Segmentation fault:段错误,检查是否有数组越界,指针异常,访问到不应该访问的内存区域 [问题点数:20分,结帖人miaoqiucheng]

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qsv + ffmpeg Segmentation fault (core dumped) 段错误
root@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# /cat /proc/cpuinfornrnprocessor : 7rnvendor_id : GenuineIntelrncpu family : 6rnmodel : 94rnmodel name : Intel(R) Core(TM) i7-6770HQ CPU @ 2.60GHzrnstepping : 3rnmicrocode : 0x8arncpu MHz : 1082.656rncache size : 6144 KBrnphysical id : 0rnsiblings : 8rncore id : 3rncpu cores : 4rnapicid : 7rninitial apicid : 7rnfpu : yesrnfpu_exception : yesrncpuid level : 22rnwp : yesrnflags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe syscall nx pdpe1gb rdtscp lm constant_tsc art arch_perfmon pebs bts rep_good nopl xtopology nonstop_tsc aperfmperf eagerfpu pni pclmulqdq dtes64 monitor ds_cpl vmx est tm2 ssse3 sdbg fma cx16 xtpr pdcm pcid sse4_1 sse4_2 x2apic movbe popcnt tsc_deadline_timer aes xsave avx f16c rdrand lahf_lm abm 3dnowprefetch epb intel_pt tpr_shadow vnmi flexpriority ept vpid fsgsbase tsc_adjust bmi1 hle avx2 smep bmi2 erms invpcid rtm mpx rdseed adx smap clflushopt xsaveopt xsavec xgetbv1 dtherm ida arat pln pts hwp hwp_notify hwp_act_window hwp_epprnbugs :rnbogomips : 5183.91rnclflush size : 64rncache_alignment : 64rnaddress sizes : 39 bits physical, 48 bits virtualrnpower management:rnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# uname -arnLinux mos 4.4.0-59-generic #80-Ubuntu SMP Fri Jan 6 17:47:47 UTC 2017 x86_64 x86_64 x86_64 GNU/Linuxrnrnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# ls /opt/intel/mediasdk/lib64/rniHD_drv_video.so libmfxhw64-p.so.1.19 libmfxhw64.so libmfxsw64-p.so.1.19 libmfxsw64.sornrnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# env |grep 'LIBVA'rnLIBVA_DRIVERS_PATH=/opt/intel/mediasdk/lib64rnLIBVA_DRIVER_NAME=iHDrnrnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# vainfornlibva info: VA-API version 0.99.0rnlibva info: va_getDriverName() returns 0rnlibva info: User requested driver 'iHD'rnlibva info: Trying to open /opt/intel/mediasdk/lib64/iHD_drv_video.sornlibva info: Found init function __vaDriverInit_0_32rnlibva info: va_openDriver() returns 0rnvainfo: VA-API version: 0.99 (libva 1.67.0.pre1)rnvainfo: Driver version: 16.5.55964-ubitrnvainfo: Supported profile and entrypointsrn VAProfileH264ConstrainedBaseline: VAEntrypointVLDrn VAProfileH264ConstrainedBaseline: VAEntrypointEncSlicern VAProfileH264ConstrainedBaseline: rn VAProfileH264ConstrainedBaseline: rn VAProfileH264Main : VAEntrypointVLDrn VAProfileH264Main : VAEntrypointEncSlicern VAProfileH264Main : rn VAProfileH264Main : rn VAProfileH264High : VAEntrypointVLDrn VAProfileH264High : VAEntrypointEncSlicern VAProfileH264High : rn VAProfileH264High : rn VAProfileMPEG2Simple : VAEntrypointEncSlicern VAProfileMPEG2Simple : VAEntrypointVLDrn VAProfileMPEG2Main : VAEntrypointEncSlicern VAProfileMPEG2Main : VAEntrypointVLDrn VAProfileVC1Advanced : VAEntrypointVLDrn VAProfileVC1Main : VAEntrypointVLDrn VAProfileVC1Simple : VAEntrypointVLDrn VAProfileJPEGBaseline : VAEntrypointVLDrn VAProfileJPEGBaseline : VAEntrypointEncPicturern VAProfileVP8Version0_3 : VAEntrypointEncSlicern VAProfileVP8Version0_3 : VAEntrypointVLDrn VAProfileVP8Version0_3 : rn VAProfileHEVCMain : VAEntrypointVLDrn VAProfileHEVCMain : VAEntrypointEncSlicern VAProfileVP9Profile0 : rn : VAEntrypointVideoProcrn VAProfileNone : VAEntrypointVideoProcrn VAProfileNone : rnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# lsmod |grep 'i915'rni915_bpo 1302528 4rnintel_ips 20480 1 i915_bporni2c_algo_bit 16384 1 i915_bporndrm_kms_helper 155648 1 i915_bporndrm 364544 5 i915_bpo,drm_kms_helperrnvideo 40960 1 i915_bpornrnrnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# ls -l /dev/dri/rn总用量 0rncrw-rw----+ 1 root video 226, 0 1月 18 18:18 card0rncrw-rw---- 1 root video 226, 64 1月 18 18:18 controlD64rncrw-rw----+ 1 root video 226, 128 1月 18 18:18 renderD128rnrnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# groupsrnroot videornrnrnrnrnrnrnrnroot@mos:~/mscore_src/extern/src/intel/MediaSamples_Linux_2017/samples/_bin/x64# ./sample_multi_transcode -i::h264 ../content/test_stream.264 -o::h264 test_out.h264 -hw rnMulti Transcoding Sample Version 7.0.16053497rnrnlibva info: VA-API version 0.99.0rnlibva info: va_getDriverName() returns 0rnlibva info: User requested driver 'iHD'rnlibva info: Trying to open /opt/intel/mediasdk/lib64/iHD_drv_video.sornlibva info: Found init function __vaDriverInit_0_32rnlibva info: va_openDriver() returns 0rnPipeline surfaces number (DecPool): 20rnrnReturn on error: error code -3, /home/lab_msdk/buildAgentDir/buildAgent_MediaSDK4/git/mdp_msdk-samples/samples/sample_multi_transcode/src/pipeline_transcode.cpp 2924rnrnrnReturn on error: error code -3, /home/lab_msdk/buildAgentDir/buildAgent_MediaSDK4/git/mdp_msdk-samples/samples/sample_multi_transcode/src/sample_multi_transcode.cpp 307rnrnrnrnrnrnroot@mos:~/mscore_src/extern/src/ffmpeg# /usr/local/bin/ffmpeg -hwaccel qsv -c:v h264_qsv -vsync 0 -i udp://224.2.2.2:9000 -look_ahead 0 -pix_fmt nv12 -c:v h264_qsv -c:a copy -b:v 2M -preset veryfast -f mpegts udp://127.0.0.1:10000 rnrnInput #0, mpegts, from 'udp://224.2.2.2:9000':rn Duration: N/A, start: 60850.147611, bitrate: N/Arn Program 1 rn Stream #0:0[0x1010]: Video: h264 (Main) ([27][0][0][0] / 0x001B), yuv420p(tv, bt709, top first), 720x576 [SAR 16:11 DAR 20:11], 25 fps, 50 tbr, 90k tbn, 50 tbcrn Stream #0:1[0x1011]: Audio: aac (LC) ([15][0][0][0] / 0x000F), 48000 Hz, stereo, fltp, 127 kb/srnlibva info: VA-API version 0.99.0rnlibva info: va_getDriverName() returns 0rnlibva info: User requested driver 'iHD'rnlibva info: Trying to open /opt/intel/mediasdk/lib64/iHD_drv_video.sornlibva info: Found init function __vaDriverInit_0_32rnlibva info: va_openDriver() returns 0rnSegmentation <em>fault</em> (core dumped)rnrn有人遇见过没有?rnrnrnroot@mos:/opt/intel/mediasdk/tools/metrics_monitor/sample# lsrnbuild.sh cttmetrics_sample.cpp metrics_monitor run.shrnroot@mos:/opt/intel/mediasdk/tools/metrics_monitor/sample# ./run.sh rnERROR: Failed to initialize metrics monitor, error code -10rnrnrnrn
segmentation fault
请问各位大牛,为什么我的代码运行后会出现这样的错误呢?rn我是在linux下编译运行的,用的是gcc编译rn这是我的代码:rn#include rn#include rn#include rnrn#define M 5rn#define K 4rn#define N 3rnint A[M][K],B[K][N],C[M][N];rnrnstruct myparrnrn int row;rn int line;rn;rnrnvoid* Times(struct mypar arg)rnrn //struct mypar * newpar = (struct mypar *)arg;rn int row,line;rn int i;rn row = arg.row;rn line = arg.line;rn C[row][line] = 0;rn for(i = 0;i < K;i++)rn C[row][line] += A[row][i]*B[i][line];rnrnrnvoid main()rnrn int i,j;rn for(i = 0;i < M;i++)rn for(j = 0;j < K;j++)rn scanf("%d",&A[i][j]);rn for(i = 0;i < K;i++)rn for(j = 0;j < N;j++)rn scanf("%d",&B[i][j]);rn pthread_t id[M][N];rn for(i = 0;i < M;i++)rn for(j = 0;j < N;j++)rn rn struct mypar par;rn par.row = i;rn par.line = j;rn pthread_create(&id[i][j],NULL,(void*)Times(par),NULL);rn rn for(i = 0;i < M;i++)rn for(j = 0;j < N;j++)rn pthread_join(id[i][j],NULL);rn for(i = 0;i < M;i++)rn for(j = 0;j < N;j++)rn rn if(j == N-1)rn printf("%d\n",C[i][j]);rn elsern printf("%d ",C[i][j]);rn rnrnrnrn我输入了rn1 1 1 1 rn1 1 1 1 rn1 1 1 1 rn1 1 1 1rn1 1 1 1 rnrn1 1 1rn1 1 1rn1 1 1rn1 1 1rn运行后就显示<em>段错误</em>了。
segmentation fault!!!
下面是我写的一个将一定长以内的十进制转换为十六进制的程序,基本的思想就是模拟手动转换的过程。不断地除以十六(下一次以商进行),得商和余数,把余数悉数存入一个数组,然后逆序输出。结果输出是正确的,可是在linux下运行最后报<em>segmentation</em> <em>fault</em>,在windows下运行显示结果后就似乎停不下了,而且CPU100%。尤其数很大的时候,似乎是动态内存处理的问题,可我就是看不出来问题在哪。哪位帮忙看看。谢谢。rnrn#include "iostream"rnusing namespace std;rnint residue(int *,char *,int,int);rnint main(void)rnrn int n,i,l=0,c,j;rn char **p;rn cin>>n;rn int *r=new int[n];rn p=new char *[n];rn for(i=0;i>p[i];rn rn for(i=0;i=0)//逆序输出rn rn if(r[c]<=16)?(l--,t):(l-=2,flag++,t*10+p[2]);//像173,前两位够除以16,就拿17除,这时下一步要处理的是2,从0开始计数就是第二位;像1525,前两位15不够,加上第三位2再除。这时下一步要处理的就是5,第三位。rn for(j=0;j
Segmentation fault
[size=10px] char *bufferA = (char*)malloc( 100* sizeof(char) );rn rnrn .......rnrn bufferA 被字符填充...略过rnrn .........rnrn [color=#FF0000]char *bufferB = (char*)malloc( 100* sizeof(char) );rn char *temp = (char*)malloc( 10 * sizeof(char) );rn strcpy(bufferB , bufferA ); rn sprintf(temp , "%d", 159);[/color]rnrn问题:出现Segmentation <em>fault</em>[/size]rn
Segmentation fault~~
~_~ 終於做好了我的my_printf, 但是當我在main裡這樣輸入的話 :rn#include rn#include "my_printf.h"rnrnint main()rnrn my_printf("%s\n", 'c');rn //printf("%s", 'c'); rn return (0);rnrnrn就 Segmentation <em>fault</em>,rn我知到%s对应的应该是个字组, 但是有什麽办法预防呢?
Segmentation Fault
#includern#includern#includern#includern#includernusing namespace std;rnrnstruct Listrnrn List *prev;rn List *next;rn string name;rn friend bool operator < (List a, List b)rn rn return a.name>n)rn rn map_m;rn map::iterator it;rn List *_l, *Head;rn Head = new List;rn _l = new List;rn _l->name = "Last";rn _l->next = NULL;rn _l->prev = Head;rn Head->next=_l;rn Head->name = "Head";rn for(int i=0; i>tmp;rn if(tmp == "new")rn rnrn cin>>tmp;rn List *_l_tmp;rn _l_tmp = new List;rn _l_tmp->name = tmp;rn rn rn _l_tmp->next = Head->next;rn _l_tmp->prev = Head;rn Head->next = _l_tmp;rn _l_tmp->next->prev = _l_tmp;rn _m.insert(map::value_type(_l_tmp->name, _l_tmp));rn rn else if(tmp == "reply")rn rn cin>>tmp;rn it = _m.find(tmp);rn rn List *Prev, *Next;rnrn rn Prev = it->second->prev;rn Next = it->second->next;rnrn if(Prev != NULL && Next != NULL)rn rn Prev->next = Next;rn Next->prev = Prev;rn rn rn it->second->next = Head->next;rn it->second->prev = Head;rn Head->next = it->second;rn it->second->next->prev = it->second;rn rn else if(tmp == "tag")rn rn cin>>tmp;rn it = _m.find(tmp);rn rn List *Prev, *Next;rn rn Prev = it->second->prev; rn Next = it->second->next;rn rn Prev->next = Next;rn Next->prev = Prev;rn rn it->second->next = it->second->prev = NULL;rn rnrn rn else if(tmp == "search")rn rn List *q;rn q = Head->next;rn int Sum=0;rn while(q->next != NULL)rn rn coutnext;rn rn cout<<
Segmentation fault???
