哪位大神来帮我看看这个51单片机实现数字电压表的代码

[wugang589]

#include <reg52.h>
#include <intrins.h>
#define _Nop() _nop_();//空操作

sbit ST = P3^0; 
sbit OE = P3^1;
sbit EOC = P3^2;

sbit BEEP = P3^3;

sbit V1 = P3^4;
sbit V2 = P3^5;
sbit V3 = P3^6;
sbit V4 = P3^7;
unsigned int h;
unsigned char digit[5];
unsigned char table[] = {0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,//不带小数点编码
                    0x40,0x79,0x24,0x30,0x19,0x12,0x02,0x78,0x00,0x10};	 //带小数点编码

void delay(unsigned int tc){
    while (tc != 0){
	unsigned int i;
	for(i = 0; i < 100;i ++)
	tc--;
	}
}

unsigned char adc0809(){
	unsigned char adda;
	ST = 0;
	OE = 0;
	P1 = 0xff;
	ST = 1; 
	_nop_();_nop_();
	ST = 0;
	_nop_();_nop_();_nop_();_nop_();
	while(EOC == 0);
	OE = 1;
	adda = P1;
	_nop_();
	OE = 0;
	return(adda);
}

unsigned int dacl(){
	int x;
	unsigned int dady = 0;
	for(x = 0;x < 10;x++)
		dady = adc0809() + dady;
	dady = dady / 10;
	return(dady);
}

void loop(void){
	while(h == 1){
		BEEP = !BEEP;
		delay(100);
		BEEP = !BEEP;

	}
}

void led_display(float val){
	if(V1 == 0){
		val = val * 500 /255;
		if(val > 200){
			//P0.7 = 1;
			h = 1;
			loop();
		}
		else if(val < 200 && val >20){
			digit[3] = 1;
			digit[2] = val / 100;
			val = val - 100 * digit[4];
			digit[1] = val / 10;
			val = val - 10 * digit[3];
			digit[0] = val * 10 / 10;

			digit[3] = table[digit[3]];
			digit[2] = table[digit[2]];
			digit[1] = table[digit[1]];
			digit[0] = table[table[0]];
		}
	}
	else if(V2 == 0){
		val = val * 10 / 255;
		if(val > 20 || val < 2 ){
			h = 1;
			loop();
		}
		else {
			digit[3] = 1;
			digit[2] = val / 10;
			val = val - 10 * digit[2];
			digit[1] = val * 10 / 10;
			val = val - digit[1]; 
            digit[0] = val * 10 / 10;

            digit[3] = table[digit[3]];
            digit[2] = table[digit[2]];
            digit[1] = table[digit[1]];
            digit[0] = table[digit[0]];
		}
	}
	else if(V3 == 0){
		val =10 * 5 * val / 255 ;
		if(val > 20 || val < 2){
			h = 1;
			loop();
		}
		else {
			digit[3] = 1;
			digit[2] = val / 10;
			val = val - 10 * digit[2];
			digit[1] = val * 10 / 10;
			val = val - digit[1]; 
            digit[0] = val * 10 / 10;

            digit[3] = table[digit[3]];
            digit[2] = table[digit[2]];
            digit[1] = table[digit[1]];
            digit[0] = table[digit[0]]; 
		}
	}
	else if(V4 == 0){
		val = 500 * val / 255;
		if(val > 200){
			h = 1;
			loop();
		}
		else {
			digit[3] = 1;
			digit[2] = val / 100;
			val = val - 100 * digit[4];
			digit[1] = val / 10;
			val = val - 10 * digit[3];
			digit[0] = val * 10 / 10;

			digit[3] = table[digit[3]];
			digit[2] = table[digit[2]];
			digit[1] = table[digit[1]];
			digit[0] = table[table[0]];
		}
	}
}

void main(){
	int i;
	int j = 3;
	int k;
	unsigned char fuhao[4];
	BEEP = 0;
	led_display(dacl());

	for(i = 3;i >= 0;i--){
		if(digit[i] != 0xc0){
			fuhao[j--] = digit[i];

		}
		for(k = 0;k < 4;k++){
			P0 = 0x01 << k;
			P2 = fuhao[k];
			delay(5);
		}
	}
}

这段代码是用C51和AD0809实现数字电压表的，但是程序烧进去没有结果，哪位大神可以抽空帮我看看。。。感激不尽。个人感觉可能main有问题。或者在adc0809模块有问题。感觉有点晕。求大神帮忙看看，谢谢了！

[dceacho]

弄个仿真器，不然光代码不容易发现哪有问题

[fanleung]

可以用灯来验证程序逻辑

[wugang589]

引用 3楼gordon71305 的回复:

是的，我今天早上也发现这个问题了。目前情况是数码管不亮，前面的adc0809模块没问题吗？总感觉ad0809转换这里可能有问题。

[gordon71305]

[Crystallllllll]

分模块检查，先看显示是否正常，再去调AD