求大神帮助检查错误，小白解决不了了，，，

2017-09-07 06:17:53 556 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

测试理论知识二：代码检查与走查、错误列表、桌面检查含义：代码检查与走查都要求人们组成一个小组来阅读或直观检查特定的程序，一组开发人员对代码进行审核，其中和只有一个人是代码的作者。以上这些方法通常会有效地查找出30%~70%的错误，这些方法不能有效的查找出高层次的设计错误，例如在软件需求分析阶段的错误。检查过程中，必须树立正确的态度，如果程序员将代码检查视为对其人格的攻击、采取防范的态度，那么检查就不会有效果。对于所有的数组引用，是否每一个下标的值都是整数？在使用的计算机上，当内存分配的单元小于内存可寻址的单元大小时，是否存在直接或间接的寻址错误？阅读详情

我按照书上的程序敲了一个图轮廓线的设计的程序，但是书上给的是一段升程的，我设计的是三段，如下图滚子位移曲线所示。

我对书上程序有一些改动，为了能够运行也改了很多地方。我使用的是VS2017，一些所需库什么的百度也都安了，但是程序运行后却不能得到正常图像，我对C语言的了解几乎为零，求各位帮助，谢谢啦下面是效果图，类似

  /*REM Design of disk cam profile */

#include<stdio.h>

#include<stdlib.h>

#include<math.h>

#include<graphics.h>

#include <conio.h>

#define PI 3.1415926

void sds();

void sdjdj();

void scos();

void ssin();

void zbz(int);

void hds();

void hdjdj();

void hcos();

void hsin();

void dral();

void htl();

float s[360], v[360], a[360], x[360], z[360], x1[360], z1[360];

float r0, e, rr, h, d, d0, ds, d02, ds2, d03, ds3, d01, ds1, pi, p, s0, d1, d2, sn, hn, i, d3, d4, d5;

float maxs, maxv, maxa, yy, ip, d0p, sd, cd, dss, dx, dy, q, ss;

void ingraph();

void ingraph()

{

	int gd = 0, gm, ErrorCode;

	initgraph(&gd, &gm, "");

	ErrorCode = 0;

	if (ErrorCode != 0)

	{

		printf("Crahpics System Error:%s\n", "ErrorCode");

		exit(1);

	}

	setbkcolor(0);

}

int SNG(float va)

{

	if (va > 0)return 1;

	if (va == 0)return 0;

	if (va < 0)return -1;

}

main()

{

	maxs = 0;maxv = 0;maxa = 0;

	p = PI / 180;

	printf("Design of disk cam profile\n");

	printf("---------------------\n");

	printf("input r0=");scanf("%f", &r0);

	printf("input rr=");scanf("%f", &rr);

	printf("input e= ");scanf("%f", &e);

	printf("input h= ");scanf("%f", &h);

	printf("rise motion law sn=");scanf("%f", &sn);

	printf("input d0=");scanf("%f", &d0);

	printf("input ds=");scanf("%f", &ds);

	printf("input d01=");scanf("%f", &d01);

	printf("input ds1=");scanf("%f", &ds1);

	printf("input d02=");scanf("%f", &d02);

	printf("input ds2=");scanf("%f", &ds2);

	printf("return motion law hn=");scanf("%f", &hn);

	printf("input d03=");scanf("%f", &d03);

	printf("input ds3=");scanf("%f", &ds3);

	s0 = sqrt(r0*r0 - e*e);

	for (i = 0;i <= d0;i++)

	{

		int sn = 0;

		switch (sn)

		{

		case 1:

			sds();break;

		case 2:

			sdjdj();break;

		case 3:

			scos();break;

		default:

			ssin();break;

		}

		zbz(i);

	}

	d1 = d0 + ds;

	for (i = d0 + 1;i <= d1;i++)

	{

		int i=0;

		s[i] = h;v[i] = 0;a[i] = 0;

		zbz(i);

	}

	d2 = d1 + d01 + ds1;

	for (i = d1 + 1;i <= d2;i++)

	{

		int i=0;

		s[i] = h+2;v[i]= 0;a[i] = 0;

		zbz(i);

	}

	d3 = d2 + d02 + ds2;

	for (i = d2 + 1;i <= d3;i++)

	{

		int i=0;

		s[i] = h+4;v[i] = 0;a[i] = 0;

		zbz(i);

	}

	d4 = d3 + d03;

	for (i = d3 + 1;i <= d4;i++)

