sql查询一个表内包含某个字段值对应的三个字段的所有数据

[Carrie_spinfo]

如下图，ID列指定的值对应的其他三个列相同的值包含的其他ID列全部显示

如何实现？

[卖水果的net]

select * from t where source in (select source from t where id = 77)

[二月十六]

--测试数据
if not object_id(N'Tempdb..#T') is null
	drop table #T
Go
Create table #T([starttime] time,[score] int,[id] int,[endtime] time)
Insert #T
select '11:12:02',5345,60,'11:34:54' union all
select '11:12:02',5345,61,'11:34:54' union all
select '11:12:02',5345,77,'11:34:54' union all
select '11:10:02',320,77,'11:33:47' union all
select '11:10:02',320,26,'11:33:47' union all
select '11:12:02',535,10,'11:34:54'
Go
--测试数据结束
SELECT  a.*
FROM    #T a
        JOIN ( SELECT DISTINCT
                        starttime ,
                        score ,
                        endtime
               FROM     #T
               WHERE    id = 77
             ) b ON b.endtime = a.endtime
                    AND b.score = a.score
                    AND b.starttime = a.starttime

[qq_37013834]

select * from A where A.sour in( (select A.sour from Awhere A.UserId= 77))

[qq_37013834]

select * from A where A.socre in( (select A.socre from A where A.Id= 77)) SQL中直接用这个可以查询出来数据，看他们写的好复杂的样子