新手求解3×2矩阵转置为2×3矩阵

[yukcheon]

package com.matrix;

//import com.sun.java_cup.internal.runtime.Scanner;
import java.util.*;

public class MatrixTest {
	public static void main(String[] args) {
		final int ROW = 3;
		final int COLUMN = 2;
		Scanner in = new Scanner(System.in);
		System.out.println("Plz enter two matrices: \n");
		
		int[][] ma = new int[ROW][COLUMN];
		int[][] mb = new int[ROW][COLUMN];
		int[][] md = new int[COLUMN][ROW];
		
		System.out.println("Enter a 3 × 2 matrix: ");
		for (int i = 0; i < ROW; i++) {
			for (int j = 0; j < COLUMN; j++) {
				ma[i][j] = in.nextInt(); // fills in ma
			}
		}
		
		System.out.println("Enter another 3 × 2 matrix: ");
		for (int i = 0; i < ROW; i++) {
			for (int j = 0; j < COLUMN; j++) {
				mb[i][j] = in.nextInt(); // fills in mb
			}
		}
		
		System.out.println("First PLUS second equals to: ");
		for (int i = 0; i < ROW; i++) {
			for (int j = 0; j < COLUMN; j++) {
				mb[i][j] += ma[i][j];
				System.out.print("\t" + mb[i][j]);
			}
			System.out.print("\n");
		}
		
		// give md transposed by ma
		for (int i = 0; i < ma.length; i++) {  // a row's length
			for (int j = 0; j < ma[0].length; j++) {  // a column's length
				md[j][i] = ma[i][j];
			}
		}
		
		System.out.println("md is transposed by ma, which is: ");
		for (int i = 0; i < ma[0].length; i++) {
			for (int j = 0; j < ma.length; j++) {
				System.out.print("\t" + md[i][j]);
			}
			System.out.print("\n");
		}
	}
}

代码如上所示，求解 3×2 矩阵转置为 2×3 矩阵，我的写法输出的一直是

1 3 5
2 4 6

不知如何修改才能输出为

1 2 3
4 5 6

诚心求解答，感谢 :-)

[suking163]

首先，lz你这是一个3行2列的数组，一次输入123456之后得到的数组结构应该是这样的 1 2 3 4 5 6 经过你的3×2 矩阵转置为 2×3 矩阵 就变成 1 3 5 2 4 6 相当于左下角跟右上角位置对调，这样的对调是没法变成你要求的 数组 1 2 3 4 5 6 如果想变成你要求的这样就需要再输入的时候改变一下

                System.out.println("Enter a 3 × 2 matrix: ");
		for (int i = 0; i < COLUMN; i++) {
			for (int j = 0; j < ROW; j++) {
				ma[j][i] = in.nextInt(); // fills in ma
			}
		}

这样应该就能得到你想要的结果了