加and吧。

lm_whales 2016-05-29

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1005 ==One thousand and five 105 ==One hundred and five 155==One hundred and fifty-five 100155 ==One hundred thousand one hundred and fifty-five 101155 ==One hundred and one thousand one hundred and fifty-five 就是千百加上几十，几个都要and 他们是12进制，+百进制+千进制 ;三种进制一百以内的数和千百在一起需要 and

赵4老师 2016-05-23

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是不是只要在每个hundred后面，且紧跟几十或几的前面，加" and "就行了？

lm_whales 2016-05-21

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引用 2 楼 zhao4zhong1 的回复:

仅供参考：


。。。。
    return 0;
}
//                  0 is [zero]
//                  1 is [one]
//                  9 is [nine]
//                 19 is [nineteen]
//                 20 is [twenty]
//                 21 is [twenty one]
//                 90 is [ninety]
//                100 is [one hundred]
//               2000 is [two thousand]
//            3000000 is [three million]
//         4000000000 is [four billion]
//1000000000000000002 is [one billion billion two]
//1234567890123456789 is [one billion two hundred thirty four million five hundred sixty seven thousand eight hundred ninety billion one hundred twenty three million four hundred fifty six thousand seven hundred eighty nine]
//9223372036854775807 is [nine billion two hundred twenty three million three hundred seventy two thousand thirty six billion eight hundred fifty four million seven hundred seventy five thousand eight hundred seven]
//

有木有觉得在本ID的嘴里“仅供参考”就和“芝麻开门”一样灵验？

忘了说了，适当的地方，加上 and

lm_whales 2016-05-21

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引用 2 楼 zhao4zhong1 的回复:

仅供参考：

#pragma warning(disable:4996)
#include <stdio.h>
char *NUMBERS_UP_TO_20[] ={
    "zero"   ,"one"    ,"two"     ,"three"   ,"four"    ,
    "five"   ,"six"    ,"seven"   ,"eight"   ,"nine"    ,
    "ten"    ,"eleven" ,"twelve"  ,"thirteen","fourteen",
    "fifteen","sixteen","sventeen","eighteen","nineteen",
};
char *NUMBERS_MULTIPLE_OF_10[] ={
    "twenty", "thirty" , "fourty", "fifty" ,
    "sixty" , "seventy", "eighty", "ninety",
};
char *NumberToString(long long int nNum,char *p) {
    char *q;
    int n;
    long long int nCrntNumber;

    q=p;
    if (nNum<0) return "";
    if (nNum<20) return NUMBERS_UP_TO_20[nNum];

    nCrntNumber=nNum/1000000000;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s billion ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=1000000000;
    }

    nCrntNumber=nNum/1000000;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s million ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=1000000;
    }

    nCrntNumber=nNum/1000;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s thousand ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=1000;
    }

    nCrntNumber=nNum/100;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s hundred ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=100;
    }

    if (0<nNum && nNum<20) {
        n=sprintf(p,"%s ",NumberToString(nNum,p));
        p+=n;
    } else {
        nCrntNumber=nNum/10;
        if (nCrntNumber>0) {
            n=sprintf(p,"%s ",NUMBERS_MULTIPLE_OF_10[nCrntNumber-2]);
            p+=n;
            nNum%=10;
        }

        nCrntNumber=nNum;
        if (nCrntNumber>0) {
            n=sprintf(p,"%s ",NumberToString(nCrntNumber,p));
            p+=n;
        }
    }

    if (p[-1]==' ') p[-1]=0;

    return q;
}
int main() {
    char sRes[256];
    long long int d;

    d=                  0  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                  1  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                  9  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 19  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 20  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 21  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 90  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                100  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=               2000  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=            3000000  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=         4000000000ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=1000000000000000002ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=1234567890123456789ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=9223372036854775807ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));//2^63-1
    return 0;
}
//                  0 is [zero]
//                  1 is [one]
//                  9 is [nine]
//                 19 is [nineteen]
//                 20 is [twenty]
//                 21 is [twenty one]
//                 90 is [ninety]
//                100 is [one hundred]
//               2000 is [two thousand]
//            3000000 is [three million]
//         4000000000 is [four billion]
//1000000000000000002 is [one billion billion two]
//1234567890123456789 is [one billion two hundred thirty four million five hundred sixty seven thousand eight hundred ninety billion one hundred twenty three million four hundred fifty six thousand seven hundred eighty nine]
//9223372036854775807 is [nine billion two hundred twenty three million three hundred seventy two thousand thirty six billion eight hundred fifty four million seven hundred seventy five thousand eight hundred seven]
//

