请教一个多进程编程的基础问题

[netepic]

from multiprocessing import Process
import os


def run(name):
    for i in range(1, 10):
        print(os.getpid(), i, 'run')

if __name__ == '__main__':
    p1 = Process(target=run, args=('test',))
    p2 = Process(target=run, args=('test',))
    print('Child process will start.')
    p1.start()
    p2.start()

执行的结果是：
Child process will start.
2772 1 run
2772 2 run
2772 3 run
2772 4 run
2772 5 run
2772 6 run
2772 7 run
2772 8 run
2772 9 run
8680 1 run
8680 2 run
8680 3 run
8680 4 run
8680 5 run
8680 6 run
8680 7 run
8680 8 run
8680 9 run

这完全是顺序执行啊，没有一点并发的感觉啊。请问我哪里写错了吗？
PS：可能会有人建议我把run函数中的循环次数调大一点，我试过即使调到10000，也一样是顺序执行。

[sprawling]

跟楼主的执行环境有关系,在交互环境里面执行就是顺序的,解释器里面就不一样了.

[Thomas_young2015]

from threading import Thread import os def run(name): for i in range(1, 10): print(os.getpid(), i, 'run') if __name__ == '__main__': thread = [] thread_count = 2 for i in range(thread_count): p = Thread(target=run, args=('test',)) thread.append(p) print('Child process will start.') for p in thread: p.start() ==================== RESTART: D:/python study/process.py ==================== Child process will start. 48764876 >>> 11 runrun 48764876 22 runrun 48764876 33 runrun 48764876 44 runrun 48764876 55 runrun 48764876 66 runrun 48764876 77 runrun 48764876 88 runrun 48764876 99 runrun

[ForestDB]

现在的CPU太快了。 from multiprocessing import Process import os import time def run(name): for i in range(1, 10): print(os.getpid(), i, 'run') time.sleep(1) if __name__ == '__main__': p1 = Process(target=run, args=('test',)) p2 = Process(target=run, args=('test',)) print 'Child process wil start.' p1.start() p2.start() from multiprocessing import Process import os import time def run(name): for i in range(1, 10): print(os.getpid(), i, 'run') time.sleep(1 if name == 'test1' else 2) if __name__ == '__main__': p1 = Process(target=run, args=('test1',)) p2 = Process(target=run, args=('test2',)) print 'Child process wil start.' p1.start() p2.start()