ajax把需要查询的班级的id传到后台,后台根据id查出数据后,发送到前台。

[大帅好]

<div class="rgh1">
							 <form id="table20" name="form6" method="post" name="people" action="../admin/setting_school_a.php?class=<?php echo $class;?>" enctype="multipart/form-data" onsubmit="return validateMe(this);">
							 <p id="crgt61" style="width: 517px;height: 87px;font-size: 28px;position: relative;float: left;margin-left: 20px;">
								<span class="cg41"style="position:absolute;top: 8px;">成员下载</span>
								<span class="cg42" style="position: absolute;cursor: pointer;top: 45px;left: 0px;">成员上传</span>
								<input type="file" id="cg62" name="student_table" style="font-size: 23px;width: 276px;position: absolute;top: 52px;left: 105px;">
								<span id="cg63" style="background: #e7e7e7;border: 1px solid #999999;padding: 5px 15px;color: #595f53;font-size: 21px;left: 310px;left: 395px;"><a href="smis.xls"  style="color:#000000;">下载</span></a>
								<button id="cg64" style="position: absolute;padding: 2px 15px;top: 53px;left: 395px;font-size: 20px;color: #2A2A2A;font-family: "微软雅黑";" onclick="ck();">提交</button>
							    </p>
							    <input type='hidden' name='hiddenClassId' id='hiddenClassId' value='' />
							  </form>
							    <form id="table20" name="form6" name="people"action="./admin1php.php?a=updata&class=<?php echo $class;?>" method="post">
								<p id="crgt62" style="width: 295px;height: 85px;margin-left: 520px;float: right;margin-top: -85px;">
									<button id="cg65"style="padding: 3px 20px;font-size: 20px;font-family: '微软雅黑';">保存</button>
									<input type="button" style="font-size: 19px;font-family:微软雅黑;margin-top: 27px;padding: 4px 20px;" name="cg66" id="cg66" onabort="upload()" value="删除"/>
								</p>
                            </div>
					   
						<div class="right3">
							<div id="rgh21">
								<div id="rgh211">
									<?php
										echo "<p><span>终端名称</span></p>";
									    $sql="select id,class,location from bp_classrooms";
									    $result = mysql_query($sql);
									   	while($row=mysql_fetch_array($result)){							   
										echo "<p><span id='classid' classid='$row[class]'>$row[location]</span></p>\n";
										 }
									  	mysql_freeresult($result);	
								    ?>
								</div>
								
								//这个地方就是要写的ajax的代码，
                                            
								<script>
									$(function(){
										$('#hiddenClassId').val($('#classid').first().attr('classid'));
										  
									})
									
									$('p').click(function(){
										$('#hiddenClassId').val($(this).children('span').attr('classid'));
										
										
									})
									
								</script>		

[大帅好]

[Go 旅城通票]

http://www.w3school.com.cn/jquery/ajax_load.asp

[大帅好]

我用过了，但是获取不到数据。

[大帅好]

引用 2 楼 showbo 的回复:

http://www.w3school.com.cn/jquery/ajax_load.asp

我用过了，但是数据带不过来。