neon vld4 对应的汇编

[Holden.liu]

__extension__ static __inline uint8x8x4_t __attribute__ ((__always_inline__))
vld4_u8 (const uint8_t * __a)
{
  uint8x8x4_t ret;
  __builtin_aarch64_simd_xi __o;
  __o = __builtin_aarch64_ld4v8qi ((const __builtin_aarch64_simd_qi *) __a);
 838:	910283a1 	add	x1, x29, #0xa0
 83c:	f9402fa0 	ldr	x0, [x29,#88]
 840:	0c400000 	ld4	{v0.8b-v3.8b}, [x0]
 844:	4c002020 	st1	{v0.16b-v3.16b}, [x1]
  ret.val[0] = (uint8x8_t) __builtin_aarch64_get_dregxiv8qi (__o, 0);
 848:	910283a0 	add	x0, x29, #0xa0  //x0=x29+0xa0
 84c:	4c402000 	ld1	{v0.16b-v3.16b}, [x0]
 850:	910043a0 	add	x0, x29, #0x10
 854:	4c002000 	st1	{v0.16b-v3.16b}, [x0]
 858:	910043a0 	add	x0, x29, #0x10
 85c:	3dc00000 	ldr	q0, [x0]
 860:	910183a0 	add	x0, x29, #0x60
 864:	fd000000 	str	d0, [x0]
  ret.val[1] = (uint8x8_t) __builtin_aarch64_get_dregxiv8qi (__o, 1);
 868:	910283a0 	add	x0, x29, #0xa0
 86c:	4c402000 	ld1	{v0.16b-v3.16b}, [x0]
 870:	910043a0 	add	x0, x29, #0x10
 874:	4c002000 	st1	{v0.16b-v3.16b}, [x0]
 878:	910083a0 	add	x0, x29, #0x20
 87c:	3dc00000 	ldr	q0, [x0]
 880:	910183a0 	add	x0, x29, #0x60
 884:	91002000 	add	x0, x0, #0x8
 888:	fd000000 	str	d0, [x0]
  ret.val[2] = (uint8x8_t) __builtin_aarch64_get_dregxiv8qi (__o, 2);
 88c:	910283a0 	add	x0, x29, #0xa0
 890:	4c402000 	ld1	{v0.16b-v3.16b}, [x0]
 894:	910043a0 	add	x0, x29, #0x10
 898:	4c002000 	st1	{v0.16b-v3.16b}, [x0]
 89c:	9100c3a0 	add	x0, x29, #0x30
 8a0:	3dc00000 	ldr	q0, [x0]
 8a4:	910183a0 	add	x0, x29, #0x60
 8a8:	91004000 	add	x0, x0, #0x10
 8ac:	fd000000 	str	d0, [x0]
  ret.val[3] = (uint8x8_t) __builtin_aarch64_get_dregxiv8qi (__o, 3);
 8b0:	910283a0 	add	x0, x29, #0xa0
 8b4:	4c402000 	ld1	{v0.16b-v3.16b}, [x0]
 8b8:	910043a0 	add	x0, x29, #0x10
 8bc:	4c002000 	st1	{v0.16b-v3.16b}, [x0]
 8c0:	910103a0 	add	x0, x29, #0x40
 8c4:	3dc00000 	ldr	q0, [x0]
 8c8:	910183a0 	add	x0, x29, #0x60
 8cc:	91006000 	add	x0, x0, #0x18
 8d0:	fd000000 	str	d0, [x0]

vld4 对应的汇编中的ld1 st1是什么意思？

[赵4老师]

百度、必应、谷歌搜相关关键字。

[日立奔腾浪潮微软松下联想]

ld = load st = store