countDownLatch.await(1, TimeUnit.SECONDS)的用法

[k10509806]

ExecutorService service = Executors.newFixedThreadPool(1);
                    
                    try
                    {
                       
                            
                            CountDownLatch countDownLatch = new CountDownLatch(1);
                            
                            // 执行
                            service.execute(new ApplyCallable(call, logisticsContext, response, countDownLatch));
                             
                            try
                            {
                                if(countDownLatch.await(1, TimeUnit.SECONDS))
                                {
                                    // 不超时
                                    return response;
                                }
                            }
                            catch (Exception e)
                            {
                                // ignore exception
                            }
                
                            // 来到这里表示超时
                            // throw new TimeoutException("send request timeout");
                            logger.error("######耗时申请跟踪号######", new String[][]{{"运输方式", transportationMode.getTransportationModeChinese()}});
                        
                            
                    }
                    finally
                    {
                        service.shutdown();
                    }

为什么超过1秒，这个service.shutdown了，里面的ApplyCallable还可以继续进行，没有关闭掉

[李德胜1995]

使用shutdownNow()试试。。。。

[k10509806]

还是不行，里面的ApplyCallable会继续进行。我的理想效果的是，超时了，里面的线程就不要继续进行了

[k10509806]

@Override
        public void run()
        {
            try
            {
                Thread.sleep(5 * 1000);
            }
            catch (InterruptedException e)
            {
                e.printStackTrace();
            }

            try
            {
                System.out.println("====继续进行======");
            }
            finally
            {
                countDownLatch.countDown();
            }

        }

java.lang.InterruptedException: sleep interrupted
	at java.lang.Thread.sleep(Native Method)
	at com.bessky.pss.portal.business.logistics.util.TrackNumberUtils$ApplyCallable.run(TrackNumberUtils.java:258)
	at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
	at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
	at java.lang.Thread.run(Thread.java:745)
[bessky_it][ERROR][2017-05-17 16:16:02] | PSS | ######耗时申请跟踪号###### | 运输方式=京华达香港平邮(华南快速小包平邮), | com.bessky.pss.portal.business.logistics.util.TrackNumberUtils.applyTrackingNumber(TrackNumberUtils.java:208) 
====继续进行======

[k10509806]

一直在调整代码中，重未成功

[OPPPPOP]

逻辑上应该是这样的 try { Thread.sleep(5 * 1000); countDownLatch.countDown(); } catch (InterruptedException e) { e.printStackTrace(); //interrupt 所以返回 return; } System.out.println("====继续进行======"); service.shutdown 改为 service.shutdownNow();