	{

		int hn=0;

		switch (hn)

		{

		case 1:

			hds();break;

		case 2:

			hdjdj();break;

		case 3:

			hcos();break;

		case 4:

			hsin();break;

		}

		zbz(i);

	}

	d5 = d4 + ds3;

	for (i = d4 + 1;i <= d5;i++)

	{

		int i=0;

		s[i] = 0;v[i] = 0;a[i] = 0;

		zbz(i);

	}

	printf("Coodinate of disk cam profile and motion law\n");

	printf("-------------------------------------\n");

	printf(" i\t  x\t  z\t\t x1\t  z1\t   s\t   v\t   a\n");

	for(i=0;i<=360;i=i+30)

	{

		int i=0;

		printf("%7.2f  %7.2f  %7.2f  %7.2f  %7.2f   %7.2f  %7.2f   %7.2f\n", 

			i, x[i], z[i], x1[i], z1[i], s[i], v[i], a[i]);

		if (fabs(s[i]) > maxs)  maxs = fabs(s[i]);

		if (fabs(v[i]) > maxv)  maxv = fabs(v[i]);

		if (fabs(a[i]) > maxa)  maxa = fabs(a[i]);

	}

	_getch();

	ingraph();

	dral();

	_getch();

	closegraph();

	ingraph();

	htl();

	_getch();

	closegraph();

}

void dral()

{

	int i;

	printf("  s");

	printf("\t\tmaxs(mm) =%f\n", maxs);

	printf("   v");

	printf("\t\tmaxv(m) =%f\n,maxv/1000");

	printf("   a");

	printf("\t\tmaxa(m) =%f\n,maxa/1000");

	printf("\n\n\n\n\n\n\n\n\n\n\n\t\t\t\t\tdlt\n\n");

	printf("  0  90  180 ");

	printf("  270  360\n");

	line(0, 240, 380, 240);

	line(380, 240, 373, 235);

	line(380, 240, 373, 245);

	line(10, 480, 10, 0);

	line(10, 0, 5, 7);line(10, 0, 15, 7);

	putpixel(10, 240 - s[1], 3);

	moveto(10, 240 - s[1]);

	setcolor(YELLOW);

	line(35, 10, 15, 10);

	for (i = 0;i <= 360;i++)

		lineto(i + 10, 240 - s[i] * maxs*0.4);

	putpixel(10, 240 - v[1], 4);

	moveto(10, 240 - v[1]);

	setcolor(RED);

	line(35, 25, 45, 25);

	for (i = 0;i <= 360;i++)

		lineto(i + 10, 240 - v[i] * maxv*0.4);

	putpixel(10, 240 - a[1], 14);

	moveto(10, 240 - a[1]);

	setcolor(BLUE);

	line(35, 40, 45, 40);

	for (i = 0;i <= 360;i++)

		lineto(i + 10, 240 - a[i] * maxa*0.2);

}

void hcos()

{

	int i=0;

	s[i] = 0.5*(h+4)*(1 + cos(PI*(i - d3) / d03));

	v[i] = -0.5*(h+4)*PI*sin(PI*(i - d3) / d03) / (d03*p);

	a[i] = -0.5*(h+4)*PI*PI*cos(PI*(i - d3) / d03) / ((d03*p)*(d03*p));

}

void hdjdj()

{

	int i = 0;

	if (i <= (d3 + d03 / 2))

	{

		s[i] = (h + 4)*(1 - 2 * ((i - d3) / d03)*((i - d3) / d03));

		v[i] = -4 * (h + 4)*(i - d3)*p / ((d03*p)*(d03*p));

		a[i] = -4 * (h + 4) / ((d03*p)*(d03*p));

	}

	else

	{

		s[i] = 2 * (h + 4)*(d03 + d3 - i)*(d03 + d3 - i) / (d03*d03);

		v[i] = -4 * (h + 4)*(d03 + d3 - i)*p / ((d03*p)*(d03*p));

		a[i] = 4 * (h + 4) / ((d03*p)*(d03*p));

	}

}

	void hds() 

	{

		int i=0;

		s[i] = (h + 4)*(1 - (i - d3) / d03);

		v[i] = -(h + 4) / (d03*p);

		a[i] = 0;

	}

	void hsin()

