HttpURLConnection是不是不能debug

[逗泥丸的平方]

是有什么特别要注意的地方吗.. 建立连接之后 ?

我发现一debug就会抛异常报已经连接了

[bobolnear]

代码贴出来看看

[逗泥丸的平方]

引用 1 楼 bobolnear 的回复:

代码贴出来看看

这有啥好贴的.. 贴了也用不了..... 就建立一个http连接 有输入流的就算

{

		String BOUNDARY = UUID.randomUUID().toString(); // 边界标识 随机生成
		String RequestURL = serverUrl + "scandir.php?path=" + path;
		System.out.println(RequestURL);
		try {
			URL url = new URL(RequestURL);
			HttpURLConnection conn = (HttpURLConnection) url.openConnection();
			conn.setReadTimeout(TIME_OUT);
			conn.setConnectTimeout(TIME_OUT);
			conn.setDoInput(true); // 允许输入流
			conn.setDoOutput(true); // 允许输出流
			conn.setUseCaches(false); // post不允许使用缓存
			conn.setRequestProperty("Charset", CHARSET); // 设置编码
			// conn.setRequestProperty("connection", "keep-alive");
			// conn.setRequestProperty("Content-Type", CONTENT_TYPE +
			// ";boundary=" + BOUNDARY);
			BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream(), "utf-8"));
			String readLine = "";
			StringBuilder sb = new StringBuilder();
			while ((readLine = br.readLine()) != null) {
				sb.append(readLine);
			}
			/**
			 * 获取响应码 200=成功 当响应成功，获取响应的流
			 */
			int res = conn.getResponseCode();

			System.out.println(conn.getResponseMessage());

			System.out.println(sb.toString());
			System.out.println(res);
			return sb.toString();
		} catch (IOException e) {
			e.printStackTrace();
		}
		return "";
	}