错误:reference to non-static member function must be called

[Bovinitwo]

找了一下午还是没搞懂,为什么会这样报错,

#include <algorithm>
class Coder {
public:
  		vector<string> findCoder(vector<string> &A, int n)
 		{
            vector<string> result;

          stable_sort(A.begin(),A.end(),compare_times);//报错:reference to non-static member function must be called

            vector<string>::iterator p_Push=find_first(A);
            while(p_Push<A.end())
            {
                result.push_back(*p_Push);
                p_Push++;
            }
            return result;
		}
    
    	bool compare_times(const string &a,const string &b)
        {
            return times(a)<times(b);
        }
    
  		vector<string>::iterator find_first(vector<string> &A)
        {
            for(vector<string>::iterator pFirst=A.begin();pFirst!=A.end();pFirst++)
            {
                if(times(*pFirst)!=0)
                    return pFirst;
            }
        }
    
    	int times(string a,int currentIndex=0,int state=0)
        {
           if(currentIndex==a.size())
               return 0;
           switch (state)
           {
               case 0:
                    {
                        if(a[currentIndex]=='c'||a[currentIndex]=='C')	return times(a,currentIndex+1,1);
                        else	return times(a,currentIndex+1,0);
                    }
                case 1:
                    {
                        if(a[currentIndex]=='o'||a[currentIndex]=='O')	return times(a,currentIndex+1,2);
                        else	return times(a,currentIndex+1,0);
                    }
                case 2:
                    {
                        if(a[currentIndex]=='d'||a[currentIndex]=='D')	return times(a,currentIndex+1,3);
                        else	return times(a,currentIndex+1,0);
                    }
                case 3:
                    {
                        if(a[currentIndex]=='e'||a[currentIndex]=='E')	return times(a,currentIndex+1,4);
                        else	return times(a,currentIndex+1,0);
                    }
                default:
                    {
                        if(a[currentIndex]=='r'||a[currentIndex]=='R')	return 1+times(a,currentIndex+1,0);
                        else	return times(a,currentIndex+1,0);
                    }
           }
        }
};

我把这些函数不写在类中,而是作普通函数,就不会报错,求大神啊

[dustpg]

面向对象编程不是逮着就加个class

[Bovinitwo]

找了一下午还是没搞懂,为什么会这样报错, 重新贴一下代码: class Coder { public: vector<string> findCoder(vector<string> &A, int n) { vector<string> result; stable_sort(A.begin(),A.end(),compare_times); //报错:reference to non-static member function must be called vector<string>::iterator p_Push=find_first(A); while(p_Push<A.end()) { result.push_back(*p_Push); p_Push++; } return result; } bool compare_times(const string &a,const string &b) { return times(a)<times(b); } vector<string>::iterator find_first(vector<string> &A) { for(vector<string>::iterator pFirst=A.begin();pFirst!=A.end();pFirst++) { if(times(*pFirst)!=0) return pFirst; } } int times(string a,int currentIndex=0,int state=0) { if(currentIndex==a.size()) return 0; switch (state) { case 0: { if(a[currentIndex]=='c'||a[currentIndex]=='C') return times(a,currentIndex+1,1); else return times(a,currentIndex+1,0); } case 1: { if(a[currentIndex]=='o'||a[currentIndex]=='O') return times(a,currentIndex+1,2); else return times(a,currentIndex+1,0); } case 2: { if(a[currentIndex]=='d'||a[currentIndex]=='D') return times(a,currentIndex+1,3); else return times(a,currentIndex+1,0); } case 3: { if(a[currentIndex]=='e'||a[currentIndex]=='E') return times(a,currentIndex+1,4); else return times(a,currentIndex+1,0); } default: { if(a[currentIndex]=='r'||a[currentIndex]=='R') return 1+times(a,currentIndex+1,0); else return times(a,currentIndex+1,0); } } } };

[Bovinitwo]

引用 1 楼 dustpg 的回复:

面向对象编程不是逮着就加个class

这是牛客网的OJ,不是我要写一个class,然后一直不能通过编译,搜了一下网上的相关答案也不是很明白,所以上来问问

[赵4老师]

http://fanyi.baidu.com/#en/zh/reference%20to%20non-static%20member%20function%20must%20be%20called

[小灸舞]

成员函数第一个参数默认是this指针， 所以compare_times函数其实是3个参数
加static ，静态函数就没有this指针，但你又调用了times成员函数。。。我服了
楼主还是把compare_times写到类外面去吧

[Bovinitwo]

引用 5 楼 qq423399099 的回复:

成员函数第一个参数默认是this指针， 所以compare_times函数其实是3个参数 加static ，静态函数就没有this指针，但你又调用了times成员函数。。。我服了 楼主还是把compare_times写到类外面去吧

谢谢,我下来再看看书