JSON对象转成dynamic如何获取属性

[CottZheng]

这有一个GeoJSON对象，我把它转换成dynamic类型变量dy

{"type":"GeometryCollection","geometries":[
{"type":"Point","coordinates":[-342419109908.69024,146751047103.7244]},
{"type":"Point","coordinates":[-230354673938.57346,-36465411704.56182]},
{"type":"Point","coordinates":[-13341004282.156763,-57811018556.01264]},
{"type":"Point","coordinates":[111175035684.6397,73820223694.60075]},
{"type":"Point","coordinates":[89829428833.18887,258815483073.84122]},
{"type":"Point","coordinates":[-107617434542.73123,322852303628.19366]},
{"type":"Point","coordinates":[-239248676793.34463,255257881931.93274]}
]}

我可以通过dy.type获取到geometrycollection，我如果想获取到Point和坐标值，该如何操作？

[xuzuning]

dy.geometries[i].coordinates[0] dy.geometries[i].coordinates[1] i = 0,1,2,3...n

[CottZheng]

引用 1 楼 xuzuning 的回复:

dy.geometries[i].coordinates[0] dy.geometries[i].coordinates[1] i = 0,1,2,3...n

“System.Collections.Generic.Dictionary<string,object>”未包含“coordinates”的定义，是什么情况？

[xuzuning]

那谁知道，你又没告诉我们对象的结构

            var s = File.ReadAllText("d7.txt");
            var a = JObject.Parse(s);
            for (var i = 0; i < a["geometries"].Count(); i++)
            {
                Console.WriteLine("x={0} y={1}", a["geometries"][i]["coordinates"][0], a["geometries"][i]["coordinates"][1]);
            }

[我叫小菜菜]

标准的json，直接转换不就OK了嘛。

[CottZheng]

引用 3 楼 xuzuning 的回复:

那谁知道，你又没告诉我们对象的结构

            var s = File.ReadAllText("d7.txt");
            var a = JObject.Parse(s);
            for (var i = 0; i < a["geometries"].Count(); i++)
            {
                Console.WriteLine("x={0} y={1}", a["geometries"][i]["coordinates"][0], a["geometries"][i]["coordinates"][1]);
            }

明白了，谢谢！