写一个正则，字符串去重的

[katakibb]

var zf=‘aodibaomabaoshijiebeijingqichebenchibentianbiaozhibiekebiyadichanganchangchengdaoqidazhongdongfengfengshendongfengfengxingdongfengxiaokangdongfengyulongnazhijiedongnanfeiyatefengtianfutefutianguangqichangfengguangqichuanqihafeihaimahanmahuachenjinbeihuachenzhonghuahuapuhuataihuizhongjianghuaijianglingqichejiebaojilijipukaidilakekelaisileleikesasileinuolianhualifanlingmulinianlinkenlufengluhumazidamgminioubaoougeqiruiqiruiruilinqiruiweilinqiyarichanrongweisanlingshangqitongyongwulingshuanglongsibalusikedaSmartwoerwoxiandaixiyatexuefolanxuetielongyingfeinidiyiqibentengyiqijilinyiqixiali’;

这是一个字符串 怎么用正则去重， 然后把获取到的字母改成大写

[yy406961]

var str = "adaaasfjjjbkk"; // 只保留第一次出现的重复串 console.log(str.replace(/(.).*(\1)/g,function($1,$2,$3){ // 第一个参数匹配整个匹配值，从第二个开始是匹配的子串 $1 = $2+$1.substring(1).replace(new RegExp($2,'g'),''); return $1; }));