char*outPath, int & outLen 参数怎么声明

[美薇]

['int WINAPI ftGetSnapedImagePath(int channel, char*outPath, int & outLen);
C# 例程是这样声明的：
[DllImport("FTDetectUCamera.dll", CallingConvention = CallingConvention.StdCall, EntryPoint = "ftGetSnapedImagePath")]
public static extern int ftGetSnapedImagePath(int channel, byte [] outPath, ref int outLen);
我把它改成下面VB这样声明不知是否正确
Private Declare Function ftGetSnapedImagePath Lib "FTDetectUCamera.dll" (ByVal chn As Long, ByRef outPath() As Byte, ByRef outLen As Long)
Dim ret As Long
Dim camIndex As Long

Dim outPath(255) As Byte
Dim outLen As Long
Dim imgPath As String
ret = ftGetSnapedImagePath(camIndex, outPath, outLen)

'运行老是错误，新手上路请指教

[美薇]

C# 例程这样使用的： byte[] outPath = new Byte[256]; int outLen = 0; int ret = ftGetSnapedImagePath(camIndex, outPath, ref outLen); C++例程这样用： char temp[256]; int len=0; memset(temp, 0, 256); ftGetSnapedImagePath(camIndex, temp, len); 改成VB后就出错了

[Tiger_Zhao]

Private Declare Function ftGetSnapedImagePath Lib "FTDetectUCamera.dll" ( _
        ByVal chn As Long, _
        ByRef outPath As Byte, _
        ByRef outLen As Long _
        ) As Long

Dim ret             As Long
Dim camIndex        As Long
Dim outPath(255)    As Byte
Dim outLen          As Long
Dim imgPath         As String
ret = ftGetSnapedImagePath(camIndex, outPath(0), outLen)

[美薇]

不停地翻资料，谢了！

[舉杯邀明月]

我觉得应该是赵老虎那样的声明可以用。