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高分求java regular expression.
有以下需求,文本如下
new line
__new001_tag00_tag
#SW
this is news 001
abbbbbbbbbbbb
new line
__new001_tag00_tag
#SW
this is news 002
abbbbbbbbbbbb
new line
new line
__new001_tag00_tag
#SW
this is news 003
abbbbbbbbbbbb
我写成这样子实现抓取3条记录:\\r\\n(\\w*?_\\w*?_\\w*?_\\w*?)\\r\\n(.*?#SW.*?)\\r\\n(.*?)\\r\\n\\ Pattern.DOTALL
现在只能匹配粗体3行，不能匹配4行,怎么样才能把第4行也匹配?
new line
__new001_tag00_tag
#SW
this is news 001
abbbbbbbbbbbb
new line
__new001_tag00_tag
#SW
this is news 002
abbbbbbbbbbbb
new line
new line
__new001_tag00_tag
#SW
this is news 003
abbbbbbbbbbbb
我写成这样子实现抓取3条记录:\\r\\n(\\w*?_\\w*?_\\w*?_\\w*?)\\r\\n(.*?#SW.*?)\\r\\n(.*?)\\r\\n\\ Pattern.DOTALL
现在只能匹配粗体3行，不能匹配4行,怎么样才能把第4行也匹配?
...全文
rickylin86 2017年08月28日
result:
---------- java ----------
__new001_tag00_tag
#SW
this is news 001
abbbbbbbbbbbb
Output completed (0 sec consumed) - Normal Termination
rickylin86 2017年08月28日
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class Test{
public static void main(String[] args){
String content = "new line\n"+
"__new001_tag00_tag\n"+
"#SW\n"+
"this is news 001\n"+
"abbbbbbbbbbbb\n"+
"new line\n"+
"__new001_tag00_tag\n"+
"#SW\n"+
"this is news 002\n"+
"abbbbbbbbbbbb\n"+
"new line\n"+
"new line\n"+
"__new001_tag00_tag\n"+
"#SW\n"+
"this is news 003\n"+
"abbbbbbbbbbbb\n";
String regex = "(?s)(?:new line\n)(.*?)(?=new line\n)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(content);
if(matcher.find()){
System.out.println(matcher.group(1));
}
}
}