	{

		int i=0;

		s[i] = (h + 4)*(1 - (i - d3) / d03 + sin(2 * PI*(i - d3) / d03) / (2 * PI));

		v[i] = -(h + 4)*(1 - cos(2 * PI*(i - d3) / d03)) / (d03*p);

		a[i] = -2 * PI*(h + 4)*sin(2 * PI*(i - d3) / d03) / ((d03*p)*(d03*p));

	}

	void htl()

	{

		line(0, 240, 640, 240);

		line(640, 240, 633, 245);

		line(640, 240, 633, 235);

		line(320, 20, 320, 460);

		line(320, 20, 325, 27);

		line(320, 20, 315, 27);

		circle(320, 240, r0);

		circle(320, 240, 5);

		line(305, 255, 316, 244);

		line(335, 255, 324, 244);

		line(303, 255, 337, 255);

		line(305, 255, 298, 263);

		line(315, 255, 308, 263);

		line(325, 255, 318, 263);

		line(335, 255, 328, 263);

		circle(320, 240, e);

		putpixel(320 + e, 240, 3);

		int yy = 0;

		moveto(320 + e, 240);

		while (yy<240)

		{

			line(320 + e, -yy + 240, 320 + e, -yy + 225);

			moveto(320 + e, -yy + 225);

			yy = yy + 20;

			if (yy>r0) lineto(320 + e, -yy + 240);

		}

		line(e + 315, 40, e + 315, 90);

		line(e + 325, 40, e + 325, 90);

		line(e + 315, 50, e + 307, 60);

		line(e + 315, 60, e + 307, 70);

		line(e + 315, 70, e + 307, 80);

		line(e + 315, 80, e + 307, 90);

		line(e + 333, 40, e + 325, 50);

		line(e + 333, 50, e + 325, 60);

		line(e + 333, 60, e + 325, 70);

		line(e + 333, 70, e + 325, 80);

		putpixel(320 + x[1], 240 - z[1], 3);

		moveto(x[1] + 320, -z[1] + 240);

		for (i = 0;i<360;i++)

		{

			int i=0;

			lineto(x[i] + 320, -z[i] + 240);

			circle(x[i] + 320, -z[i] + 240, rr);

			moveto(x[i] + 320, 240 - z[i]);

		}int i;

		putpixel(x1[1] + 320, -z1[1] + 240, 3);

		moveto(x1[1] + 320, -z1[1] + 240);

		for (i = 0;i <= 360; i++)

		lineto(x1[i] + 320, -z1[i] + 240);

	}

	void scos()

	{

		int i=0;

		s[i] = 0.5*h*(1 - cos(PI*i / d0));

		v[i] = 0.5*h*PI*sin(PI*i / d0) / (d0*p);

		a[i] = 0.5*h*PI*PI*cos(PI*i / d0) / ((d0*p)*(d0*p));

	}

	void sdjdj()

	{

		int ip, d0p;

		ip = i*p;d0p = d0*p;

		if (i <= d0 / 2)

		{

			int i=0;

			s[i] = 2 * h*(i / d0)*(i / d0);

			v[i] = 4 * h*ip / (d0p*d0p);

			a[i] = 4 * h / (d0p*d0p);

		}

		else

		{

			int i=0;

			s[i] = h - 2 * h*((d0 - i) / d0)*((d0 - i) / d0);

			v[i] = 4 * h*(d0 - i)*p / (d0p*d0p);

			a[i] = -4 * h / (d0p*d0p);

		}

	}

	void sds()

	{

		int i=0;

		s[i] = h*i / d0;

		v[i] = h / (d0*p);

		a[i] = 0;

	}

	void ssin()

	{

		int i=0;

		s[i] = h*(i / d0 - sin(2 * PI*i / d0) / (2 * PI));

		v[i] = h*(1 - cos(2 * PI*i / d0)) / (d0*p);

		a[i] = 2 * PI*h*sin(2 * PI*i / d0) / ((d0*p)*(d0*p));

	}

	void zbz(int j)

	{   

		ss = s0 + s[j];d = j*p;

		sd = sin(d);cd = cos(d);

		x[j] = ss*sd + e*cd;

		z[j] = ss*cd - e*sd;

		dss = v[j] - e;

		dx = dss*sd + ss*cd;

		dy = dss*cd - ss*sd;

		if (fabs(dy)>1E-10)

		{

			q = atan(dx / (-dy));

			q = q - (SNG(-dy) - 1)*PI / 2;

