#include<iostream>
using namespace std;
class A
{
public:
A()
{
cout<<"constructing A"<<endl;
}
~A()
{
cout<<"destructing A"<<endl;
}
};

class B:public A
{
public:
B()
{
cout<<"constructing B"<<endl;
}
~B()
{
cout<<"destructing B"<<endl;
}
};

class C:public B
{
public:
C()
{
cout<<"constructing C"<<endl;
}
~C()
{
cout<<"destructing C"<<endl;
}
};

int main()
{
C c1;
system("pause");
return 0;
}


编译器不显示析构函数，但我感觉是执行了的，请问为什么会这样?

修改代码后如下：
#include<iostream>
using namespace std;
class A
{
public:
A()
{
cout<<"constructing A"<<endl;
}
~A()
{
cout<<"destructing A"<<endl;
}
};

class B:public A
{
public:
B()
{
cout<<"constructing B"<<endl;
}
~B()
{
cout<<"destructing B"<<endl;
}
};

class C:public B
{
public:
C()
{
cout<<"constructing C"<<endl;
}
~C()
{
cout<<"destructing C"<<endl;
}
};

void end_pause()
{
system("pause");
}

int main()
{
atexit(end_pause);
C c1;
return 0;
}

此时编译器显示析构函数，请问这次为什么能显示?
谢谢各位解答的大兄弟了