求助！！！！一个list解析问题！！！

[勿念先生]

public class Test4 { public static void main(String[] args){ /* * 初始的数据结构List<Map<String, List<Map<String, Object>>>> * 目的：将list里面的list中的每个map每个字段一一对应的相加变成这样的数据结构：Map<String, List<Map<String, Object>>> * 去掉最外层的list * 例如: * [ * {resultList=[{number3=3, number2=2, number1=1}, {number3=6, number2=5, number1=4}, {number3=9, number2=8, number1=7}]}, * {resultList=[{number3=3, number2=2, number1=1}, {number3=6, number2=5, number1=4}, {number3=9, number2=8, number1=7}]}, * {resultList=[{number3=3, number2=2, number1=1}, {number3=6, number2=5, number1=4}, {number3=9, number2=8, number1=7}]} * ] * 变成 * {resultList=[{number3=9, number2=8, number1=3}, {number3=18, number2=15, number1=12}, {number3=27, number2=24, number1=21}]}

[勿念先生]

发帖子时候过长一直报null，这bug不修复吗？？？？

[勿念先生]

就是一个这样的list求怎么解析成我想要的，去掉最外层的list。 public class Test4 { public static void main(String[] args){ /* * 初始的数据结构List<Map<String, List<Map<String, Object>>>> * 目的：将list里面的list中的每个map每个字段一一对应的相加变成这样的数据结构：Map<String, List<Map<String, Object>>> * 去掉最外层的list * 例如: * [ * {resultList=[{number3=3, number2=2, number1=1}, {number3=6, number2=5, number1=4}, {number3=9, number2=8, number1=7}]}, * {resultList=[{number3=3, number2=2, number1=1}, {number3=6, number2=5, number1=4}, {number3=9, number2=8, number1=7}]}, * {resultList=[{number3=3, number2=2, number1=1}, {number3=6, number2=5, number1=4}, {number3=9, number2=8, number1=7}]} * ] * 变成 * {resultList=[{number3=9, number2=8, number1=3}, {number3=18, number2=15, number1=12}, {number3=27, number2=24, number1=21}]} * */ List<Map<String, Object>> list1 = new ArrayList<Map<String, Object>>(); Map<String, Object> map1 = new HashMap<String, Object>(); Map<String, Object> map2 = new HashMap<String, Object>(); Map<String, Object> map3 = new HashMap<String, Object>(); List<Map<String, Object>> paramList1 = new ArrayList<Map<String, Object>>(); Map<String, Object> paramMap1 = new HashMap<String, Object>(); paramMap1.put("number1", 1); paramMap1.put("number2", 2); paramMap1.put("number3", 3); Map<String, Object> paramMap2 = new HashMap<String, Object>(); paramMap2.put("number1", 4); paramMap2.put("number2", 5); paramMap2.put("number3", 6); Map<String, Object> paramMap3 = new HashMap<String, Object>(); paramMap3.put("number1", 7); paramMap3.put("number2", 8); paramMap3.put("number3", 9); paramList1.add(paramMap1); paramList1.add(paramMap2); paramList1.add(paramMap3); map1.put("resultList", paramList1); map2.put("resultList", paramList1); map3.put("resultList", paramList1); list1.add(map1); list1.add(map2); list1.add(map3); System.out.println(list1.toString()); } }

[勿念先生]

终于解决了。。。。。。。

[ITjavaman]

System.out.println(so(list1).toString());


private static Map<String, List<Map<String, Object>>> so(List<Map<String, Object>> list1){
		int num1=0,num2=0,num3=0;
		Map<String, Object> map = new HashMap<String, Object>();
		List<Map<String, Object>> paramList = new ArrayList<Map<String, Object>>();
		Map<String, Object> paramMap = new HashMap<String, Object>();
		
		Map<String, List<Map<String, Object>>> resultMap = new HashMap<String, List<Map<String, Object>>>();
		List<Map<String, Object>> resultList = new ArrayList<Map<String, Object>>();
		Map<String,Object> mapModel =null;

		for(int i=0;i<list1.size();i++){
			map=(Map<String, Object>)list1.get(i);
			paramList=(List<Map<String, Object>>)map.get("resultList");
			for(int j=0;j<paramList.size();j++){
				paramMap=(Map<String, Object>)paramList.get(j);
				num1=num1+(Integer)paramMap.get("number1");
				num2=num2+(Integer)paramMap.get("number2");
				num3=num3+(Integer)paramMap.get("number3");
			}
			mapModel = new HashMap<String,Object>();
			
			mapModel.put("number1", num1);
			mapModel.put("number2", num2);
			mapModel.put("number3", num3);
			resultList.add(mapModel);

			num1=0;
			num2=0;
			num3=0;
		}
		resultMap.put("resultList", resultList);
		return resultMap;
	}

你要的？