在程序运行的时候,出现这种错误,什么意思。rn为什么在编译的时候没有出现??rn下面的程序为什么会出现这种错误。rnrn#include rnmain()rnrnchar string[100];rnint seconds=1000;rnchar *string_change;rnchar *string_last;rnrnsprintf(string,"%d",seconds);rnstring_change=&string[0];rnprintf("string_change is %s\n",string_change);rnstrcat(string_last,string_change); //程序走到这就出现 Segmentation <em>fault</em> 的错误。郁闷!!!rnprintf("string_last is %s\n",string_last); rnrnrnrn如上的错误<em>是否</em>可以避免,如何去做,真心求教!!!rn顺便说一下。我是用gcc去编译的。rn晕死。这种错误时常出现,我一直都没有将其解决。。。。rn每次运行的时候见到这几个字,都想把它给吃了。。。
Segmentation fault
#include rn#include rn#include rnvoid mythread(void) /* 定义新线程运行的函数 */rnrn int i,ret;rn ret = pthread_setcancelstate(PTHREAD_CANCEL_ENABLE, NULL); /* 设置线程的取消状态 */rn if(ret != 0)rn rn printf("Thread pthread_setcancelsate failed."); /* 如果取消状态未设置成功,打印错误信息 */rn exit(1);rn rn ret = pthread_setcanceltype(PTHREAD_CANCEL_DEFERRED, NULL); /* 设置线程的取消类型 */rn if(ret != 0)rn rn printf("Thread pthread_setcanceltype failed."); /* 如果取消类型未设置成功,打印错误信息 */rn exit(1);rn rn for(i=0; i); /* 终止当前线程 */rn所以thread_retult<em>指针</em>是有问题的!rnrn经过测试,进程是被正常取消的了,只要输出不是(char *)thread_result,都能正常输出。rnrn但是具体什么问题,如何解决并不知道!同时也不知道自己理解的对不对!本人纯菜鸟一枚,求大神指教!
指针越界访问数组越界访问有什么区别?
void main()rnrn int a[1];rn a[2] = 2; // ok!rn int* p = a;rn *(p+2) = 2; // error!rnrnrn为什么有这样的不同!rn
Linux 下 memcpy()有Segmentation fault
Linux 下, 如下的function call:rnrnAF1()rnrn my_structure span; /*define local variable in AF1*/rn rn 给span赋值rn ......rn ......rnrn memcpy(, &span, 3)rn .....rnrn return rnrnrn运行报告memcpy处有Segmentation, 而且是span地址越界,dump显示span地址已经不再User space。 各位高手能否给指点一二?rnrn多谢!rnrn
try catch 如何捕捉 Segmentation fault 异常????
[code=C/C++]rnint main(int argc,char *argv[])rnrn tryrn rn vector mv;rn signal(SIGSEGV,NULL);rn cout << mv[2] << endl;rn rn catch(char *str)rn rn rn rn catch(...)rn rn rn rn cout <<
内存访问错误造成Segmentation fault (SIGSEGV)
 linux下程序对SIGSEGV信号的默认处理方式是产生coredump并终止程序,可以参考man 7 signal Signal Value Action Comment ────────────────────────────────────────────────────────────────────── SIGHUP...
Segmentation fault问题
//c语言实现输入任意长度的字符串n#include n#include nint main (void )nnchar *string = NULL ,*temp = NULL;nchar ch;nint i;n//先将字符串初始化为空nstring = (char *)malloc(1);nstring[0] = '\0';n//len为实际长度(包括空字符)nint len = 1;nwhile ((ch = getchar())!= '\n')nn //申请一个新字符串n temp = (char *)malloc(len+1);n if (temp = NULL)n n printf("内存不足!");n free(string);n exit(0);n n i=0;n while (string[i] != '\0'&&i
QT mini2440 Segmentation fault
我将QT的程序移植到mini2440开发板上原来一直好好地,为什么突然提示我“Segmengtion <em>fault</em>”,有人遇到过吗?
segmentation fault,求高手!
这是服务器端的程序:rn[code=C/C++]rn#include rn#includern#includern#includern#includern#includern//#includern#includern#define PORT 8888rn#define BACKLOG 2rnvoid process_conn_server(int s);rnint main(int argc, char *argv[])rnrn int ss,sc;rn struct sockaddr_in server_addr;rn struct sockaddr_in client_addr;rn int err;rn pid_t pid;rn ss=socket(AF_INET,SOCK_STREAM,0);rn if(ss0);rn rn printf("yes yes");rn rn tmp=0;rn tmp=inet_pton(AF_INET,argv[1],&(server_addr.sin_addr));rnrn assert(tmp>0);rn rn printf("yes");rn rn connect(s,(struct sockaddr *)&server_addr,sizeof(struct sockaddr));rn process_conn_server(s);rn close(s);rn rnvoid process_conn_server(int s)rnrn ssize_t size=0;rn char buffer[1024];rn for(; ;)rn rn size=read(0,buffer,1024);rn if(size>0)rn rn write(s,buffer,size);rn size=read(s,buffer,1024);rn write(1,buffer,size);rn rn rnrnrn谢谢了。。。。rn[/code]
Segmentation fault (core dumped)
[code=c]#include rn#include rn//#include rn#include rnusing namespace std;rnstruct userdevicernrn /* data */rn string m_devicename;rn long m_deviced;rn int m_devicePopedom;rn;rnrntypedef multimap USERTABLE;rntypedef USERTABLE::const_iterator CIT;rntypedef pair Range;rnint main()rnrn CIT it;rnuserdevice d1,d2,d3,d4;rnd1.m_devicename="d1";rnd1.m_deviced=12341234;rnd1.m_devicePopedom=123;rnrnd2.m_devicename="d2";rnd2.m_deviced=23622344;rnd2.m_devicePopedom=234;rnrnrnd3.m_devicename="d3";rnd3.m_deviced=23451234;rnd3.m_devicePopedom=345;rnrnrnd4.m_devicename="d4";rnd4.m_deviced=43622344;rnd4.m_devicePopedom=456;rnrnUSERTABLE m_user;rnm_user.insert(pair ("zhangsanfeng",d1));rnm_user.insert(pair ("zhangsanfeng",d2));rnm_user.insert(pair ("zhangsanfeng",d3));rnm_user.insert(pair ("zhangsanfeng",d4));rnrnRange range=m_user.equal_range("zhangsanfeng");rncout<<<<<;就是这句,但是不知道为什么会出错啊,求高手指点啊
fgets()错误:Segmentation fault
用C编了一个小的程序,运行环境是linux。编译通过,但在运行的时候出现Segmentation <em>fault</em>!rnrnvoid do_more(FILE *fp)rnrnchar line[NUM];rnwhile(fgets(line, NUM, fp))rnrn……rnrnrnrn通过调试问题应该是出现在 fgets(line, NUM, fp); 这一句。rnrn调试中发现,循环中如果第一次执行这条语句没问题,rn但是到了第二次执行这条语句的时候程序就跳出来了,并输出Segmentation <em>fault</em> 。rnrn网上找到的可能原因是:1,<em>数组越界</em>.2,<em>访问</em>空,野<em>指针</em>或未被初始化的<em>指针</em>.rn可是问题还是不知道怎么解决,希望各位大大给帮帮忙!!