		}

		else

		{

			q = PI / 2;

			q = q - (SNG(-dy) - 1)*PI / 2;

		}

		x1[j] = x[j] - rr*cos(q);

		z1[j] = z[j] - rr*sin(q);

	}

...全文

CDC检查常见的错误及原因这种场景是会存在问题的，因为再经过同步之后路径的delay可能存在不同，那么就可能会导致信号出现异常组合，导致不期望的信号组合导致逻辑失败，所以需要在设计中明确是否会存在对应问题，是否需要将同步信号简化，逻辑前移或者后移。Clock1的数据在clock2中经过同步的信号，和经过同步之后打拍的信号最终进行组合逻辑，这在实际使用中需要确认用法，因为这种做法，可能是导致同步之后的信号组合和原始的值的组合不同，导致电路问题；同一个源头的不同路径可以会有不同的delay，可能产生不同的时间延迟，因此引起毛刺；阅读详情

ERbbit

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schlafenhamster 2017-09-09

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////////////////////////////////////////////////////////
/*REM kinematics analysis for crank-slider mechanism*/
#define PI 3.1415926f

float Q1[360], Q2[360], w2[360], e2[360], s[360], v[360], a[360];
float maxs=0, maxv=0, maxa=0;

void drawl(float maxx, float maxy, float maxz)
{
	int i;
#if 0
	printf("  s");
	printf("\t\tsmax(m)=%f\n", maxx / 1000);
	printf("  v");
	printf("\t\tvmax(m)=%f\n", maxy / 1000);
	printf("  a");
	printf("\t\tamax(m)=%f\n", maxz / 1000);
	printf("\n\n\n\n\n\n\n\n\n\n\n\t\t\t\t\t\tQ1\n");
	printf("%9.4f ", f10 / p);
	printf("%9.4f ", 90 + f10 / p);
	printf("%9.4f ", 180 + f10 / p);
	printf("%9.4f ", f10 / p - 90);
	printf("%9.4f ", f10 / p);
#endif
	maxx = (float)(480 * 0.4 / maxx);
	maxy = (float)(480 * 0.4 / maxy);
	maxz = (float)(480 * 0.4 / maxz);
	line(0, 240, 420, 240);
	line(420, 240, 413, 245);line(420, 240, 413, 235);
	line(10, 0, 10, 480);
	line(10, 0, 5, 7);line(10, 0, 15, 7);
// red
	putpixel(10, 240 -s[1] * maxx , 4);// useless ?
	setcolor(4);
	line(35, 10, 45, 10);
	text(50,0,"s");
	moveto(10, 240 - s[1] * maxx);
	for (i = 2;i < 360;i++) // a[360] 0->359 !
		lineto(i + 10, 240 - s[i] * maxx);
// green
	putpixel(10, 240 - v[1] * maxy, 2);
	setcolor(2);
	line(35, 25, 45, 25);
	text(50,16,"v");
	moveto(10, 240 - v[1] * maxy);
	for (i = 2;i < 360;i++)
		lineto(i + 10, 240 - v[i] * maxy);
// blue 
	putpixel(10, 240 - a[1] * maxz, 1);
	setcolor(1);// yellow-> blue
	line(35, 40, 45, 40);
	text(50,30,"a");
	moveto(10, 240 - a[1] * maxz);
	for (i = 2;i < 360;i++)
		lineto(i + 10, 240 - a[i] * maxz);
}
//
int main()
{
	int i;
//	printf("input l1=28.5");scanf("%f", &l1);
	float l1=28.5;
//	printf("input l2=64");scanf("%f", &l2);
	float l2=64;
//	printf("input e=20");scanf("%f", &e);
	float e=20;
//	printf("input n=44");scanf("%f", &n);
	float n=44;
//	printf("\t    kinetics analysis for crank - slider mechanism\n");
//	printf("\t    - - - - - - - - - - - - - - - - - - -\n");
//	printf("   Q1\t\tQ2\t w2\t e2\t s\t v\t a\n");
	float p = PI / 180.0f;
	float w1 = PI*n / 30.0f;
	float f = (float)atan(e / sqrt((l2 - l1)*(l2 - l1) - e*e));
	float f10 = PI - f;
	float xc0 = (float)sqrt((l2 - l1)*(l2 - l1) - e*e);
	for (i = 0;i < 360;i++)
	{
		float f1 = f10 + i*p;
		if (f1 > 2 * PI) f1 -= 2 * PI;
		Q1[i] = f1;
		float sf2 =(float) (-(e + l1*sin(Q1[i])) / l2);
		float f2 = (float)atan(sf2 / sqrt(1 - sf2*sf2));
		if (f2 > 0) Q2[i] = f2;
		else		Q2[i] = (float)(2 * PI - fabs(f2));
		w2[i] = (float)(-(l1*w1*cos(Q1[i] - Q2[i])) / l2);
		e2[i] = (float)(l1*w2[i] * w2[i] * sin(Q1[i] - Q2[i])) / l2;
		s[i] = (float)(l1*cos(Q1[i]) + l2*cos(Q2[i]) - xc0);
		v[i] = (float)(-l1*w1*sin(Q1[i]) - l2*w2[i] * sin(Q2[i]));
		a[i] = (float)(-l1*w1*w1*cos(Q1[i]) - l2*w2[i] * w2[i] * cos(Q2[i]) - l2*e2[i] * sin(Q2[i]));
		if((i % 10) == 0)
			printf("%9.3f  %9.3f  %9.3f  %9.3f  %9.3f  %9.3f  %9.3f\n",
			        Q1[i]/p, Q2[i]/p, w2[i], e2[i], s[i], v[i]/1000, a[i]/1000);
		if (fabs(s[i]) > maxs) maxs = (float)fabs(s[i]);
		if (fabs(v[i]) > maxv) maxv = (float)fabs(v[i]);
		if (fabs(a[i]) > maxa) maxa = (float)fabs(a[i]);
	}
	printf("Press return to continue!");
	getchar();
	cls();
// draw curves
	initgraph();
	drawl(maxs, maxv, maxa);
	getchar();
	return 0;
}

