js关于arttemplate的不转义问题
编程小小鸟 2017-02-22 10:00:56 <script src="template.js"></script>
<script src="template-native.js"></script>
</head>
<body>
<div id="content"></div>
<script id="test" type="text/html">
<h1><%=title%></h1>
<ul>
<%for(i = 0; i < list.length; i ++) {%>
<li><%=i + 1%><%=list[i]%></li>
<%}%>
</ul>
</script>
<script>
var data = {
title: '基本例子',
isAdmin: true,
list: [
'<a href="mm33.html" target="_blank"><img src="1F.jpg" width="21" height="220" alt=""></a>',
'<a href="mm33.html" target="_blank"><img src="1F.jpg" width="40" height="220" alt=""></a>',
'<a href="mm33.html" target="_blank"><img src="1F.jpg" width="60" height="220" alt=""></a>'
]
};
var html = template('test', data);
document.getElementById('content').innerHTML = html;
</script>
</body>
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arttemplate模板中要使<a href="mm33.html" target="_blank"><img src="1F.jpg" width="21" height="220" alt=""></a>',不转义怎么做