FragmentPagerAdapter 切换框架不刷新内容

[qq_37893573]

public class MyPagerAdapter extends FragmentPagerAdapter
    {
        private Fragment pageFragment;
        private int NUM_PAGES = 4;
        private final String[] Titles= new String[] {
                "待接单",
                "已接单",
                "配送中",
                "全部"};
        public MyPagerAdapter(FragmentManager fm) {
            super(fm);
        }
        @Override
        public Fragment getItem(int position) {
            switch (position){
                case 0:
                    pageFragment = new Frm1();
                    return pageFragment;
                case 1:
                    pageFragment = new Frm2();
                    return pageFragment;
                case 2:
                    pageFragment = new Frm3();
                    return pageFragment;
                case 3:
                    pageFragment = new Frm4();
                    return pageFragment;

                default:
                    return null;
            }
        }

        @Override
        public CharSequence getPageTitle(int position) {
            return Titles[position];
        }
        @Override
        public int getCount() {
            return NUM_PAGES;
        }
        @Override
        public int getItemPosition(Object object) {
            return POSITION_NONE;
        }

    }

网上看了许多方式仍旧不好使 请大神帮忙看看 目前 访问FRM1 FRM2 后 内容不更新但是 访问最后一个FRM4 返回到FRM1却发现更新了 很无语求解答

[lixuce1234]

你可以设置viewpager的预加载个数是4 就不会重新加载了 vp.setOffscreenPageLimit(4);貌似是这个方法 你看一下 应该对你有帮助

[qq_37893573]

private int NUM_PAGES = 4; 是 4啊 我是想让他重新加载 现在切换 数据更新后发现不变 我想让他实时更新和后端同步

[qq_37893573]

有没有大神啊

[qq_37893573]

 @Override
    public Object instantiateItem(ViewGroup container, int position) {
        if (mCurTransaction == null) {
            mCurTransaction = mFragmentManager.beginTransaction();
        }

        final long itemId = getItemId(position);

        // Do we already have this fragment?
        String name = makeFragmentName(container.getId(), itemId);
        Fragment fragment = mFragmentManager.findFragmentByTag(name);
        if (fragment != null) {
            if (DEBUG) Log.v(TAG, "Attaching item #" + itemId + ": f=" + fragment);
            mCurTransaction.attach(fragment);
        } else {
            fragment = getItem(position);
            if (DEBUG) Log.v(TAG, "Adding item #" + itemId + ": f=" + fragment);
            mCurTransaction.add(container.getId(), fragment,
                    makeFragmentName(container.getId(), itemId));
        }
        if (fragment != mCurrentPrimaryItem) {
            fragment.setMenuVisibility(false);
            fragment.setUserVisibleHint(false);
        }

        return fragment;
    }

查询百度 说是这段代码的问题具体怎么操作求解答啊