schlafenhamster 2017-09-09

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// Crank.cpp : Defines the entry point for the console application.
//
//#define _WIN32_WINNT 0x0500 // for ::SetDCPenColor(g_hdc, Colors[color]);

//#include "stdafx.h"

#include <Windows.h>
#include <Wincon.h>
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <iostream>   
using namespace std;

typedef HWND (WINAPI *PROCGETCONSOLEWINDOW)();
PROCGETCONSOLEWINDOW GetConsoleWindow;

HWND g_hWnd=0;
HDC  g_hdc=0;

void line(int x0,int y0,int x1,int y1)
{
	MoveToEx(g_hdc,x0,y0,NULL);
	LineTo(g_hdc,x1,y1);
}

void moveto(float x0,float y0)
{
	MoveToEx(g_hdc,(int)x0,(int)y0,NULL);
}

void lineto(float x1,float y1)
{
	LineTo(g_hdc,(int)x1,(int)y1);
}

void text(int x0,int y0,char txt[])
{
	TextOut(g_hdc,(int)x0,(int)y0,txt,strlen(txt));
}

/* 0=黑色 1=蓝色 2=绿色 3=湖蓝色 4=红色 5=紫色 6=黄色 7=白色 8=灰色 9=淡蓝色 A=淡绿色 
   B=淡浅绿色 C=淡红色 D=淡紫色 E=淡黄色 F=亮白色
*/	
COLORREF Colors[]={
RGB(0,0,0),      //	BLACK	,    //0
RGB(0,0,255),    //	BLUE	,    //1
RGB(0,255,0),    //	GREEN	,    //2
RGB(0,255,255),  //	CYAN	,    //3
RGB(255,0,0),    //	RED	    ,    //4
RGB(255,0,255),  //	MAGENTA	,    //5
RGB(0,128,128),  //	BROWN	,    //6
RGB(192,192,192),//	LIGHTGRAY	,//7
RGB(128,128,128),//	DARKGRAY	,//8
RGB(0,0,128),    //	LIGHTBLUE	,//9
RGB(0,128,0),    //	LIGHTGREEN	,//10
RGB(0,128,128),  //	LIGHTCYAN	,//11
RGB(128,0,0),    //	LIGHTRED	,//12
RGB(255,128,155),//	LIGHTMAGENTA,//13
RGB(255,255,0),  //	YELLOW	    ,//14
RGB(255,255,255),//	WHITE	    ,//15
};

void setcolor(int color)
{
	HPEN hPen,hOldPen;
	hPen = CreatePen(PS_SOLID,2,Colors[color]);
	hOldPen=(HPEN)SelectObject(g_hdc,HGDIOBJ(hPen));
	DeleteObject(hOldPen);
}