线程报错,Segmentation fault
void CDataOpEngine::run(void)rn LOG4CXX_DEBUG(logger, "CDataOpEngine::run(void) in!");rn CJob* job;rn CExtCmd* pEC;rn CJobParam *param;rn while(1)rn pEC=this->coServer->popExtCmf();rnrnrn if(!pEC)rn LOG4CXX_DEBUG(logger, "pEC is null");rn continue;rn rn if(!pEC->content)rn LOG4CXX_DEBUG(logger, "pEC->content is null");rn continue;rn rnrn param =new CJobParam();rnrn param->data.ec=pEC;rnrn param->svr.pComSvr=this->coServer;rn LOG4CXX_DEBUG(logger, "CDataOpEngine::run(void) in!37-3");rn char cmdType=pEC->content[5];rn LOG4CXX_DEBUG(logger, "CDataOpEngine::run(void) in!43");rnrn if(cmdType =='0')rnrn job=new CComSvrLoginJob();rn rn else if(cmdType=='1')rnrn job=new CComSvrLogoutJob();rn rn elsernrn job=new CComSvrECOpJob();rnrn rn job->param=param;rnrn pool->addJob(job);rn rn cout<<content[5]; 这一句时,时不时的报“Segmentation <em>fault</em>“错误,然后程序就停止了,请大家给分析一下原因,谢谢rn
数据结构-队列,Segmentation fault
#includern#includern#define SIZE 13rntypedef structrn int *base;rn int front;rn int rear;rn SqQueue;rnint InitQueue(SqQueue Q)rn Q.base=(int *)malloc(sizeof(int)*SIZE);rn if(!Q.base)exit(0);rn Q.front=Q.rear=0;rn return 1;rnrnint QueueLength(SqQueue Q)rn if(Q.rear=Q.front)exit(0);rn printf("The Length of Queue is %d\n",(Q.rear-Q.front+SIZE)%SIZE);rnrnvoid EnQueue(SqQueue Q,int e)rn if(((Q.rear+1)%SIZE)==Q.front)rn printf("full\n");rn exit(0);rn rn Q.base[Q.rear]=e;rn Q.rear=(Q.rear+1)%SIZE;rnrnvoid DeQueue(SqQueue Q,int e)rn if(Q.rear=Q.front)rn printf("empty\n");rn rn e=Q.base[Q.front];rn Q.front++;rnrnvoid Show(SqQueue Q,int i)rn printf("Num.%d is %d\n",i,Q.base[i]);rnrnint DestoryQueue(SqQueue Q)rn free(Q.base);rn Q.front=Q.rear=0;rn return 1;rnrnmain()rnrn int i,e;rn SqQueue Q;rn InitQueue(Q);rn for(i=0;i
segmentation fault 的错误
编程中,遇到以下错误:程序的结构是这样的rn调用一个文件分割的函数split()rnwhile()rn ...rnrn循环只执行了一次,就出现<em>segmentation</em> <em>fault</em>的错误。rn但是,如果程序结构是:rnwhile()rn split() rn ....rnrn则程序在执行了若干次以后才出现此错误。rn请教各位,这是什么原因呢?急!在线等!rnrnrn
segmentation fault”求助
[img=https://img-bbs.csdn.net/upload/201807/31/1532970815_229897.jpg][/img]rn通过以上程序,我希望算出输入的整数的和并输出。rn[img=https://img-bbs.csdn.net/upload/201807/31/1532970656_692431.jpg][/img]rn但输入2 3 7 8时,出现一个错误“<em>segmentation</em> <em>fault</em>”,我查了一下,得知该错误是由于我<em>访问</em>了不该<em>访问</em>的内存导致的,但是仍旧不太明白,请问这个错误具体在以上程序中是怎么回事呢?
linux下segmentation fault
写了一个练习题,是n皇后问题,但是只要当n>=4时就会报错,不知是什么问题rn[code=c]rn#includern#includernusing namespace std;rn int n;rn int* arr;rn int sum=0;rn bool place(int m)rn rn for(int i=0;i>n;rn arr=new int(n);//下标为第几个,值为横轴rn traceback(0);rn cout<
51904 Segmentation fault
51904 Segmentation <em>fault</em> 请问高手怎么解决
segmentation fault(core dumped)
在运行自己的程序时出现<em>段错误</em>rn(gdb) runrnStarting program: /home/user/contiki/myexamples/RSA/rsa_test rn[Thread debugging using libthread_db enabled]rnUsing host libthread_db library "/lib/i386-linux-gnu/libthread_db.so.1".rnrnProgram received signal SIGSEGV, Segmentation <em>fault</em>.rn0x080487fc in rsatest ()rnrn我的程序如下:rn#include "relic.h"rn#include "relic_cp.h"rn#include "relic_test.h"rn#include rnrnint rsatest() rn int code = STS_ERR;rn rsa_t pub,prv;rn uint8_t in[10],out[BN_BITS / 8 +1],h[MD_LEN];rn int il,ol;rn int result;rnrn rsa_null(pub);rn rsa_null(prv);rnrn TRY rn rsa_new(pub);rn rsa_new(prv);rnrn result = cp_rsa_gen(pub,prv,BN_BITS);rnrn TEST_BEGIN("rsa encryption/decryption is correct") rn TEST_ASSERT(result == STS_OK,end);rn il = 10;rn ol = BN_BITS / 8 + 1;rn rand_bytes(in,il);rn TEST_ASSERT(cp_rsa_enc(out,&ol,in,il,pub) == STS_OK,end);rn TEST_ASSERT(cp_rsa_dec(out,&ol,out,ol,prv) == STS_OK,end);rn TEST_ASSERT(memcmp(in,out,ol) == 0,end);rn TEST_END;rn CATCH_ANY rn ERROR(end);rn rn code = STS_OK;rnrn end:rn rsa_free(pub);rn rsa_free(prv);rn return code;rnrnrnint main() rn int flag = STS_ERR;rn flag = rsatest();rn if(flag) rn printf("Done!");rn rn return 0;rnrnrnrnrnrn
奇怪的segmentation fault 错误!!!!!!!!!!!!!!
