如何将一个字符串数组随机分配为两组数组

[qq_31919421]

String[] i = { "商纣", "杨戬", "夏桀", "褒姒", "白起", "嬴政", "韩信", "赵云", "妲己", "张良", "关羽", "张飞" }; 随机匹配为两组数组 每一组的字符串都是在i这个数组了随机抽取，而且不重复，有好的方法实现吗 ps：别吐槽上面的名字

[qq_31919421]

12个字符串随机分配为两组，每组6个字符串。

[李德胜1995]

遍历String数组，装在List集合，使用Collections.shuffle(list)方法打乱数组，平均分为两组即可。。。

[Freefish1994]

LS正解

	public static void main(String[] args) {
		List<String> strList = Arrays.asList(new String[] { "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12" });
		Collections.shuffle(strList);
		String[] strs1 = new String[strList.size() / 2], strs2 = new String[strList.size() / 2];
		for (int i = 0; i < strs1.length; i++) {
			strs1[i] = strList.get(i);
			strs2[i] = strList.get(i + strs1.length);
		}
	}

[qq_31919421]

楼上正解，谢谢一楼的点拨。

[wp7007]

String[] name={"a","b","c","d","e","f"}; int mid=name.length/2; String[] a=new String[mid]; String[] b=new String[mid]; String tmp=null; int j=0; for(int i=name.length;i>mid;i--){ int p=(int) (Math.random()*i); a[j++]=name[p]; tmp=name[i-1]; name[i-1]=name[p]; name[p]=tmp; } int k=0; for(int i=mid;i>0;i--){ int p=(int) (Math.random()*i); b[k++]=name[p]; tmp=name[i-1]; name[i-1]=name[p]; name[p]=tmp; } for(String xString:a){ System.out.println(xString); } for(String xString:b){ System.out.println(xString); }

[窝 窝]

[qq_39744460]

生产的随机数不会重吗