字符串转字节数组,求一个函数

[我看你有戏]

char* pData = "00 3a 00 00 00 00 00 00 00 00 00 00 00 00 00 00 40 00 00 40 2e 64";
需要转成一个字节数组 BYTE aryby[]={0x00,0x3a,0x00,0x00.........,0x40,0x2e,0x64};

求一个转化函数，谢谢

[赵4老师]

仅供参考：

#include <stdio.h>
#include <string.h>
#include <conio.h>
FILE *fi,*fo;
int r;
unsigned int n,c;
long offset;
//-------------------------------------------------------
void main(int argc,char *argv[])
{
    if (argc<3) {
        cprintf("Hex2Bin srcfile desfile");
        return;
    }
    if ((fi=fopen(argv[1],"rb"))==NULL) {
        cprintf("Can not find file %s",argv[1]);
        return;
    }
    if ((fo=fopen(argv[2],"wb"))==NULL) {
        fclose(fi);
        cprintf("Can not create file %s",argv[2]);
        return;
    }
    n=0;
    while (1) {
        offset=ftell(fi);
        r=fscanf(fi,"%2x",&c);
        if (EOF==r) break;//
        if (1==r) {
            fputc(c,fo);
            n++;
        } else {//0==r
            fseek(fi,offset,SEEK_SET);//因为VC6的Release版及其VC7,8,9,10,...版的fscanf未按约定保持offset不变，所以此处必须恢复offset
            r=fgetc(fi);
            if (EOF==r) break;//
        }
    }
    fcloseall();
    cprintf("OK to Hex2Bin %d bytes.",n);
}

[lm_whales]

读取两个字符转换为对应的单字节字符 C语言 int c=0; sscanf (s,"%2x",&c); aryby[i]=c; 现在也可以用 hh前缀 sscanf (s,"%2hhx",aryby+i);

[幻夢之葉]

int len = strlen(pData); memcpy(aryby, pData, len*sizeof(char));