SQL 查询排序

t101lian 2017-06-01 05:24:45

现在有两列数据, oder by date 查询出来的结果如下
date, setnum
2017-05-27 14:27:07.813 1
2017-05-27 14:27:07.813 1
2017-05-27 14:27:07.813 1
2017-05-27 14:27:07.823 12
2017-05-27 14:27:07.823 12
2017-05-27 14:27:07.823 12
2017-05-27 14:27:07.830 23
2017-05-27 14:27:07.830 23
2017-05-27 14:27:07.830 23
2017-05-27 14:27:07.837 34
2017-05-27 14:27:07.837 34
2017-05-27 14:27:07.837 34
2017-05-27 14:27:07.847 36
2017-05-27 14:27:07.847 36
2017-05-27 14:27:07.847 36
2017-05-27 14:27:07.853 37
2017-05-27 14:27:07.853 37
2017-05-27 14:27:07.853 37
2017-05-27 14:27:07.860 38
2017-05-27 14:27:07.860 38
2017-05-27 14:27:07.860 38

------
因为setnum的顺序是乱的，现在想得到新的newnum ,结果如下

date, setnum , newnum
2017-05-27 14:27:07.813 1 1
2017-05-27 14:27:07.813 1 1
2017-05-27 14:27:07.813 1 1
2017-05-27 14:27:07.823 12 2
2017-05-27 14:27:07.823 12 2
2017-05-27 14:27:07.823 12 2
2017-05-27 14:27:07.830 23 3
2017-05-27 14:27:07.830 23 3
2017-05-27 14:27:07.830 23 3
2017-05-27 14:27:07.837 34 4
2017-05-27 14:27:07.837 34 4
2017-05-27 14:27:07.837 34 4
2017-05-27 14:27:07.847 36 5
2017-05-27 14:27:07.847 36 5
2017-05-27 14:27:07.847 36 5
..。。。。。。

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二月十六 2017-06-01

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--测试数据

if not object_id(N'Tempdb..#T') is null

	drop table #T

Go

 CREATE TABLE #T([date] DATETIME,setnum INT)

Insert #T

select '2017-05-27 14:27:07.813',1 union all

select '2017-05-27 14:27:07.813',1 union all

select '2017-05-27 14:27:07.813',1 union all

select '2017-05-27 14:27:07.823',12 union all

select '2017-05-27 14:27:07.823',12 union all

select '2017-05-27 14:27:07.823',12 union all

select '2017-05-27 14:27:07.830',23 union all

select '2017-05-27 14:27:07.830',23 union all

select '2017-05-27 14:27:07.830',23 union all

select '2017-05-27 14:27:07.837',34 union all

select '2017-05-27 14:27:07.837',34 union all

select '2017-05-27 14:27:07.837',34 union all

select '2017-05-27 14:27:07.847',36 union all

select '2017-05-27 14:27:07.847',36 union all

select '2017-05-27 14:27:07.847',36 union all

select '2017-05-27 14:27:07.853',37 union all

select '2017-05-27 14:27:07.853',37 union all

select '2017-05-27 14:27:07.853',37 union all

select '2017-05-27 14:27:07.860',38 union all

select '2017-05-27 14:27:07.860',38 union all

select '2017-05-27 14:27:07.860',38

Go

--测试数据结束

Select *,DENSE_RANK()OVER(ORDER BY setnum) AS newnum  from #T