下面这段代码在tc2.0下编译运行,结果正确。但在redhat9.0下用gcc编译通过,运行时出现rn<em>segmentation</em> <em>fault</em> 错误,怎么回事????gcc编译器<em>检查</em>如此严格?????rnrnrnrn#include rnrn int main()rn rn char *s="Golden Global View";rn char d[20];rn rn //clrscr();rn rn //strcpy(d,s);rn //printf("%s",d);rn rn memset(s,'w',4);rn printf("%s",s);rn rn rnrn getchar();rn return 0;rn
Segmentation fault 郁闷
以下程序是用mysql c api计算t_flow_data表项的记录数:rn编译命令行如下:rngcc -I /usr/local/mysql/include/mysql -c connect_database.crngcc -L /usr/local/mysql/lib/mysql/ -lmysqlclient -lm -o connect_database connernct_database.ornrn执行时,结果正确选择出来了,但是出现Segmentation <em>fault</em>:rnrnConnect SuccrnThe result is 4999999rnSegmentation <em>fault</em>rnrn到底是怎么回事啊?rnrn#include rn#include rn#include "/usr/local/mysql/include/mysql/mysql.h"rn#include "configuration.inc.h"rn/*rn* 函数介绍:该函数负责数据库的连接rn* 输入参数:rn* 输出参数:rn* 返回值 :成功时返回连接标识,否则返回NULLrn* 全局变量:rn* 调用模块:rn* 抛出<em>异常</em>:错误时输出错误信息rn*/rnint Connect_DataBase(MYSQL *db_connect)rnrn mysql_init(db_connect);rnrn if (!mysql_real_connect(db_connect , HOST , DBUSER , DBPASSWD , DBNAME , 0 , rnNULL ,0))rn rn fprintf(stderr , "Failed to Connect DataBase , Error:%s\n" , mysql_error(db_rnconnect));rn return 0;rn rn elsern return 1;rnrnrnint main()rnrn MYSQL *mysql;rn MYSQL_RES *mysql_store;rn MYSQL_ROW row;rn rn if (Connect_DataBase(mysql))/* Connect DataBase*/rn rn printf("Connect Succ\n");rn rn else rn exit(-1);rn rn mysql_query(mysql , "select count(*) from t_flow_data");rn rn mysql_store = mysql_store_result(mysql);rn rn row = mysql_fetch_row(mysql_store);rnrn printf("The result is %s\n" , row[0]);rn rn mysql_free_result(mysql_store);rn mysql_close(mysql);rn rn return 1;rnrn
结构体数组的segmentation fault
rntypedef structrn int hisgram;rn int z_end;rnDistribution;rnrn rnint main(void)rn rn rn rn double dz=0.0001;//the segments distance of z axisrn rn int dimen=int((125)/dz);// the number of segments divided in z axisrn cout<
求助:Segmentation Fault
[code=C/C++]rn#include rnrnrnint search(char* input,char* pattern);rnvoid main(int argc,char* argv);rn char * line;rn int position=0 ;rn if (argc!=2) rn printf("Please enter Pattern");rn rn rn scanf("%s",line); rn if(position = search(line,++argv))rn printf ("Position = %d",position);rn rn rnrnrnrnint search(char* input ,char* pattern)rn int position=0;rn while(*input++ != *pattern)rn position++;rn while(*input++ = *pattern++)rn if (*pattern='\0')rn return position;rn rn return 0;rnrnrn[/code]rnrnrn运行结果是<em>segmentation</em> <em>fault</em>, 为神马啊????
关于动态链接库 segmentation fault
我将多个cpp文件编译成o文件,命令如下:rnrng++ -fPIC -c c1.cpprng++ -fPIC -c c2.cpprng++ -fPIC -c c3.cpprnrn然后将多个o文件, 链接成动态链接库 so 文件,命令如下:rnrng++ -shared c1.o c2.o c3.o -o SocketExt.sornrn结果,测试时,发现只要是调用了跨文件的函数,就会报错:rnrn<em>segmentation</em> <em>fault</em>rnrn请问,如何解决呢?
为什么Segmentation fault呢?
