求下列字符串样式的生成算法

[omagic]

如题：
字符串样式为：[{"field":"String1","operator":"String2","value":["String3"]}]

哪位朋友帮个忙，谢谢！

我自己的算法用到了Gson，算法大致如下，前半段生成没有问题，只是最有一个value始终生成不完整差个中括号『[]』内的格式：
最后生成的字符串是这样的：[{"field":"String1","operator":"String2","value":"[String3]"}]

   private static List<Object> CreateFilter(String field, String operator, String value) {
        List<Object> Filter = new ArrayList<Object>();
        JsonObject tFilter = new JsonObject();
        tFilter.addProperty("field", field);
        tFilter.addProperty("operator", operator);
        List<String> om = new ArrayList<String>();
        om.add(value);
        tFilter.addProperty("value",om.toString());
        Filter.add(tFilter);
        return Filter;
    }

[爱睡觉的阿狸]

public class TestGson {

	public static void main(String[] args) {
		List<Object> list = createFilter("String1", "String2", "String3"); 
		Gson gson = new Gson();
		System.out.println(gson.toJson(list));
	}
	
	private static List<Object> createFilter(String field, String operator, String value) {
        List<Object> filter = new ArrayList<Object>();
        Map<String, Object> map = new LinkedHashMap<String, Object>();
        map.put("field", field);
        map.put("operator", operator);
        List<String> om = new ArrayList<String>();
        om.add(value);
        map.put("value",om);
        filter.add(map);
        return filter;
    }
}

[omagic]

非常感谢版主的回答，其实后来我换了一个思路来弄，效果能达到。。我好像有强迫症，必须用算法来完成

private static String CreateFilters(String field, String operator, String value) {
        return "[{\"field\":\"" + field +"\",\"operator\":\"" + operator + "\",\"value\":[\"" + value + "\"]}]";
    }