catch 中 throw e 什么效果？

[PrayAllForYou]

package exception;

public class TestException {
public TestException() {
}

boolean testEx() throws Exception {
boolean ret = true;
try {
ret = testEx1();
} catch (Exception e) {
System.out.println("testEx, catch exception");
ret = false;
throw e;
} finally {
System.out.println("testEx, finally; return value=" + ret);
return ret;
}
}

boolean testEx1() throws Exception {
boolean ret = true;
try {
ret = testEx2();
if (!ret) {
return false;
}
System.out.println("testEx1, at the end of try");
return ret;
} catch (Exception e) {
System.out.println("testEx1, catch exception");
ret = false;
throw e;
} finally {
System.out.println("testEx1, finally; return value=" + ret);
return ret;
}
}

boolean testEx2() throws Exception {
boolean ret = true;
try {
int b = 12;
int c;
for (int i = 2; i >= -2; i--) {
c = b / i;
System.out.println("i=" + i);
}
return true;
} catch (Exception e) {
System.out.println("testEx2, catch exception");
ret = false;
throw e;
} finally {
System.out.println("testEx2, finally; return value=" + ret);
return ret;
}
}

public static void main(String[] args) {
TestException testException1 = new TestException();
try {
testException1.testEx();
} catch (Exception e) {
e.printStackTrace();
}
}
}
结果：
i=2
i=1
testEx2, catch exception
testEx2, finally; return value=false
testEx1, finally; return value=false
testEx, finally; return value=false

运行testEx2() catch捕获异常，并且往上抛出异常，testEx1 中 这句话 ret = testEx2(); 不该有异常么， 不应该进入testEx1 的catch语句嘛？？？

[家里敷泥呀]

因为testEx2的finally里面return了。 你的代码相当于是先throw后return，throw和return是相互矛盾的，这里有个后来居上的原则，哪个在后面，那个就把前面的覆盖了。 你可以试试，在catch中return，然后finally中throw。

[尼古拉斯-全蛋]

打断点调试一下