这个程序老是报错,说“Segmentation <em>fault</em>”;知道是server.c的18行错了,但不会改啊,请各位大哥指教指教~~~rn代码如下:rnserver.crnrn#include "cliserv.h"rnint main(int argc,char* argv[])rnrnint server_fifo_fd,client_fifo_fd;rnstruct data_to_pass my_data;rnint nbytes;rnchar client_fifo_name[256];rnchar *tmp_char_ptr;rnrnmkfifo(SERVER_FIFO_NAME,0777);rnserver_fifo_fd=open(SERVER_FIFO_NAME,O_RDONLY);rnif(server_fifo_fd==-1)rnerr_exit("Server fifo failure");rnprintf("server_fifo_fd = %d\n",server_fifo_fd);rnrn/*sleep(10);*/rndornnbytes=read(server_fifo_fd,&my_data,sizeof(my_data));rnprintf("read %d bytes",nbytes);rnif(nbytes>0)rnrntmp_char_ptr=my_data.text_data;rnprintf("read %s\n",*tmp_char_ptr);rnwhile(*tmp_char_ptr)rnrn*tmp_char_ptr=toupper(*tmp_char_ptr);rnprintf("ok:recive %s\n",*tmp_char_ptr);rntmp_char_ptr++;rnrnsprintf(client_fifo_name,CLIENT_FIFO_NAME,my_data.client_pid);rnclient_fifo_fd=open(client_fifo_name,O_WRONLY);rnif(client_fifo_fd!=-1)rnrnwrite(client_fifo_fd,&my_data,sizeof(my_data));rnclose(client_fifo_fd); rn rn rnrnwhile(nbytes>0);rnclose(server_fifo_fd);rnunlink(SERVER_FIFO_NAME);rnreturn 0;rnrnrnclient.crnrn#include "cliserv.h"rnint main()rnrnint server_fifo_fd,client_fifo_fd;rnstruct data_to_pass my_request;rnint times_to_send;rnchar client_fifo_name[256];rnpid_t mypid;rnrnserver_fifo_fd=open(SERVER_FIFO_NAME,O_WRONLY);rnprintf("the server_fifo_fd = %d\n",server_fifo_fd);rnif(server_fifo_fd==-1)rnerr_exit("sorry,no server");rnrnmypid=getpid();rnsprintf(client_fifo_name,CLIENT_FIFO_NAME,mypid);rnif (mkfifo(client_fifo_name,0777)==-1)rnrnerr_exit(client_fifo_name);rnrnrnfor(times_to_send=0;times_to_send0)rnrnprintf("%d received:%s\n",mypid,my_request.text_data);rnrnclose(client_fifo_fd);rnrn rnclose(server_fifo_fd);rnunlink(client_fifo_name);/*注意*/rnexit(EXIT_SUCCESS);rnrnrnclserv.hrnrn#include rn#include rn#include rn#include rn#include rn#include rn#include rn#include rn#include rn#include "err_exit.h"rnrn#define SERVER_FIFO_NAME "/tmp/serv_fifo"rn#define CLIENT_FIFO_NAME "/tmp/client_%d_fifo"rn#define BUFFER_SIZE 80rnstruct data_to_passrnrnpid_t client_pid;rnchar text_data[BUFFER_SIZE-1];rn;rnrnrnerr_exit.hrn#include rn#include rn#define err_exit(MESSAGE)(perror(MESSAGE),exit(1))rn#include rnpid_t getpid(void);rnpid_t getppid(void);rn#include rnpid_t fork(void);rnrn
segmentation fault :11错误
用Mac,C语言写作业,在Xcode里面可以良好运行在terminal里面缺会出错不知道为什么,而且安装之后总是不能使用gdb所以也不知道怎么找到出错的语句,本人纯小白希望各位大大能帮助我一下。。。rn[code=c]rnrn#include rn#include rn#include rn#include rn#include rn#include rnrnchar s1[]="1";rnchar s2[]="1";rnrnrnint main(int argc, const char * argv[])rnrn char buf1[256],a[256]=0,b[256],c[256];rn rn int p1[2],p2[2],p3[2],p4[2];rn int parentw1,parentw2, child1r,child2r,parentr1,parentr2,child1w,child2w,pid;rn pipe(p1);rn pipe(p2);rn pipe(p3);rn pipe(p4);rn child1r=p1[0];rn child2r=p2[0];rn parentw1=p1[1];rn parentw2=p2[1];rn rn parentr1=p3[0];rn parentr2=p4[0];rn child1w=p3[1];rn child2w=p4[1];rn rn if (fork()==0) rn /*first child process--adder*/rn pid=getpid();rn FILE *fd;rn char s[]="stopstop";rn close(parentw2);close(parentw1);close(parentr1);close(parentr2);close(child2r);close(child2w);rn int f;rn rn int i=0;rn rn int sum=0;rn rn int k[1024];rn rn while (1) rn read(child1r, buf1, sizeof(b)); //get the number of fieldrn rn f=atoi(buf1);rn read(child1r, buf1, sizeof(b)); //get the name of filern rn sscanf(buf1, "%s",a);rn rn rn if (strcmp(a,s)==0) //compare to find wether the file name is stopstop if it is ,then break and teminatern rn break;rn rn rn fd=fopen(a, "r");rn while (!feof(fd)) rn fscanf(fd, "%d",&k[i]); //get all the numbers in the file then calculate the modrn i++;rn rn for (int i=1; i,sum);rn write(child1w, s1, sizeof(s1));rn rn // write(childw1, s1, sizeof(s1));rn rn exit(1);rn rn rn elsern rn if (fork()==0) rn /*second child process--factorial*/rn pid=getpid();rn rn int x,fac;rn int f ;rn int k = 0;rn rn close(parentw1);close(parentw2);close(parentr2);close(parentr1);close(child1r);close(child1w);rn while (1) rn read(child2r, buf1, sizeof(b));rn rn rn f=atoi(buf1);rn rn read(child2r, buf1, sizeof(b));rn rn x=atoi(buf1);rn rn rn rn if (f==0) rn break;rn rn k=x;rn for (int i=1; i
setjmp SEGMENTATION FAULT 错误。
linux环境下,程序中调用setjmp。运行此程序,出现Segmentation <em>fault</em> 错误,rn删掉setjmp调用程序运行正常。rn换成sigsetjmp()也出现同样错误。rnrn而且我已经把 setjmp函数放在最靠近main()入口的地方了,还是出错。rn其他小程序:调用setjmp的都运行正常。rnrn查了网上的资料,有说这个bug的。但是我也没给返回值赋值。rnThis is a very common bug with setjmp() and longjmp() -- to use them properly, you CANNOT RETURN FROM THE PROCEDURE THAT CALLS setjmp(). rnrnURL:http://www.cs.utk.edu/~plank/plank/classes/cs360/360/notes/Setjmp/lecture.html
关于segmentation fault的问题
本程序意在实现一个扫描软件rn现在的问题是用gdb调试,一旦退出这个函数就发生<em>segmentation</em> error,怀疑发生了栈溢出,但是觉得不太可能)rn原函数大致是这样的(被main调用)rnextern Option o;rnint PTM_main(int argc, char *argv[])rn rn char *p;rn char *host_spec;rn int i, arg;rn int num_host_exp_groups = 0;rn int numhosts_scanned = 0;rn int numhosts_up = 0;rn char *normalfilename = NULL;rn char **host_exp_group;rn struct scan_lists *ports = NULL;rn time_t timep;rn char mytime[128];rn HostGroupState *hstate;rn Target *currenths;rn。。。。。rn host_exp_group = (char **) safe_malloc(o.host_group_sz * sizeof(char *));rn rn while(1)rn while(num_host_exp_groups < o.host_group_sz &&rn (host_spec = grab_next_host_spec(argc, argv))) rn host_exp_group[num_host_exp_groups++] = strdup(host_spec);rn rn if (num_host_exp_groups == 0)rn break;rn hstate = new HostGroupState(o.host_group_sz,0,host_exp_group, num_host_exp_groups);rn //========================================================================== rn while(currenths = nexthost(hstate, &(o.pingtype))) rn numhosts_scanned++; rn rn if (currenths->flags & HOST_UP ) rn numhosts_up++;rnrn delete currenths;rn rn //=========================================================================rn rnrn delete hstate;rn // Free my host expressions rn for(i=0; i < num_host_exp_groups; i++)rn free(host_exp_group[i]);rn num_host_exp_groups = 0;rn rn rn free(host_exp_group);rn return 0rnrnrn只要把中间==中间这段删掉就没问题了,但是实在没想通为什么不在==里面就发生错误,而要到return以后才出问题,请高手帮忙
Segmentation fault错误
[code=C/C++]rn#include rn#include rn#include rn#include rn#include rn#include rnrnint main()rnrn struct DIR *dp;rn struct dirent *temp_dp;rn char temp_name[NAME_MAX+1];rn struct stat temp_stat;rn int temp_fd;rnrn dp=opendir("/dev/");rn if(dp==NULL)rn fprintf(stderr,"open /dev/ dir error");rn exit(0);rn rn strcpy(temp_name,"/dev/");rn rn while((temp_dp=readdir(dp))!=NULL)rn strncpy(temp_name+sizeof("/dev/")-1,rn temp_dp->d_name,NAME_MAX);rn if(strcmp(temp_name,"/dev/.")==0 || strcmp(temp_name,rn "/dev/..")==0)rn continue;rn if((temp_fd=open(temp_name,O_RDONLY)));rn rn close(temp_fd);rn rnrnrn[/code]rn怎么输出Segmentation <em>fault</em>错误?