有木有觉得在本ID的嘴里“仅供参考”就和“芝麻开门”一样灵验？

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赵4老师 2016-05-16

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仅供参考：

#pragma warning(disable:4996)
#include <stdio.h>
char *NUMBERS_UP_TO_20[] ={
    "zero"   ,"one"    ,"two"     ,"three"   ,"four"    ,
    "five"   ,"six"    ,"seven"   ,"eight"   ,"nine"    ,
    "ten"    ,"eleven" ,"twelve"  ,"thirteen","fourteen",
    "fifteen","sixteen","sventeen","eighteen","nineteen",
};
char *NUMBERS_MULTIPLE_OF_10[] ={
    "twenty", "thirty" , "fourty", "fifty" ,
    "sixty" , "seventy", "eighty", "ninety",
};
char *NumberToString(long long int nNum,char *p) {
    char *q;
    int n;
    long long int nCrntNumber;

    q=p;
    if (nNum<0) return "";
    if (nNum<20) return NUMBERS_UP_TO_20[nNum];

    nCrntNumber=nNum/1000000000;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s billion ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=1000000000;
    }

    nCrntNumber=nNum/1000000;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s million ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=1000000;
    }

    nCrntNumber=nNum/1000;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s thousand ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=1000;
    }

    nCrntNumber=nNum/100;
    if (nCrntNumber>0) {
        n=sprintf(p,"%s hundred ",NumberToString(nCrntNumber,p));
        p+=n;
        nNum%=100;
    }

    if (0<nNum && nNum<20) {
        n=sprintf(p,"%s ",NumberToString(nNum,p));
        p+=n;
    } else {
        nCrntNumber=nNum/10;
        if (nCrntNumber>0) {
            n=sprintf(p,"%s ",NUMBERS_MULTIPLE_OF_10[nCrntNumber-2]);
            p+=n;
            nNum%=10;
        }

        nCrntNumber=nNum;
        if (nCrntNumber>0) {
            n=sprintf(p,"%s ",NumberToString(nCrntNumber,p));
            p+=n;
        }
    }

    if (p[-1]==' ') p[-1]=0;

    return q;
}
int main() {
    char sRes[256];
    long long int d;

    d=                  0  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                  1  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                  9  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 19  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 20  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 21  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                 90  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=                100  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=               2000  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=            3000000  ;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=         4000000000ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=1000000000000000002ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=1234567890123456789ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));
    d=9223372036854775807ll;printf("%19lld is [%s]\n",d,NumberToString(d,sRes));//2^63-1
    return 0;
}
//                  0 is [zero]
//                  1 is [one]
//                  9 is [nine]
//                 19 is [nineteen]
//                 20 is [twenty]
//                 21 is [twenty one]
//                 90 is [ninety]
//                100 is [one hundred]
//               2000 is [two thousand]
//            3000000 is [three million]
//         4000000000 is [four billion]
//1000000000000000002 is [one billion billion two]
//1234567890123456789 is [one billion two hundred thirty four million five hundred sixty seven thousand eight hundred ninety billion one hundred twenty three million four hundred fifty six thousand seven hundred eighty nine]
//9223372036854775807 is [nine billion two hundred twenty three million three hundred seventy two thousand thirty six billion eight hundred fifty four million seven hundred seventy five thousand eight hundred seven]
//

有木有觉得在本ID的嘴里“仅供参考”就和“芝麻开门”一样灵验？

lm_whales 2016-05-16

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引用楼主 qq_35012205 的回复:

求一个将阿拉伯数字转换为美元大写的代码或函数。。。

? 这话怎么说啊转换为美语（美式英语）？好像不能直接拿数字换美元？可以用人民币，英镑等等这一类的货币直接兑换如果仅仅是是美元的表示，加个 $ 即可 $ 5,$100 这种便是美语要变成 five $，a hundred $ 这种吧考虑到都是用的数字冠词换成数字吧 one hundred $ 主要麻烦是，要考虑单位百，千，兆，。。。。。国外，一般大数字。用千进制单位thousand，million,billion,trillion 注意美国和英国billion 含义有所不同哦国内万进制单位万，亿，万亿，亿亿过去有十万为亿，十亿为兆的用法，这是十进制，所有单位都是十进制。也有万万为亿，万亿为兆的用法，这是万进制，万以后的大数，采用万进制。不过，现在兆以上的不用了兆用作百万了，是十进制的