void putpixel(float x0,float y0, int color)
{
	SetPixel(g_hdc,(int)x0,(int)y0,Colors[color]);
}

void circle(int xc,int yc,int rd)
{
	Ellipse(g_hdc,xc-rd,yc-rd,xc+rd,yc+rd);
}

void initgraph()
{// no vscroll bar
    HANDLE hConsoleOutput = ::GetStdHandle(STD_OUTPUT_HANDLE);  
    COORD dwSize = {80, 26};  
    ::SetConsoleScreenBufferSize(hConsoleOutput, dwSize);  
    SMALL_RECT rc1 = {0, 0, 79, 25};  
    ::SetConsoleWindowInfo(hConsoleOutput, TRUE, &rc1);  
// hide caret
	CONSOLE_CURSOR_INFO cursor_info = {1, FALSE};
	SetConsoleCursorInfo(hConsoleOutput, &cursor_info);
//	
    SetConsoleTitle("Drawing");  
	HMODULE hKernel32 = GetModuleHandle("kernel32");
	GetConsoleWindow = (PROCGETCONSOLEWINDOW)GetProcAddress(hKernel32,"GetConsoleWindow");
// get handles
	g_hWnd=GetConsoleWindow();
	g_hdc=GetDC(g_hWnd);
	system("color F0");
} 
//
void cls()
{
// here's where we'll home the cursor 
COORD coordScreen = { 0, 0 };
BOOL  bSuccess;
DWORD cCharsWritten;
CONSOLE_SCREEN_BUFFER_INFO csbi;// to get buffer info
DWORD dwConSize;// number of character cells in the current buffer
HANDLE hConsoleOutput;
// get the handle
	hConsoleOutput=GetStdHandle(STD_OUTPUT_HANDLE); 
// get the number of character cells in the current buffer
	 bSuccess=GetConsoleScreenBufferInfo(hConsoleOutput,&csbi );
	 dwConSize=csbi.dwSize.X * csbi.dwSize.Y;
// fill the entire screen with blanks 
	bSuccess=FillConsoleOutputCharacter(hConsoleOutput,
		                     (TCHAR)' ',dwConSize,
							 coordScreen,&cCharsWritten);
// get the current text attribute 
	bSuccess=GetConsoleScreenBufferInfo(hConsoleOutput,&csbi);
// now set the buffer's attributes accordingly
	bSuccess=FillConsoleOutputAttribute(hConsoleOutput,
		                        csbi.wAttributes,dwConSize,
								coordScreen,&cCharsWritten);
// put the cursor at (0, 0)
	bSuccess=SetConsoleCursorPosition(hConsoleOutput,
									  coordScreen);
	return;
}

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赵4老师 2017-09-08

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http://www.easyx.cn 代码功能归根结底不是别人帮自己看或讲解或注释出来的；而是被自己静下心来花足够长的时间和精力亲自动手单步或设断点或对执行到某步获得的中间结果显示或写到日志文件中一步一步分析出来的。提醒：再牛×的老师也无法代替学生自己领悟和上厕所！单步调试和设断点调试（VS IDE中编译连接通过以后，按F10或F11键单步执行，按Shift+F11退出当前函数；在某行按F9设断点后按F5执行停在该断点处。）是程序员必须掌握的技能之一。

schlafenhamster 2017-09-08

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你用的是什么开发平台 TC ？ VC ？

schlafenhamster 2017-09-08

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请给一个默认值 // printf("input r0=");scanf("%f", &r0); r0=25; // printf("input rr=");scanf("%f", &rr); rr=30; // printf("input e= ");scanf("%f", &e); e=20; // printf("input h= ");scanf("%f", &h); h=40; // printf("rise motion law sn=");scanf("%f", &sn); sn=1; // printf("input d0=");scanf("%f", &d0); d0=1; // printf("input ds=");scanf("%f", &ds); ds=1; // printf("input d01=");scanf("%f", &d01); d01=0.5; // printf("input ds1=");scanf("%f", &ds1); ds1=10; // printf("input d02=");scanf("%f", &d02); d02=0.6f; // printf("input ds2=");scanf("%f", &ds2); ds2=2; // printf("return motion law hn=");scanf("%f", &hn); hn=2; // printf("input d03=");scanf("%f", &d03); d03=2; // printf("input ds3=");scanf("%f", &ds3); ds3=4;