Android sqlite3 Segmentation fault
请问各位在adb shell 中输入sqlite3 报Segmentation <em>fault</em>错误怎么解决,谢谢各位
segmentation fault错误求解
程序运行时碰到了<em>segmentation</em> <em>fault</em>,程序的大体意思是,当接收到客户端发送来的'S'字符时,启动另外一个线程来发送58张图片,send_data函数在前17次接收到'S'字符发送图片时不会出问题,但到第18次发送第33张图片时会出现<em>segmentation</em> <em>fault</em>错误,多次测试都是第18次发送第33张图片时出现问题,请大家帮帮忙找找啥原因,谢谢!rn程序: rnmain()rn rn//其他程序rnrn if('S'==buffer[0]) rn rn pthread_t thread; rn if(pthread_create(&thread,NULL,send_data,&client_socket)!=0)//当接收到S字符时,启动多线程发送图片rn printf("Build thread failed!\n");break; rn rnrn/////////////////////////////////////////////////////////////////////////////////////rnvoid *send_data(void *socket)rnrn int ret=0;rn int client_socket;rn char sendbuffer[BUFFER_SIZE];rn char compare[]="finshed";rn char file_name[40];rn char file_size[30];//store the file size,and send to the clientrn FILE *file_fd=NULL;rn long int file_len;rn int send_num=0;rn int i,j,num;rnrn client_socket=*((int *)socket);rnrnfor(j=1;j
libevent使用 Segmentation fault??
[size=14px]最近在ubuntu上编译libevent,写了一个简单的服务端测试例子,客户端连接后总是产生以下错误:rnProgram received signal SIGSEGV, Segmentation <em>fault</em>.rn0x00000000 in ?? ()rn单步调试到bufferevent_enable就出现以上错误。[/size]rnrn[code=c]void accept_handle(evutil_socket_t sfd,short event, void *arg)rn rn printf("accept handle\n"); rn struct event_base *base = (struct event_base*)arg; rn struct sockaddr_in sin; rn socklen_t slen = sizeof(sin); rn evutil_socket_t fd = accept(sfd,(struct sockaddr*)&sin,&slen); rn if(fd < 0) rn rn printf("accept error"); rn return; rn rnrn struct bufferevent* bev = bufferevent_socket_new(base,sfd,BEV_OPT_CLOSE_ON_FREE);rn bufferevent_setcb(bev,read_cb,NULL,error_cb,arg);rn bufferevent_enable(bev, EV_READ|EV_WRITE|EV_PERSIST); //到此处出现问题rn rn // bufferevent_write(bev, MESSAGE, strlen(MESSAGE));rn[/code]rn20分请教啊[img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/001/face/1.gif][/img]
请教 Segmentation fault 的解决方案
写了一个程序, 在我自己的机器上跑的很好。 GCC3.4.6+4.1 的库 redhat en 4.7 as。rnrn但放到服务器上不管是编译 还是 直接复制 在本地编译好的 都通过和运行不了。 rnrn运行 直接显示Segmentation <em>fault</em>。 环境都一样 REDHAT en 4.7 AS GCC3.46+4.1库。rnrn尝试过的方法: 重装系统 安装 GCC3.4.6+4.1库 rnrn换另外N台服务器 (环境相同)运行 重装系统以后编译的 程序 ,也不行。rnrn在网上搜索了一下 。说是因为 FTP 上传引起的编码问题。 于是 用 USB 直接拷贝本地编译好的程序 到服务器上运行也不出现上诉错误。rnrn求教高人解答给个思路。rnrn在此先谢过了。rn
调试出错:segmentation fault
我的开发环境是VMwarern在windows下开了个share共享文件,用mount来联到share,现在调试程序的时候总是多多少少会出现<em>segmentation</em> <em>fault</em>的错误,请问如何解决?
为什么 Segmentation fault
一个简单的函数,代码如下:rn[code=c]rnvoid avg (int a[])rnrn int i = 0;rn int sum = 0;rn while (i < size, ++i) // 此处表达式 ++i,编译运行时报:Segmentation <em>fault</em> rn sum += a[i];rnrn[/code]rnrn如果将将上面函数改为:rn[code=c]rnvoid avg (int a[])rnrn int i = 0;rn int sum = 0;rn while (i < size)rn rn sum += a[i];rn ++i; // 把 ++i放到循环体内就OKrn rnrn[/code]rn上面这个函数编译运行就不会错。rnrn在网上查了下有关Segmentation <em>fault</em>的原因,是因为<em>访问</em>的内存超出了系统所给这个程序的内存空间。但不知道,为什么在上面的函数中将表达式++i放在不同位置,就造成了内存<em>访问</em>出错。求解答,谢谢!
segmentation fault的问题
从网上下了个输入法的源码imframe,编译运行后界面显示出来了,但是点击键盘按钮的时候系统console输出 <em>segmentation</em> <em>fault</em>。rnrn于是我自己写了个输入法的demo,调用QWSInputMethod的sendcommitstring方法提交字符到编辑框上时也报了<em>segmentation</em> <em>fault</em>的问题。rnrn各位有遇到过这样的提示么?这是什么原因导致的?rn困扰好几天了,没有进展,网上有说是系统字体的问题,但是我确认不是字体的问题。rn
为什么会报Segmentation fault????????
