JavaScriptSerializer 转XML

[cxy521]

<?xml version="1.0" encoding="utf-8"?>
<string xmlns="Able">
<ReturnValue>
<State>1</State>
<Count>1</Count>
<ResponseID>54877596</ResponseID>
</ReturnValue>
</string>
上面这段XML如果我用 JavaScriptSerializer 方法转T，T的Model 怎么写？
/// <summary>
/// JSON文本转对象,泛型方法
/// </summary>
/// <typeparam name="T">类型</typeparam>
/// <param name="jsonText">JSON文本</param>
/// <returns>指定类型的对象</returns>
public static T JSONToObject<T>(string jsonText)
{
JavaScriptSerializer jss = new JavaScriptSerializer();
try
{
return jss.Deserialize<T>(jsonText);
}
catch (Exception ex)
{
throw new Exception("JSONHelper.JSONToObject(): " + ex.Message);
}
}
*************************************************************************

[巴士上的邂逅]

首先将完整的Xml文本复制一下，在vs2013.net4.5项目下，依次选择菜单：编辑-》选择性粘贴-》将XML粘贴为类，会生成一下对应的实体类

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "Able")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "Able", IsNullable = false)]
public partial class @string
{

    private stringReturnValue returnValueField;

    /// <remarks/>
    public stringReturnValue ReturnValue
    {
        get
        {
            return this.returnValueField;
        }
        set
        {
            this.returnValueField = value;
        }
    }
}

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "Able")]
public partial class stringReturnValue
{

    private byte stateField;

    private byte countField;

    private uint responseIDField;

    /// <remarks/>
    public byte State
    {
        get
        {
            return this.stateField;
        }
        set
        {
            this.stateField = value;
        }
    }

    /// <remarks/>
    public byte Count
    {
        get
        {
            return this.countField;
        }
        set
        {
            this.countField = value;
        }
    }

    /// <remarks/>
    public uint ResponseID
    {
        get
        {
            return this.responseIDField;
        }
        set
        {
            this.responseIDField = value;
        }
    }
}

[摇撼大地]

引用 1 楼 yuankaiwsl 的回复:

首先将完整的Xml文本复制一下，在vs2013.net4.5项目下，依次选择菜单：编辑-》选择性粘贴-》将XML粘贴为类，会生成一下对应的实体类

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "Able")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "Able", IsNullable = false)]
public partial class @string
{

    private stringReturnValue returnValueField;

    /// <remarks/>
    public stringReturnValue ReturnValue
    {
        get
        {
            return this.returnValueField;
        }
        set
        {
            this.returnValueField = value;
        }
    }
}

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "Able")]
public partial class stringReturnValue
{

    private byte stateField;

    private byte countField;

    private uint responseIDField;

    /// <remarks/>
    public byte State
    {
        get
        {
            return this.stateField;
        }
        set
        {
            this.stateField = value;
        }
    }

    /// <remarks/>
    public byte Count
    {
        get
        {
            return this.countField;
        }
        set
        {
            this.countField = value;
        }
    }

    /// <remarks/>
    public uint ResponseID
    {
        get
        {
            return this.responseIDField;
        }
        set
        {
            this.responseIDField = value;
        }
    }
}

学到了~~~