C++类模板的数据成员为结构体模板，该结构体模板中有一成员为结构体模板，有大神能帮我解惑吗

[Rufengi]

#include<iostream>
#include<string>
using namespace std;
template<typename A,typename B>
struct score
{
A math;
B English;
};

template <typename T>
struct student
{
string name;
T Score;
};

template <typename T>
class teacher
{
public:
student<T> info;
teacher()
{

}
void printf()
{
cout << info << endl;
}
friend ostream &operator<<(ostream &out, student <T> &my)
{
out << "\t" << my.name << "\t" << my.Score.English << "\t" << my.Score.math << endl;
return out;
}
};
int main()
{
student<score<int, int>> mystu = { "呵呵", { 100, 100 } };
teacher<student<score<int, int>>>mytea;
myteacher.printf();
system("pause");
return 0;
}

[supergerm]

#include<iostream>
#include<string>
using namespace std;
template<typename A, typename B>
struct score
{
	A math;
	B English;

	friend ostream &operator<<(ostream &out, score &value)
	{
		out << value.math << "\t" << value.English << endl;
		return out;
	}
};

template <typename T>
struct  student
{
	string name;
	T Score;

	friend ostream &operator<<(ostream &out, student <T> &my)
	{
		out << "\t" << my.name << "\t" << my.Score << endl;
		return out;
	}
};

template <typename T>
class teacher
{
public:
	T info;
	teacher()
	{

	}

	teacher(T s)
	{
		info.name = s.name;
		info.Score.math = s.Score.math;
		info.Score.English = s.Score.English;
	}

	void printf()
	{
		cout << info << endl;
	}
};
int main()
{
	student<score<int, int>> mystu = { "呵呵", { 100, 100 } };

	teacher<student<score<int, int>>>mytea(mystu);
	mytea.printf();
	system("pause");
	return 0;
}

[Rufengi]

还是错误的啊，名字乱码

[supergerm]

你的编译器问题吧？

[Rufengi]

不好意思，刚刚又试了下，没错，我的问题，不过，你那个输出流重载不太理解，如果放在类中的话，那该怎么写呢

[Rufengi]

我明白了，谢谢！

[幻夢之葉]

哪儿不懂？ 模板的嵌套 student<score<int, int>> score用int，int进行实例化，score<int, int>为一个具体类型 然后再把这个类型当做student的模板参数 替换进去即： struct score { int math; int English; }; struct student { string name; score Score; }; class teacher { public: student info; }

[Rufengi]

这个我能理解，就是不知道代码错在哪里，实现不了，改来改去还是错误的