设计一个保存你个人信息的类，包含姓名和年龄。

[Sensation777]

main函数不能变，通过main函数来设计！以下是我的代码，不知哪里错了，怎样才能运行通过呀~求大神们看看谢谢！


#include<iostream>
#include<string>

using namespace std;

class PersonInfo
{
private:
string name;

int year;

public:
void PersonInfo(string name,int year)
{
this->name=name;

this->year=year;
}

void Name();

void Age();
};



void PersonInfo::Name()
{
cout<<name<<endl;
}

void PersonInfo::Age()
{
cout<<year<<endl;
}

int main()

{

string name;

int year;

cin >> name >> year;

PersonInfo info(name, year);

cout << "I am " << info.Name() << ", " << info.Age() << " years old.\n";

return 0;

}

[幻夢之葉]

string PersonInfo::Name() { return name; } int PersonInfo::Age() { return year; } 这里是要求查询，也就是返回对应的信息

[ck2333]

两个成员函数要么直接调用，要么就用返回值像你主函数里写的这样输出。 另外，构造函数是没有返回值的。

#include<iostream>
#include<string>

using namespace std;

class PersonInfo
{
	private:
		string    name;

    	int       year;

	public:
		PersonInfo(string name,int year)
		{
			this->name=name;

			this->year=year; 
		}

		string Name();

		int Age();
};



string PersonInfo::Name()
{
	return name;
}

int PersonInfo::Age()
{
	return year;
}

int main()

{

    string    name;

    int    year;

    cin >> name >> year;

    PersonInfo info(name, year);

    cout << "I am " << info.Name() << ", " << info.Age() << " years old.\n";

    return 0;

}

#include<iostream>
#include<string>

using namespace std;

class PersonInfo
{
	private:
		string    name;

    	int       year;

	public:
		PersonInfo(string name,int year)
	{
		this->name=name;

		this->year=year; 
	}

	void Name();

	void Age();
};



void PersonInfo::Name()
{
	cout<<name;
}

void PersonInfo::Age()
{
	cout<<year;
}

int main()

{

    string    name;

    int    year;

    cin >> name >> year;

    PersonInfo info(name, year);

    cout << "I am ";
	info.Name() ;
	cout << ", " ;
	info.Age() ;
	cout << " years old.\n";

    return 0;
}

[sichuanwww]