这种json样式的菜单，怎么获取它然后禁用

[大橘子呀]

/*菜单json*/
	var menu = [{"id":"1","name":"主菜单","parentId":"0","url":"","icon":"","order":"1","isHeader":"1","childMenus":[
					{"id":"2","name":"用户管理","parentId":"1","url":"","icon":"","order":"1","isHeader":"0","childMenus":[
						{"id":"3","name":"管理用户","parentId":"3","url":"test1.html","icon":"","order":"1","isHeader":"0","childMenus":""},
						{"id":"4","name":"权限管理","parentId":"3","url":"mamanger.jsp","icon":"","order":"1","isHeader":"0","childMenus":""}
					]},
					{"id":"5","name":"村务管理","parentId":"1","url":"","icon":"","order":"1","isHeader":"0","childMenus":[
						{"id":"6","name":"管理用户","parentId":"3","url":"test1.html","icon":"","order":"1","isHeader":"0","childMenus":""},
						{"id":"7","name":"权限管理","parentId":"3","url":"test2.html","icon":"","order":"1","isHeader":"0","childMenus":""}
					]},
				]},

生成的菜单是这样的，如果要在界面上禁用某一个菜单怎么实现

[Go 旅城通票]

改菜单js类库罗，如果menu数据项有disabled配置什么的就不给菜单添加相关的处理事件 或者直接修改json，删除不显示显示的节点项目

[灿尔哈擦苏]

不加事件不就好了

[Msxindl_Com]

可以取消该菜单的 hover 和 onclick 事件，也可以设置成 disabled 或者干脆不加载这个菜单，或者设置 display:none 等等

[happy002]

看js类库怎么写的呗