#include rnrnint main() rn char buf[4096];rn char *str = "#include \r\n";rnrn snprintf(buf,sizeof(buf),str);rn printf("%d %d %d\n",buf[18],buf[19],buf[20]);rn printf("%s\n",buf[18]);//这里为什么会报Segmentation <em>fault</em>rn rn return 0;rnrnrn
为什么会出Segmentation fault???
代码如下:rn[code=C/C++]#include rn#include rnrnusing namespace std;rnclass Brnrn string name;rnpublic:rn void setname(string n) name = n; rn string getname()return name; rn rn;rnrnclass Arnrnprotected:rn B* b;rnpublic:rn void setname(string n)rn b->setname(n);rn rn rn string getname()rn return b->getname(); rn rn;rnrnrnrnclass C : public Arnrn rn;rnrnint main()rnrn C* c;rn c->setname("name");rn cout << c->getname();rnrn[/code]
linux+SDL segmentation fault
有谁用过linux+SDL图形编程的?最近发现在一台机器上面写好的一个SDL程序,移植到另外一台机器上面就会出现<em>segmentation</em> <em>fault</em> (SDL Parachute Deployed),如果要查原因,只能是把源代码拷过去加日志来查。有没有其他的办法?就像linux下面其他的程序当出现<em>segmentation</em> <em>fault</em>的时候都会产生一个core文件,不知道SDL为什么没有?有知道的请教一下,谢谢!
关于Segmentation fault的错误
为什么下面的代码执行时第1,3,4行会报Segmentation <em>fault</em>的错误,而第2行不报错rn1、//if (!strcmp(row[1], "")) printf("(strcmp)field question's value is string ''");rn2 if (strlen(row[1]) == 0) printf("(strlen)field question's value is string ''");rn3 //if (!strcmp(row[2], "")) printf("field answer's value is string ''");rn4 //if (!strcmp(row[3], "null")) printf("field joinaddr's value is string null");
新手:关于Segmentation fault
#include "stdlib.h"rn#include "stdio.h"rnFILE *fp; rnmain (int argc,char * argv[])//在工程选项中/设置/调式/程序变量:输入你要的文件名:如file.txtrnrnrn// int create(int argc,char * argv[]);rn int write(int argc,char * argv[]);rn rn rn write(argc,argv);rn rnint write(int argc,char * argv[])rn rn// int fd2;rn char ch;rn char string [256];rn if ((fp=fopen(argv[1],"a+"))==NULL)rn// if ((fd2=open(argv,4)))rn .....rn 会报错说Segmentation <em>fault</em>!rn不知道怎么解决,大家帮帮忙啊 ,,,都凌晨三点了啊,当学生不容易啊!!!
segmentation fault in linux
内容提要 本文简单介绍了Segmentation <em>fault</em>发生的原因,结合实际例子描述了内核向用户态程序发送SIGSEGV信号的流程。文中以实例回答了常见的一些SIGSEGV问题,例如“为什么函数返回了栈还可以<em>访问</em>?”、“为什么free()后的内存仍然可以使用”、“为什么我遇到的是SIGSEGV而不是SIGILL信号”等。最后笔者结合自己的经验,列举了一些预防SIGSEGV的编程习惯,供大家参考。SIGSEGV严格依赖操作系统、编译器、硬件平台,本文基于Linux、GCC、32bit IA32架构,但对其他平台操作系统也有借鉴意义。
求助“Segmentation fault
info: Linking Tree Network Frame using map /home/jiaowenx/HLMDATA/MAPS/flowdir.asc /usr/local/bin/SME: line 1086: 17767 Segmentation <em>fault</em> rn$SME_PROJ/$ProjectName/Driver/$RUN_TARGET $TCL_SCRIPT $USE_SHELL $JAVA_RUN_ARGS $NO_CONF -ppath $SME3_PROJ -p $ProjectName -m $ModelName $CONFIG_INPUT -pause $PAUSE -scen $ScenarioName $SME_CONTROL_ARGSrnrn运行程序的时候出现了上面的错误,请高手指点。
fault"的调试问题">关于"Segmentation fault"的调试问题
main函数如下:rnint main(int argc, char* argv[])rnrn ....rn ....rnrn return 0;rnrn用GDB跟踪时, 发现每次执行到return 0处,就开始执行全局对象的析构rn函数,执行完西析构之后,就提示"Segmentation <em>fault</em>"。实在郁闷,不知道rn什么地方出了问题。整个系统只有一个全局对象,而且在提示错误前已经成功析构。rnrn不知道有什么好的方法调试?rnrn开发环境:linux 2.6.21rn
lex&yacc Segmentation fault
最近要写一个shell程序,用lex和yacc解析命令,写了一个简单的规则,但是运行的时候就出现Segmentation <em>fault</em>(core dumped)错误。麻烦大家帮我看看吧rntoken.lrn[code=c]rnrn%rn#include rn#include "parser.tab.h"rnrnvoid yyerror(char *);rnint yywrap();rn%rn%%rn[a-zA-Z0-9\-] yylval = *yytext; return STRING;rn[ /t] ; rnrn. yyerror("Invalid character");rnrn%%rnrnint yywrap()rnrn return 1;rnrnrn[/code]rnrnparser.yrn[code=c]rn%rn#include rn#include rn#include "functions.h"rnrn#define YYSTYPE char*rnYYSTYPE yylva;rnrnint yylex();rnvoid yyerror(char *);rnrn%rn%token STRINGrn%%rnline :rn |commandrn rn print_test();rn rn ;rncommand :fgcommandrn |fgcommand '&'rn rn make_command(0,NULL);rn rn ;rnfgcommand :simple_cmdrn rn push_command();rn rn ;rnsimple_cmd :prog_invocation input_redirect output_redirectrn ;rnprog_invocation:STRING argsrn rn make_command(1,$1);rn rn ;rninput_redirect:rn |'' STRINGrn rn make_command(3,$2);rn rn ;rnargs:rn |args STRINGrn rn make_command(1,$2);rn rn ;rn%%rnvoid yyerror(char *s)rnrn printf("%s\n",s);rnrnrnint main()rnrn yyparse();rn return 0;rnrnrn[/code]rnrn其中make_command()函数为:rn[code=c]rnvoid make_command(int type,char *str)rnrn if(type == 0) // a back ground commandrn rn is_back = 1;rn rn else if(type == 1) // command argsrn rn strcpy(cmd_buff[arg_index ++],str);rn rn else if(type == 2) // input file namern rn strcpy(input_file,str);rn rn else if(type == 3) // output file namern rn strcpy(output_file,str);rn rnrnrn[/code]rn这个函数的功能就是想要将解析得到的结果存储下来。麻烦大家帮忙看看啊rn
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