python数据操作

HTML33 2017-08-18 11:23:32
00050fbc7058dcf35dcb86f52b4b09bf,20151109004815,21048,22643,533
00050fbc7058dcf35dcb86f52b4b09bf,20151109014818,21048,22643,533 time_difference:3603.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109024821,21048,22643,533 time_difference:3603.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109034823,21048,22643,533 time_difference:3602.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109044827,21048,22643,533 time_difference:3604.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109054830,21048,22643,533 time_difference:3603.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109064833,21048,22643,533 time_difference:3603.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109074836,21048,22643,533 time_difference:3603.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109084856,21048,22643,533 time_difference:3620.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109094859,21048,22643,533 time_difference:3603.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109134910,21048,22643,533 time_difference:14411.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109144914,21048,22643,533 time_difference:3604.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109154916,21048,22643,533 time_difference:3602.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109160913,21048,22643,533 time_difference:1197.0
00050fbc7058dcf35dcb86f52b4b09bf,20151109161011,21048,22643,533 time_difference:58.0
015f26230e222cc432dc47ddd331c4df,20151112050040,21010,8618,527
015f26230e222cc432dc47ddd331c4df,20151112053042,21010,8618,527 time_difference:1802.0
015f26230e222cc432dc47ddd331c4df,20151112053903,21010,8618,527 time_difference:501.0
015f26230e222cc432dc47ddd331c4df,20151112060907,21010,8619,527 time_difference:1804.0
015f26230e222cc432dc47ddd331c4df,20151112063909,21010,8618,527 time_difference:1802.0
015f26230e222cc432dc47ddd331c4df,20151112070911,21010,12909,527 time_difference:1802.0
015f26230e222cc432dc47ddd331c4df,20151112073914,21010,12909,527 time_difference:1803.0
015f26230e222cc432dc47ddd331c4df,20151112090542,21010,8619,527 time_difference:5188.0
015f26230e222cc432dc47ddd331c4df,20151112093545,21010,12909,527 time_difference:1803.0
015f26230e222cc432dc47ddd331c4df,20151112110553,21010,12909,527 time_difference:5408

如果最后一个时差大于3600s,就合并前后两个数据,(比如第一条记录和第二条记录大于3600s,合并第一第二,再从第三条开始判断) 如果中间隔着几个小于3600s的 ,就一直到大于3600s的记录处,合并第一条和这一条记录,去掉中间的数据
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tianfang 2017-08-22
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基本功 至少先写出自己的思路来再问

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